The Physical Properties of Eleven Chemical Compounds Problem: Discover whether various chemical compounds are molecular or ionic and if they are acidic or basic. Hypothesis: If the compound is ionic‚ then it will be soluble because the energy given off water molecules compensates for the energy needed to break ionic bonds‚ also‚ if the compound is Ionic‚ it will be an electrolyte‚ because they mostly break up into ions when in water. If the compound is molecular‚ then it will be soluble‚ it cannot
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Writing ionic equations for redox reactions You can split the ionic equation into two parts‚ and look at it from the point of view of the magnesium and of the copper(II) ions separately. This shows clearly that the magnesium has lost two electrons‚ and the copper(II) ions have gained them. These two equations are described as "electron-half-equations" or "half-equations" or "ionic-half-equations" or "half-reactions" - lots of variations all meaning exactly the same thing! Any redox reaction
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2. I noticed that all of the ionic compounds are soluble in water. This is due to the fact that water molecules are polar. Meaning that they have dipole bonds‚ which have a slightly positive and slightly negative end due to electronegativity differences between atoms. When ionic bonds are placed in water‚ they dissociate into their ions (positive and negative) due to the process of dissociation. These ions are then attracted to different dipoles present in the water molecule‚ in other words the negative
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Chemical Reactions Lab Synthesis Reactions: Synthesis reactions occur when two elements or compounds combine to create one single compound. The general equation of synthesis reactions is: A+B→AB. The following are the complete balanced equations for the five synthesis reactions performed in the lab. Reaction 1: Reaction 2: Reaction 3: Reaction 4: Reaction 5: The reaction of CO2 and water is a prime example of a synthesis reaction. This is a synthesis reaction because it follows the general
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Writing Half Reaction and Net Ionic Equation Going back to our first concept or topic‚ we’ve learn how to identify the Oxidizing and Reducing agent and the Oxidation as well as the Reduction. In this part of the Redox reaction or in this step‚ it is very important that you already know the Oxidizing and Reducing agent for us to find the half reaction. In this step or part‚ we will also learn how to balance using the addition of electrons in both sides if necessary. After this step we can now write
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Investigating the solubility of Group II hydroxides Jiyeon Kim Aim: To investigate the solubility of Group II hydroxides (Mg(OH)2‚ Ca(OH)2‚ Sr(OH)2‚ Ba(OH)2) Research Question: What is the trend of solubility of Group II hydroxides going down the group as determined through measuring the volume of hydroxides needed to titrate with a known concentration of hydrochloric acid? Background Information: Solubility is when a solute forms a homogeneous solution by dissolving in solvent. The solubility of any
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Like Proteus vulgaris Microbiology Lab Report for Unknown Robert Bhowanidin MCB 2010L / Section 1290 October 24th‚ 2013 The following report will describe both my journey to find my unknown as well as the results that led to my discovery. Before I start‚ I will say that I am 100% positive that my unknown (which was #31) is none other than Proteus vulgaris. My data and the ensuing results from them simply cannot be disputed. From my first batch of results‚ Proteus vulgaris reared its head
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Define and describe ionic and covalent bonds. An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions. A covalent bond is the chemical bond that involves the sharing of pairs of electrons between atoms. A compound is made when two or more atoms form a chemical bond‚ linking them together. The two types of bonds are ionic bonds and covalent bonds. In an ionic bond‚ the atoms are bound together by the attraction between oppositely charged
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percentage. The wet sand mixture was placed in a separate beaker‚ weighed previously‚ and heated to evaporate the water. When dry and cool the beaker was weighed. The weight of the beaker was subtracted from the weight of the beaker and sand. The result was then divided by the original weight of the mixture to determine the
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Measuring the Solubility Product of Ca(OH)2 Purpose: The purpose of this investigation is to find the solubility product (Ksp) of Ca(OH)2 by titrating the hydrochloric acid with calcium hydroxide and using their entities to find the concentration of Ca2+ and OH- ions. Materials: Refer to lab sheet “Measuring the Solubility of Ca(OH)2” (handout) Method (Procedure): Refer to lab sheet “Measuring the Solubility of Ca(OH)2” (handout) Observations Trial 1 Trial 2 Initial burette reading 0mL 17.75mL
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