The third stage of the market segmentation process is the creation of a specific Market mix to fulfill the needs‚ as well as market conditions of each specific target ` ` Segment (Wilkie‚ 1990; Gunter & Furnham‚ 1992; Kotler‚ 1994). Although many authors Limit the market segmentation process to market identification rather on the key elements Of the entire process‚ most companies fail to give due importance to other stages in Market segmentation such as product positioning
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Gas Law Problems Boyles Law 1. A gas occupies 12.3 litres at a pressure of 40.0 mm Hg. What is the volume when the pressure is increased to 60.0 mm Hg? 2. If a gas at 25.0 °C occupies 3.60 litres at a pressure of 1.00 atm‚ what will be its volume at a pressure of 2.50 atm? 3. To what pressure must a gas be compressed in order to get into a 3.00 cubic foot tank the entire weight of a gas that occupies 400.0 cu. ft. at standard pressure? 4. A gas occupies 1.56 L at 1.00 atm. What will be the volume
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following 3 questions as per assignment; QUESTION 1 – What are the three primary differences between Cisco layer 2 network resiliency and HP IRF resiliency? The first obvious difference is the protocols that they use. Cisco uses Spanning Tree Protocol (STP) while HP IRF uses the Link Aggregation Control Protocol. The second difference lies in the architecture being used. Cisco uses a mesh of network switches‚ linked to other switches in the aggregation layer‚ which in turn is linked to the core. This
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S. 5.2 – The Mole The mole: - - - - Ex. - Molar mass (g/mol): - - - Ex. |Element |Atomic mass shown on Periodic |Molar mass of element | | |table | | |N |14.0067 |14.0067 g
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includes a series of stages. Few authors agree on the specifics of the process but it is common to see the marketing plan beginning with analysis‚ the development of strategy and the implementation of the marketing mix (Hooley et al 1996‚ Simkin 2000‚ Kotler 2001‚ Baker 2000‚ Dibb 2002). Marketing plans‚ according to McDonald (2003)‚ contain a series of steps that make up the marketing planning
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as coaxial‚ CAT5e‚ CAT6‚ UTP (Unshielded Twisted Pair)‚ and STP (Shielded Twisted Pair) to just name a few. Coaxial has been in use for the longest period of time and one of the first types used in networking. CAT5e is the most common used today in networking with the bandwidth it supports and is available in UTP or STP. CAT6 can support any application that “lower” cables can and also has a higher bandwidth and is available in UTP and STP as well. UTP is unshielded twisted pair‚ which means that the
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Case study prepared on Sewage Treatment Plant at Tapovan. Location of Plant:-Sewage Treatment Plant at Tapovan‚ Panchavati‚ Nasik – 422 003. Introduction :- Domestic Sewage Water is collected from different parts of city. It explains as follows – 1] Takli.SPS-20 MLD. 2] Old Ganeshwadi SPS-25 MLD. 3] New Ganeshwadi SPS-45 MLD. 4] Kapila SPS-7.5 MLD. In an average‚ about 75 MLD sewage water is collected. The quantity and quality of sewage water is varies with respect to day. Also the quality of sewage
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SIGNALING SYSTEM 7 The hardware and software functions of the SS7 protocol are divided into functional abstractions called “levels”. These levels map loosely to the Open Systems Interconnect (OSI) 7 layer model defined by the international standards organisation . • Messsage transfer part • Isdn user part • Telephone user part • Signaling connection control part • Transaction capabilities applications part SS7 Protocol Stack The hardware and software functions of the SS7 protocol are divided into
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needs only be high enough for the receiver to detect it. Making the voltage higher would make the receiver electronics more difficult. 4.1.3 Hospitals‚ security systems‚ PA & recording studios. The drawback of STP cables is that they will increase the total cost of an installation. STP cables are more expensive due to the shielding‚ which is an additional material that goes into every meter of the cable. The shielding also makes the cable heavier and stiffer. Thus‚ it is more difficult to handle
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Some metals react with acids while others do not. In this experiment‚ students will perform 2 reactions: aluminum/zinc with excess 6M hydrochloric acid and aluminum-zinc alloy with excess 6M hydrochloric acid. The purpose of this experiment is to determine the atomic mass of each metal and the percent composition of a known mass aluminum-zinc alloy by determining the moles of H2 gas formed. Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g) 1 mole of H2(g) is produced for every 1 mole of Zn(s) 2. 2Al(s)
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