study the method of purification of an organic compound by simple extraction 3. To study the test of identification of alkyl halide Chemicals and Apparatus: ~18.0 g 1-butanol‚ ~20.0 g sodium bromide‚ 15 ml of concentrated sulfuric acid‚ anhydrous magnesium sulfate‚ ~10 ml of 5% aqueous sodium bicarbonate‚ ~1 ml of sodium iodide – acetone reagent‚ 1 ml of bromine in chloroform‚ 1 piece of 100 cm3 round-bottomed flask‚ 1 piece of 50 cm3 of beaker‚ 1 piece of 50 cm3 of conical flask‚ 1 piece of 250 cm3
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TABLE OF CONTENTS 1. IA (Alkaline Metals) 1.1. H………………………………………………………………………..2 1.2. Li………………………………………………………………………..2 1.3. Na………………………………………………………………………2 1.4. K………………………………………………………………………..3 1.5. Rb………………………………………………………………………3 1.6. Cs………………………………………………………………………3 1.7. Fr……………………………………………………………………….4 1. IIA (Alkaline Earth Metals) 2.8. Be………………………………………………………………………4 2.9. Mg………………………………………………………………………4 2.10. Ca………………………………………………………………………4
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physical properties of matter. Introduction Sugar and salt look so similar that most people cannot tell them apart without tasting them. Chemically‚ white refined table sugar‚ sucrose‚ and salt are very different. An ionic bond between a positive sodium ion and a negative chloride ion creates a molecule of sodiumchloride (NaCl). Covalent bonds between hydrogen‚ oxygen‚ and carbon atoms form to form a sucrose molecule (C12H22O11). Ionic bonds form when oppositely Figure 1: The pile of white grains
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distilled water to dissolve the sodium carbonate until 250 ml of solution were made. I had to calculate‚ from the information provided‚ how much sodium carbonate to use in the making of the solution. Using the volume and concentration of the solution‚ I was able to calculate the moles of the solution (concentration x volume). Using the periodic table I was able to calculate the molar mass of sodium carbonate which was 106‚ from this I could calculate the mass of the sodium carbonate I needed to make the
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of ethanoic acid in table vinegar by titrating a sample with alkali sodium hydroxide (NaOH) with a known concentration of 0.1molL-1. The equation of the reaction between ethanoic acid and sodium hydroxide is as follows: CH3COOH + NaOH CH3COONa + H2O When the titrations end point is determined and volumes of reactants are measured the concentration of the ethanoic acid can be calculated. Keywords: Titration‚ Sodium Hydroxide‚ Ethanoic Acid‚ Equivalence Point‚ pH Meter‚
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one of the sodium carbonate/bicarbonate mixtures produced a precipitate‚ the exception was when NaHCO3 was combined with Co(NO3)2 or cobalt nitrate. Furthermore‚ most copper and iron nitrates‚ even with differing sodium compounds produced a precipitate. Exceptions were Cu(NO3)2 with sodium sulfate and sodium chloride. It was also noticed that nickel‚ barium‚ and iron nitrates (excluding those with few with no reaction) across the board had the same color precipitates no matter the sodium compound
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Extracting NaCl from Rock Salt and assessing its purity Aim The aim of this experiment was to obtain a pure product from a solution through the processes o extraction‚ filtering and evaporation. Introduction Extraction is used when trying to separate or purify a product. For an extraction to be successful the substance used to make the solvent should readily dissolve. The substance used in this practical was rock salt. The liquid used should not react with the substance that needs extracting
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Chapter 6 Study Guide Fluids‚ Electrolytes‚ and Acid-Base balance Compartmental Distribution of Body Fluids 2/3 of the body’s water is contained in the ICF‚ the remaining 1/3 is in the ECF ICF fluid volume is regulated by proteins and other non-diffusible organic compounds in cells Interstitial fluids (IF) act as a transport vehicle for gasses‚ nutrients‚ wastes‚ and other materials 14%-16% of body weight Reservoir for maintenance of vascular volume; used during hemorrhage
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result‚ it clearly shows that the concentration of sulfuric acid is 0.05 mol/dm3 using the concentration equation‚ c= n/v. 25 cm3 of the volume with sodium hydroxide is equal to 0.025 dm3 by dividing a thousand with cm 3 and multiply it with 0.1 mol/ dm3 which is the concentration of sodium hydroxide. With the ratio between sulfuric acid and sodium hydroxide is 1 to 2 so‚ 0.0025 should be divided by 2 and 0.00125 moles of sulfuric acid is come out. Finally‚ using c = m/v‚ 0.00125 mole/0.025 dm3
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Sodium Laureth Sulfate: Common use -A detergent cleansing agent‚ cleanses and emulsifies properties - Sodium laureth sulfate is often used in laundry and hand dishwashing detergents. In addition‚ it can be found in cleansers‚ carpet cleaners‚ toilet cleaning products‚ stain & odor removers‚ all-purpose cleaners‚ etc. Importance of chemical in the item -An effective foaming agent -An anionic detergent and surfactant - Sodium laureth sulfate works well as a degreaser. Physical and Chemical
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