Redox Titration Analysis of a Commercial Bleach Purpose To perform a redox titration. To determine the amount of hypochlorite ion present in commercial bleach. Introduction Many commercial products‚ such as bleaches and hair coloring agents‚ contain oxidizing agents. The most common oxidizing agent in bleaches is sodium hypochlorite‚ NaClO (sometimes written NaOCl). Commercial bleaches are made by bubbling chlorine gas into a sodium hydroxide solution. Some of the chlorine is oxidized
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Title: Redox Reaction Introduction: Some of the most important chemical reactions are Redox reactions. They are also known as oxidation-reduction reactions. This reaction passes one or more electrons from one species to another. The species that loses electrons are being oxidized while the species that gains electrons are reduced. The reaction occurs simultaneously. Numbers are given to each element in a chemical reaction to help us find out which element is oxidized and which is
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>ir Ck Jdgn; (At the time of the house warming service‚ a cross. Two candles lighted‚ and a bowl with water to be blessed and sprinkled‚ shall be placed on a table facing to the East of convenient place of the house. All others including the Celebrant‚ who is conducting the service‚ must stand behind it. Now it is time to start the house warming ceremony) >ir Ck Jdgn cau; Qgk SaCSaH Qgk dkgjCk; g!k d\jv& saqkdkfjgj uk; Qgk elYf\jH ilq[\j Ck Jdgjv&[ fxj)lrk= si=ik; djq)k emj lyluj >ir\jsRy ] ik;
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|NaOCl + KI|4 |small white precipitate‚ color changed to black after starch was added | | with 1 drop of starch| || G.|KI + Pb(NO3)2|5 |turned bright yellow‚ milky texture| H.|NaOH + phenolphthalein|6 |turned dark pink‚ magenta| I.|HCl + phenolphthalein|7 |clear| J.|NaOH + AgNO3|8 |turned brownish green‚ cloudy| K.|AgNO3 + NH3|9 |turned light brown| |after exposure to bright light| || L.|NH3 and CuSO4|10 |light blue‚ cloudy| Part F: Testing of Various Foods with the NaOCl + KI solution
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down starch in solutions that are increasing in neutral pH. To do this the experiment was carried out so that tubes containing a reaction solution of the Amylase enzyme and starch were simultaneously mixed. The reactions were then introduced to I2-KI‚ which stopped the reactions‚ at two minute intervals. Each of these trials was repeated three times to ensure proper accuracy. After concluding the reactions they were placed into a spectrophotometer (A580) for analysis. Graphing the values of the
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Break Up Of Marks For Formative Assessment 3 & 4 For Class IX ENGLISH |1. |Monday Test |10 Marks | |2. |Literature based Role Play[ Bishop’s Candlestick] |3 Marks | |3. |MCB based Debate[content‚ Language‚ Pronunciation] |3 Marks | |
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the solution. The tip of the buret was checked to make sure there weren’t any bubbles in it. Then a 250mL beaker was obtained. A 25mL pipette was used to add exactly 25mL of the KIO₃ solution. Then 50mL of deionized water and about .25g of solid KI was added. The solution was stirred until the solid was completely dissolved. 2mL of glacial acetic acid was then added.
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bhi unnati hum‚ Waise to hai internet pe har prakaar ka gyaan‚ Par ache bure ki nahi hai use pehchaan . Nahin hain shabd kaise karoon dhanyavaad‚ Bas chahiye har pal aap sabka aashirvaad‚ Hoon jahan aaj mai usme hain bada yogdaan‚ Aap sabka jinhone diya mujhe itna gyaan. Aapne banaya hai mujhe is yogya‚ Ki praapt karoon mai apna lakshya‚ Diya hai har samay aapne sahaara ‚ Jab bhi laga mujhe ki mai haara. Par main hoon kitna matlabi‚ Yaad kiya na maine aapko kabhi‚ Aaj
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Szegény Gélyi János lovai című novella elemzése „Megérti a négy okos állat a parádét…” A környezet‚ a természet legapróbb részletei is zseniálisan alátámasztják‚ olykor megindokolják‚ vagy kiegészítik a cselekmény folyamát Mikszáth novelláiban. A büszke‚ boldog lovak kicicomázott parádéja Gélyi János érzésének metaforája. Ez a metafora – Gélyi érzéseinek és a lovaknak párhuzama – végigvonul az egész művön. Bokros és Tündér a két ló neve‚ jelzős szerkezetként értelmezve Vér Klárát‚ a
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method. Aim: To produce 1.50 g of lead iodide‚ PbI2‚ assuming 100 % conversion‚ using 1.00 g solid potassium iodide‚ KI‚ and 0.1 M lead nitrate‚ Pb(NO3)2 solution of volume 30 cm3 and hence calculate percentage yield. Calculations: 2KI(s) + Pb(NO3)2( aq) —> PbI2 (s) + 2KNO3 (aq) Mass of PbI2 to be produced = 1.5 g Moles of PbI2 = = 0.003 Moles of KI = 0.003*2 = 0.006 Mass of KI = 0.006*166 = 1.00 g Moles Pb(NO3)2 = 0.003 Volume Pb(NO3)2 = = 0.03 dm3 = 30 cm3 Background Information: Reaction:
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