HKDSE CHEMISTRY – A Modern View (Chemistry) Experiment Workbook 5 Suggested answers Chapter 52 Importance of industrial processes Chapter 53 Rate equation Experiment 53.1 Determining the rate equation of a reaction using method of initial rate (A microscale experiment) 1 Chapter 54 Activation energy Experiment 54.1 Determining the activation energy of a chemical reaction 3 Chapter 55 Catalysis and industrial processes Experiment 55.1 Investigating the action of a catalyst 6 Experiment
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different temperatures determined by the use of an electric water bath. With these results‚ the effect of temperature on the rate of reaction will be investigated. 2. Determine the activation enthalpy with and without the catalyst ammonium molybdate(VI) and with different protic acids and use this to compare the effectiveness. To find out which catalyst is most effective‚ this aim will be carried out as an iodine clock reaction. The goal of this aim is to find out what catalyst is best to
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Discuss Alberti’s argument that‚ ‘Grace of form could never be separated or divorced from suitability for use.’ Bk VI‚ 2. Abbot Suger believed that he existed ‘neither in the slime of the Earth nor the purity in heaven.’ Suger’s writings expose the contemporary medieval mind-set of Earth as foul‚ sinful and ‘slimy.’ Yet moving forward to the Renaissance era of the 14th Century‚ prolific archaeologist‚ humanist and aficionado of the ancient and modern arts- Leon Battista Alberti- characterises the
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Transition Metals 1a) The d-orbitals of a free transition metal atom or ion are degenerate (all have the same energy.) However‚ when transition metals form coordination complexes‚ the d-orbitals of the metal interact with the electron cloud of the ligands in such a manner that the d-orbitals become non-degenerate (not all having the same energy.) The way in which the orbitals are split into different energy levels is dependent on the geometry of the complex. Crystal field theory can be used to predict
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Using the Iodine clock method to find the order of a reaction Introduction When peroxodisulfate (VI) ions and iodide ions react together in solution they form sulfate (VI) ions and iodide. This reaction is shown below: S2O82-aq+ 2I-aq SO42-aq+ I2(aq) The reactants and the sulfate (VI) ions are colourless however the Iodine is a yellow/brown colour. This allows you to measure the progress of the reaction through the colour change when the iodine is produced. In order to determine the order of
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factors affecting the kinetics of reaction between peroxodisulfate (vi) and iodide d. del prado1 and j. belano2 1 department of food science and nutrition‚ college of home economics 2 department of food science and nutrition‚ college of home economics university of the philppines‚ diliman‚ quezon city 1101‚ philippines date submitted: january 7‚ 2013 ------------------------------------------------- ------------------------------------------------- ABSTRACT -------------------------------------------------
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Procedure © KCl http://hk.geocities.com/fatherofchemistry Discussion Part A: Making Mn(VI) from Mn(VII) and Mn(IV) 1.> Explain why only one of the three mixtures reacted to give green Mn(VI). [ANS] By Le Chatelier’s Principle‚ only the alkaline medium will shift the equilibrium to right and yield green MnO42-. 2.> What happened when acid was added to Mn(VI)? Explain. [ANS] The solution changes from green to purple again. The acid removes OH- on the left side
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ALCOHOLS Alcohols are compounds in which one or more hydrogen atoms in an alkane have been replaced by an -OH group. For the purposes of UK A level‚ we will only look at compounds containing one -OH group. For example: Primary alcohols In a primary (1°) alcohol‚ the carbon which carries the -OH group is only attached to one alkyl group Some examples of primary alcohols include: Secondary alcohols In a secondary (2°) alcohol‚ the carbon with the -OH group attached is joined directly to
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halogens and halide Ions Test for halogen Test method Test observations Test chemistry and comments Chlorine gas Cl2 A pungent green gas. (i) Apply damp blue litmus. (Can use red litmus and just see bleaching effect.) (ii) A drop silver nitrate on the end of a glass rod into the gas. (i) litmus turns red and then is bleached white. (ii) White precipitate. (i) Non-metal‚ is acid in aqueous solution and a powerful oxidising agent (ii) It forms a small amount of chloride ion in water‚ so gives
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examples illustrate how this can be done. Appearing blue There are a number of so called ’iodine clock’ reactions in which molecular iodine is one of the products. Probably the most famous of these is the reaction involving hydrogen peroxide and iodide
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