the dimensions of the room. (iv) A river 2m deep and 45m wide is flowing at the rate of 3 km per hour. Find the volume of water that runs into the sea per minute. (v) A closed cylinder has diameter 8cm and height 10cm. Find its total surface area and volume. (vi) The volume of a metallic cylinder pipe is 748cm3 . Its length is 14 cm and external diameter 18cm. Find its thickness. (vii) A cylindrical bucket‚ 28cm in diameter 72cm high is full of water. The water is emptied into
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Guidelines for Mathematics Laboratory in Schools Class X Central Board of Secondary Education Preet Vihar‚ Delhi – 110092. 1 2 1 . Introduction Taking into consideration the national aspirations and expectations reflected in the recommendations of the National Curriculum Framework developed by NCERT‚ the Central Board of Secondary Education had initiated a number of steps to make teaching and learning of mathematics at school stage activity-based and experimentation oriented
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Drag on a cylinder ENME432L section 0101 Date of the Experiment: Feb. 21‚ 2012 Date submitted: Feb. 28‚ 2012 Instructor: Anilchandra Attaluri Prepared by: Ku Choe: ________ Dwight Hofstetter: _________ Aasam Tasaddaq: ________Kody Snow: ________ Benjamin DiDonato: _______ Lab report checklist: x Have you included the raw (handwritten) data sheet? x Have you included your pre-lab report which has been signed by your TA or instructor? x Have you typed the measured data and include
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MEMB221 MECHANICS AND MATERIALS LABORATORY SEM 2 2012/13 EXPERIMENT 6: THIN CYLINDER DATE PERFORMED: 13TH DECEMBER 2012 DUE DATE: 20TH DECEMBER 2012 SECTION: 2 GROUP NUMBER: 6 GROUP MEMBERS: a) MUHAMAD HADI BIN MOHAMED RADZI (ME087932) b) THINES A/L MURUGAN (ME086895) c) MUHAMMAD HASRUL BIN ROSLI (ME087000) d) HAIZUM AMALINA BINTI A. WAHID (ME087898) LAB INSTRUCTOR: MADAM NOLIA HARUDIN TABLE OF CONTENT No. | Content | Page | 1. | Summary / Abstract | 3 | 2
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of the screw rod it will rotate in the nut and in turn moves the movable jaw. Here the rotary motion is converted into reciprocating motion. In Hydraulic type’s one end of the piston rod is connected to the movable jaw and the piston slides in the cylinder. Here the hydraulic fluid actuates the movement of the piston; this in turn actuates the movable jaw. Here the principle movement is only a reciprocating movement. Pneumatic type is same as the hydraulic type. Here instead of hydraulic fluid‚ air
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FOUR STROKE PETROL ENGINE The four stroke petrol engine works in the following way:- Intake stroke In this stroke‚ fuel and air is allowed inside the cylinder by the downward movement of the piston which involves the opening of intake valve. Compression stroke Piston moves upward again in this stroke and the fuel and air mixture is compressed. Power stroke In this stroke power is generated when the spark plug ignites the fuel and piston moves down‚ this helps the engine to start initially
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may begin‚ he new engine will be load tested‚ ie run at 20% then in gradients brought up to to 100% this is usually over a period of 24 hour‚ so that the engines fuel rack can be adjusted if necessary‚ to prevent over or underfueling of individual cylinders. Progress 3: Main focus: Engine replacement/removal method Dry dock modification requirements Hull extrusion‚ opening NDT testing
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UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certificate of Education Advanced Subsidiary Level and Advanced Level MATHEMATICS Paper 1 Pure Mathematics 1 (P1) October/November 2005 1 hour 45 minutes Additional materials: Answer Booklet/Paper Graph paper List of Formulae (MF9) 9709/01 READ THESE INSTRUCTIONS FIRST If you have been given an Answer Booklet‚ follow the instructions on the front cover of the Booklet. Write your Centre number‚ candidate number and name on all the work
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1a Packaging of a potato chip 6cm Volume of a single = 170cm cubed Volume of cylinder = ∏r squared Height= volume Divided by ( ∏r squared) Height= 170cm divided by (∏ x 3 squared) Height = 6.01 round of to 6cm Allowing 1 extra cm for room Top and bottom of cylinder = 6cm + 1cm = 7cm Height= 6cm + 1cm = 7cm Total surface Area= area of base + area of top +
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beans and ground nuts. Apparatus: 100mL measuring cylinder‚ 50mL measuring cylinder‚ analytical balance and cooking oil. Procedure: Results: Table 2.1: Data of equivalent radius‚ solid density‚ bulk density and porosity of granular materials. nj Red beans Green beans Ground nuts Weight of 400 beans‚ M (kg) 38 22 144 Volume of 400 beans + void spaces‚ V (ml) 48 26 232 Initial reading of cylinder V1 (ml) 300 300 300 Final reading of cylinder V2 (ml) 285 290 210 Volume of void spaces‚ v=v1-v2
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