Lab Questions: Unit 1 Autopsy of a Crime Scene 1. Which technique is the best choice when blood is found at a crime scene? In the genetics laboratory‚ who is one individual that contributed to modern genetic analysis? What did this person contribute? - The DNA Analysis Technique is the best choice because no two individuals have the same DNA. This makes it easy to determine a match between the person the blood came from and the blood sample. Alec Jeffrey’s came up with the first genetic profile
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indicated by a very pale pink color. To calculate the molarity of NaOH‚ the following equation was used MNaOH x VNaOH = MKHP x VKHP therefore the molarity was .125 M. INTRODUCTION This lab experiment covers the preparation of standard solution and the acid/base titration. The first part of the lab is to prepare a standard solution of Potassium hydrogen per. A standard solution is a solution of known concentration‚ in which it is prepared using exacting techniques to make sure that the molarity
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Lab 5 The Diffraction Grating Chinua McDonald Objective: To measure the wavelength of light with a diffraction grating. Theory: The two types of diffraction gratings are the transmission and reflection gratings. They are made by ruling on a piece of glass or metal a number of evenly spaced lines with a fine diamond point. Diffraction phenomena can be analyzed in terms of Huygens’ principle‚ according to which every point on the wave front of a wave should be considered as a source
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Grayland Martin Period 5 9/4/12 Laboratory 2 Report: Enzyme Catakysis 1. Title • The effect that temperature‚ pH‚ time‚ enzyme concentration‚ and substrate concentration has on Enzyme Catalysis. 2. Abstract • Assess the general functions and activities of enzymes. Analyze the relationship between the structure and function of enzymes. Understand the concept of initial reaction rates of enzymes. Change the temperature‚ pH‚ enzyme concentration‚ substrate
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Epoxidation Reactions Lab Report 2 Abstract An oxygen atom is transferred from a peroxy acid to the carbon=carbon double bond thus forming an epoxide. Scheme 1. Oxone Epoxidation. Scheme 2. mCPBA Epoxidation. The percent yield for the Oxone epoxidation reaction was 65% yield and the mCPBA epoxidation reaction was 70% yield. Oxone is the greener alternative because using mCPBA is twice as expensive as Oxone and leaves behind the epoxide plus m-chlorobenzoic acid while Oxone creates non-toxic
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IS3110 LAB 5 Identify Threats and Vulnerabilities in an IT Infrastructure 1. What are the differences between ZeNmap GUI (Nmap) and Nessus? NMAP is primarily a host detection and port discovery tool. Instead of using Nessus to look for specific vulnerabilities against a known quantity of hosts‚ NMAP discovers active IP hosts using a combination of probes. On the other hand Nessus takes the open ports into account and notifies you if these ports have potential security vulnerabilities attached
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Identities expressing trig functions in terms of their complements cos t = sin([pic]/2 – t) sin t = cos([pic]/2 – t) cot t = tan([pic]/2 – t) tan t = cot([pic]/2 – t) csc t = sec([pic]/2 – t) sec t = csc([pic]/2 – t) Periodicity of trig functions. Sine‚ cosine‚ secant‚ and cosecant have period 2[pic] while tangent and cotangent have period[pic]. sin (t + 2[pic]) = sin t cos (t + 2[pic]) = cos t tan (t + [pic]) = tan t Identities for negative angles. Sine‚ tangent
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NTC 324 Week 2 Individual Assignment With Lab Challenge https://hwguiders.com/downloads/ntc-324-week-2-individual-assignment-lab-challenge NTC 324 Week 2 Individual Assignment With Lab Challenge NTC 324 Week 2 Individual Assignment Assignment Preparation: Activities include completing the assigned reading‚ independent student reading‚ and research. Choose the best answer for each question in the “Best Answer” at the end of these chapters‚ and write a few sentences for each question to justify
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cheese. Lactic acid bacteria(LAB)‚ a bacteria that can be found in the production of cheese‚ its stress gene was investigated in the experiment by using various biochemical and genetic techniques to identify and extract. The characterisation of the strain illustrates how identification of strains differ using different methods‚ such as gram stain and 16s rRNA screening. After the characterisation‚ the stress gene isolation assist the further understanding of the gene on LAB be giving different stress
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absorptivity (1). Then we can use the value of Ԑ to determine the concentration of [K2Cr2O7]‚ by taking the absorbance ratings and dividing them by Ԑ. Determining the order of reaction for a reactant‚ in this case K2Cr2O7‚ must be done experimentally (2). This is accomplished by making three graphs. One is concentration of reactant‚ [K2Cr2O7]‚ versus time which shows if there is zero order dependence of specific reactant. The second is the natural log of the concentration of a reactant‚ ln[K2Cr2O7]
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