Topic 2 – Spot Exchange Markets Question 1 You need to buy CHF 1‚000‚000 to pay your Swiss watch supplier. Your bank quotes bid-ask rates of CHF/USD 1.3990 – 1.4000. What will be your dollar cost of the CHF 1‚000‚000? The bid-ask rates of USD/CHF are: 1 1 1.4000 1.3990 0.7143 0.7148 The dollar cost: 1 1.3990 USD 714‚ 796.28 CHF 1‚ 000‚ 000 Question 2 As a FX trader‚ you see the following quotes: USD/CAD 0.7047 MXN/CAD 6.4390 MXN/USD 8.7535 Is there an arbitrage opportunity‚ and if
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Solutions for Review Problems of Chapter 14 1. a. Given the following diagram for a product‚ determine the quantity of each component required to assemble one unit of the finished product. b. Draw a tree diagram for the stapler: a. F: 2 J: 2 x 2 = 4 D: 2 x 4 = 8 G: 1 L: 1 x 2 = 2 J: 1 x 2 = 2 H: 1 A: 1 x 4 = 4 D: 1 x 2 = 2 Totals: F = 2; G = 1; H = 1; J = 6; D = 10; L = 2; A = 4 b. Stapler Top Assembly Base Assembly Cover Spring Slide Assembly Base Strike Pad Rubber Pad 2 Slide
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CHAPTER 2 The Financial Statements BRIEF EXERCISES BE2–1 2008 2008 2008 Beginning Ending Retained 2008 2008 2008 Retained Earnings + Revenues – Expenses – Dividends = Earnings $28.2 + $43.3 – $38.2 – X = $30.6 X = $2.7 2008 Dividends as a percentage of 2008 net income: 2008 Dividends = $ 2.7 = 52.9% 2008 Net income ($43.3-$38.2) $ 5.1 BE2–2 1) Current Liabilities financed $32 billion of the
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The Manager and Management Accounting Copyright © 2015 Pearson Education‚ Inc. All Rights Reserved 1. 2. 3. Distinguish financial accounting from management accounting Understand how management accountants help firms make strategic decisions Describe the set of business functions in the value chain and identify the dimensions of performance that customers are expecting of companies Copyright © 2015 Pearson Education‚ Inc. All Rights Reserved. 1-2 4. 5. 6. 7. Explain the five-step decision-making
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ANSWERS TO QUESTIONS 1. Examples are: (a) Payment of an accounts payable. (b) Collection of an accounts receivable from a customer. (c) Transfer of an accounts payable to a note payable. 2. Transactions (a)‚ (b)‚ (d) are considered business transactions and are recorded in the accounting records because a change in assets‚ liabilities‚ or owners’/stockholders’ equity has been effected as a result of a transfer of values from one party to another. Transactions (c) and (e) are not business
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Chapter 15 Entities Overview SOLUTIONS MANUAL Discussion Questions 1. [LO 1] What are the more common legal entities used for operating a business? How are these entities treated similarly and differently for state law purposes? Answer: Corporations‚ limited liability companies (LLCs)‚ general and limited partnerships‚ and sole proprietorships. These entities differ in terms of the formalities that must be observed to create them‚ the legal rights and responsibilities conferred on
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Programming Logic and Design‚ 6e Solutions 6-1 Programming Logic and Design‚ 6th Edition Chapter 6 Exercises 1. a. Design the logic for a program that allows a user to enter 10 numbers‚ then displays them in the reverse order of their entry. Answer: A sample solution follows Flowchart: Pseudocode: start Declarations num index num SIZE = 10 num numbers[SIZE] = 0‚0‚0‚0‚0‚0‚0‚0‚0‚0 getReady() Programming Logic and Design‚ 6e Solutions 6-2 while index < SIZE getNumbers()
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Administrative Office Management Chapter 1 The office in today’s world of business The office - A place where activities take place to facilitate operations of the business enterprise - Data gathering‚ record keeping‚ info management‚ business communication - “beehive” of activity where substantial paperwork of many kinds are done Importance of office work - Facilitating/servicing unit for all major functions in the company - Brain and nerve centre because of its network of activities
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prohibited reproduction‚ storage in a retrieval 9–1 system‚ or transmission in any form or by any means‚ electronic‚ mechanical‚ photocopying‚ recording‚ or likewise. For information regarding permission(s)‚ write to: Rights and Permissions Department‚ Pearson Education‚ Inc.‚ Upper Saddle River‚ NJ 07458. 9–2 CHAPTER 9. Sinusoidal Steady State Analysis [c] VL = IZL = (10/30◦ )(200/90◦ ) × 10−3 = 2/120◦ V [d] vL = 2 cos(10‚000t + 120◦ ) V −1 −1 = = −50 Ω ωC 4000(5 × 10−6 ) [b] ZC = jXC = −j50
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16 Fourier Series Assessment Problems AP 16.1 av = 1 T ak = 2 T = 0 Vm dt + 2T /3 0 4Vm 3kω0 T = bk = 2T /3 2 T 2T /3 0 4Vm 3kω0 T 1 T Vm 3 T 2T /3 Vm cos kω0 t dt + sin 4kπ 3 = Vm sin kω0 t dt + 1 − cos 4kπ 3 7 dt = Vm = 7π V 9 Vm cos kω0 t dt 3 T 2T /3 6 4kπ sin k 3 Vm sin kω0 t dt 3 T 2T /3 = 6 k 1 − cos 4kπ 3 AP 16.2 [a] av = 7π = 21.99 V [b] a1 = −5.196 b1 = 9 a2 = 2.598 a3 = 0 a4 = −1.299 a5 = 1.039 b2 = 4.5 b3 = 0 b5 = 1.8 b4 = 2.25 2π = 50 rad/s T [d]
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