6 and z = 2.6. First we look for the area of both by doing “2nd ‚Vars‚ NORMALCDF” and inputting “-1000‚ “Z‚” 0‚ 1 then find the difference between both. 2. A business wants to estimate the true mean annual income of its customers. It randomly samples 220 of its customers. The mean annual income was $61‚400 with a standard deviation of $2‚200. Find a 95% confidence interval for the true mean annual income of the business’ customers. First we find E by doing Zc(standard deviation/square root of
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for men and women are not equal. b. Samples and Populations: Given your research question and hypothesis above‚ what would your population of interest be? Describe your population. My population of interest is: men and women between the ages of 22 and 30 that have taken the MCAT one time. Describe the population – what does it contain? The population contains men and women ages 22 to 30. To test your research hypothesis‚ describe the sample you might collect‚ including sampling method
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Non Performing Assets (npa) in sbi Getting current updates and regulations for the non performing assets (npa) in sbi With a steep rise in the ratio of the nonperforming assets all over the country‚ it has been really tough for the RBI to control and manage in the given time frame. No doubt‚ public sector banks including SBI have been in the list of banks that have been implementing the procedures to control the default line of the borrowers. On the other hand‚ it should also be noted that nonperforming
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ones. Therefore they did a test with 40 samples of both new balls and old ones. The testing was performed with a mechanical hitting machine so that any difference between the mean distances for the two models could be measure to evaluate the difference in the two models‚ presented with the sample size of 40 and confidence level of 95%. The table below depicts a descriptive statistical summary for the case study. | Current Model | New Model | Sample Mean | 268.89 | 272.98 | Standard Error
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Sample 9.23 A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages are labeled as 8 ounces‚ the company wants the packages to contain a mean of 8.17 ounces so that virtually none of the packages contain less than 8 ounces. A sample of 50 packages is selected periodically‚ and the packaging process is stopped if there is evidence that the mean amount packaged is different from 8.17 ounces. Suppose that in a particular of 50 packages
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Review Questions for the Midterm Exam Part I. All the Homeworks and Quizzes (50% of the Midterm Exam) Part II. Additional Review Questions 1. Which of the following statements is correct? a) The range is a measure of central tendency. b) The median is a measure of dispersion. c) For a symmetric distribution‚ the mean is equal to the median. d) For a skewed distribution‚ the variance is a negative number. e) The variance is a measure of central tendency. 2. After
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sampling effort‚ Boos Allen was confident that the population average household income is $119‚155 and that the population sample household income standard deviation is $30‚000. Two Playbill executives recently hypothesized that the average annual household income of its readership has increased and so believe that the magazine price should also increase. From a 2012 sample‚ Boos Allen has profiled the new average annual household income to be $124‚450 with a population standard deviation unchanged
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nation. In view of the day to day radical changes in agricultural research‚ the scenario is becoming tough for agricultural scientists and associated scholars. Statistical science is concerned with the aspect of theory of design of experiments and sample investigation and drawing valid inferences from using various statistical methods. The statisticians design the experiments‚ trials and analyze the data and interpret the facts. Statistical design and technique helps to describe the involvement
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3‚000/5 = 600 Solution 2: The variance for x is 5‚000‚000 The variance for y is 5‚050‚000 Solution 3: The Standard deviation is found by squaring the result of the variance: SD of x = 2236‚ this tells us on average how far is from sample mean. SD of y = 2247 Solution 4: The coefficient of variation is as follows: The coefficient of variation for x is: 0.000447. The coefficient of variation for y is: 0.000445. Solution 5: On the argument that the SD of the first is greater
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NORTHCENTRAL UNIVERSITY ASSIGNMENT COVER SHEET Student: ODEDOYIN ABEL THIS FORM MUST BE COMPLETELY FILLED IN Follow these procedures: If requested by your instructor‚ please include an assignment cover sheet. This will become the first page of your assignment. In addition‚ your assignment header should include your last name‚ first initial‚ course code‚ dash‚ and assignment number. This should be left justified‚ with the page number right justified. For example: Student: ODEDOYIN A MGT
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