electrons? +2 3) What is the charge on an ion formed when an atom gains two electrons? -2 The Mole 1) Find the molar mass of zinc 65g/mol 2)Find the molar mass of sulfuric acid H2 SO4 98g/mol 3) How many moles of sodium chloride are present in 117g of Na2 CI 2 moles 4) I have 54g of water (H2O) and 84 g of iron (Fe) do I have more moles of water or of iron I have more miles of water (54 g = 3 moles H20 ‚ 84g = 1.5 moles Fe) Arrangement of Electrons 1)
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calculating the percent yield. Materials: 1 Distilled water 1 Paper towels 1 Small paper cup 1 Coffee cup or mug 1 Beaker‚ 100 mL‚ glass 1 Funnel 1 Cylinder‚ 25 mL 1 Goggles-Safety 1 Scale-Digital-500g 1 Weighing boat‚ Plastic 1 CaCl2·2 H2O-Calcium Chloride‚ Dihydrate - 2.5 g 1 Filter Paper 12.5-cm 1 NaCO3-Sodium Carbonate - 2 g Procedure 1. Put on your goggles. 2. Weigh out 1.0 g of CaCl2·2H2O and put it into the 100-mL beaker. Add 25 mL of distilled water and stir to form
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TERMS OF REFERENCE Mr L Neeson of the North Carolina Department of Transport requested this report. The report was needed to provide a progress update and likely outcomes on the investigation into an accident that took place on a bridge over Route 29 highway on 20th May 2000. Although privately owned‚ the bridge crosses a state highway and it is thus the responsibility of the North Carolina Department of Transport to ensure that a proper investigation into the accident is carried out. Mr. Neeson’s
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Observations Substance Added | Temp Before | Temp After | Change in Temp(Celsius) | Observations | Open - Calcium Chloride | 24 | 30 | 6 | translucent ‚ slightly murky | Open - Ammonium Nitrate | 24 | 30 | 6 | translucent‚ slightly murky | Closed - Calcium Chloride | 24 | 18 | 6 | transparent | Closed - Ammonium Nitrate | 24 | 17 | 7 | transparent | Calculations i) Calcium Chloride: Q = (100) (4.184) (6) = 2510.4 Ammonium Nitrate: Q = (100) (4.184) (7) = 2928.8 ii) NH4NO3: (14.0067)
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4) aluminum oxide 5) sodium iodide 6) strontium fluoride 7) lithium sulfide 8) radium chloride 9) calcium oxide 10) aluminum phosphide 11) potassium sulfide 12) lithium bromide 13) strontium phosphide 14) barium chloride 15) sodium bromide 16) magnesium fluoride 17) sodium oxide 18) strontium sulfide 19) boron nitride 20) aluminum nitride 21) cesium oxide 22) rubidium iodide 23) magnesium oxide 24) calcium bromide 25) lithium iodide 26) berylium bromide 27) potassium oxide 28) strontium iodide
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Chemical Reactions and Equations Chemical Reaction: The transformation of chemical substance into another chemical substance is known as Chemical Reaction. For example: rusting of iron‚ setting of milk into curd‚ digestion of food‚ respiration‚ etc. In chemical reaction new substance is formed which is completely different in properties from the original substance‚ so in a chemical reaction chemical change takes place. Following are the signs of chemical reaction: (a) Change of state of substance
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as CaCO₃. High levels of total hardness are not considered a health concern. There are two types of Hardness: Temporary hardness: this is due to the presence of bicorbonates of calcium and magnesium. It can be easily removed by boiling. Permanent hardness: this is due to the presence of chlorides & sulphate of calcium & magnesium. This type of hardness cannot be removed by boiling. MOTIVATION I was bothered that the water in Ilara community doesn’t combine easily with soap leading to excessive
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ST ANDREW’S JUNIOR COLLEGE JC 2 Preliminary Examination CHEMISTRY 9647/03 Higher 2 13 September 2010 Paper 3 Free Response 2 hours Candidates answer on separate paper. Additional Materials: Answer paper‚ Graph Paper‚ Data Booklet READ THESE INSTRUCTIONS FIRST Write your name and civics group on all the work you hand in. Write in dark blue or black pen on both sides of the paper. You may use a soft pencil for any diagrams‚ graphs or rough working. Do not use staples‚
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constant‚ Ksp is given in the following example: Ksp for AgCl is Ksp = [Ag][Cl] Ksp for PbI2 is Ksp = [Pb][I]2 This gives the relationship between the ions in the saturated solution and is the maximum concentration possible without creating precipitation. In this lab‚ solutions of lead nitrate and potassium iodide will be mixed at a number of dilutions. The reactions will then be observed to see at which point a precipitate no longer occurs. Ksp will then
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Ksp Cu(OH)2 Keq = Ksp Cu(OH)2 = 2.2 x 10-20 b. + 6.0M H2C2O4 Cu(OH)2(s) (( Cu2+(aq) + 2OH-(aq) Ksp Cu(OH)2 H2C2O4 (( H+ + HC2O4- Ka1 H2C2O4 HC2O4- (( H+ + C2O42- Ka2 H2C2O4 Cu2+ + C2O42- (( CuC2O4 1/Ksp CuC2O4 2(OH- + H+ (( H2O) 1/K2w Net Keq = (Ksp Cu(OH)2 x Ka1 x Ka2 )/Ksp CuC2O4 = 1.969 x 10-2 c. pinch of Zinc dust Cu(OH)2(s) (( Cu2+(aq) + 2OH-(aq) Ksp Cu(OH)2
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