Pre-Lab Work Sheet Which type of compound usually has higher melting points: ionic compounds or covalent compounds? What is the reason for this difference in melting points? (3 points) Ionic compounds have higher melting and boiling points than covalent compounds. The electrostatic attraction in an ionic bond is very strong hence a lot of heat energy is required to break it down‚ ionic bonds have high melting and boiling points. In covalent bonds‚ the intermolecular forces are very weak and
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points are properties that can easily be determined and help in identifying a substance. These properties can be found in chemical literature ad reference tables‚ and can be used to distinguish a pure substance from many other pure substances. In this lab you will use the pure substance Paradichlorobenzene and determine its melting an freezing points by warming and cooling a sample of the substance‚ then plotting heating and cooling curves and analyzing them. Data that you collect will represent the
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Unit 2 Home Labs Goals: • Read Safety • Perform Changes: Physical or Chemical Lab • Perform Special Physical Properties of Matter Lab • Perform Paper Chromatography Lab Turn-in: 1) Changes: Physical or Chemical Lab - Completed Procedure / Observations‚ questions‚ and a written description of most important concept that you learned in the discussion section. 2) Special Physical Properties of Matter Lab – Completed Procedure / Observations‚ questions‚ and
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MBK Lab 01 – Lab Report Name: ____________________ Section: ___________________ EXPERIMENT 1 TITLE: Observing Bacteria and Blood OBJECTIVE: To gain functional knowledge of microscope operations through practical applications of a microscope in the observation of bacteria and blood. PROCEDURES: Using the microscope‚ an oil immersion lens and observing Bacteria Cultures in Yogurt . Preparing a Blood Slide and observing Blood: After reviewing the section of the manual
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Lab 10 Name: Complete the following then save with your name and attach to the dropbox for lab 10. Data Tables and Post-Lab Assessment Experiment 1 Post-Lab Questions 1. Label each of the arrows in the following slide image: A. Chromosomes B. Nucleus C. Cytoplasm D. Cell wall 2. What is the difference between the rough and smooth endoplasmic reticulum? 3. Would an animal cell be able to survive without mitochondria? Why or why not? 4. What
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is the capacitative reactance‚ R is the resistance‚ and ω = 2π f ( f is the linear frequency). Apparatus • PC with DataStudio installed • Science Workshop 750 USB Interface Box • Power Amplifier • Voltage Sensor • AC/DC Electronics Lab Board • LCR meter • Connecting patch cords Experimental Procedure The experimental procedure can be divided into three parts: Part I: Using a Frequency Scan to Determine the Resonance Frequency • The first
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derived from Hess’s Law. Pre-lab Questions: 1. Define Heat of Reaction. The enthalpy change associated with the completion of a chemical reaction. 2. Define Specific Heat. The energy it takes to raise the temperature of 1 gram of a substance by one degree Celsius. 3. Calculate the heat of reaction assuming no heat is lost to the calorimeter. Use correct significant figures. Q = c x m x t q = (4.18)(1.02 g/ml x 50ml )(3.9 oC) = -831 J 4. In problem 3 above‚ the calorimeter has
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AP Lab #5 Plant Pigments/Photosynthesis I. Identifying the Effects of Different Variables of Light and Carbon Dioxide on the Rate of Photosynthesis and Observing the Separation of Pigments Through Chromatography II. Introduction Plants have a variety of pigments‚ all of which absorb a different color of light. The three main pigments are chlorophyll a‚ chlorophyll b and carotenoids. Chlorophyll a is the primary plant pigment that absorbs red and blue light‚ which ultimately appears green to the human eye
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(l) ∆H= -54.0 kJ/mol NH4++ OH- → NH3+ + H2O (l) (x-1) ∆H=-4.09 kJ/mol (x-1) -54.0+4.09=-49.9 NH3+ + H+ → NH4+ =- 49.9 kJ /mol (-49.9- -26.2)/-49.9 x 100 =47.3% Lab Questions: Pre: 1. The change in thermal content in a reaction 2. The amount of energy needed to change one gram of a substance 1 degree C 3. (50 mL)(1.02 g/mL)(4.18 J/g C)(25.3-21.4) = 830 J 4. 830J+8.20J/g C(25.3-21.4)= 860J 5. .25L(.6mol/1L)+.25L(.L/1mol)= 0.3mol AB 830J/.3mol(1kJ/1000J)= 2.7 kj/mol Post 1. Calorimetry
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Lab Report: Stoichiometry Lab Oct. 27‚ 2011 Claire Elizabeth Lab Partners: Hannah Signature:___________________ Introduction- Baking soda and vinegar are two common materials found in almost every household. That‚ plus the fact that all the starting and finishing materials are non hazardous and safe‚ is why this is one of the first chemical reactions that many people are exposed to The purpose of this experiment tests which of the two reactants (vinegar and baking soda) is the limited
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