passed Result: All hard drives (1) are using the NTFS file system. Detail: | Drive Letter | File System | | C: | NTFS | Issue: Password Expiration Score: Check failed (non-critical) Result: Some user accounts (2 of 4) have non-expiring passwords. Detail: | User | | Guest | | sec | Issue: Guest Account Score: Check passed Result: The Guest account is disabled on this computer. Issue: Autologon Score: Check passed
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13! (1 0.85)0 (0.85)130 (1 0.85)1 (0.85)131 0! (13 0)! 1! (13 1)! =0 . 1 2+ 0 09 . 2 7 7 =4 0.39= 839.83% Thus‚ the probability that the engineer incorrectly passes a day’s production as acceptable if only 85% of the day’s Blu-ray players actually conform to specification is 39.83%. (b) What is the probability that the engineer unnecessarily
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The final compound which I am going to look at is 4-aminobenzenecarboxylic acid. The compound is also known as 4-Aminobenzoic acid. The molecular and structural formula of the compound is C7H7NO2 which means that the compound consists of seven carbon atoms attached to seven hydrogen atoms along with one nitrogen atom and two carbon atoms attached as a carbon-oxygen double bond. The displayed formula for the 4-aminobenzenecarboxylic acid compound is shown and it shows the formula in a ring form therefore
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Alarms DeVry University NETW420 Alexander Davis Jun 1‚ 2014 This week’s assignment is to describe various event categories and event based transactions that are used by the Network Management System. It would be impossible to categorize all potential causes for alarms in all existing network systems however‚ understanding some common alerts and categories is essential for any network manager. Many Network Management Systems have a log and event manager that collects data
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4000310515center095000420003263900175001760220OSMOSIS IN POTATO CELLS 450000OSMOSIS IN POTATO CELLS 42672007972425Aruna DhungelbIOLOGY 2A OCTOBER-28-14 00Aruna DhungelbIOLOGY 2A OCTOBER-28-14 Osmosis in Potato Cells Aruna Dhungel Biology 2A October 28 2014 Purpose: To see how much osmosis or diffusion will occurs in potato cell based on the concentration of molarity. Procedure: Obtained 3 cups and label A‚ B‚ and C To cup A added 150ml H2O and 8.775gNaCl (stirred cup) Poured
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The quest to be the first is unending. The need to outdo one another is part of our competitive nature. While this state of mind is embraced‚ ultimately the interpersonal aspect of the diffusion of these innovative ideas helps in determining the sustainability and success. The Kindle has been introduced as the hottest‚ new innovative way to read a book. As the research for this modern form of reading was done‚ the question arose‚ “Who initiated the concept of e-paper?” The essay took a totally
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Assignment Week 4 Chapter 11 20. A parallel RL circuit has values of IL = 240 mA and IR = 180 mA. Calculate the magnitude and phase angle of the circuit current. It=√ IL^2 + IR^2= √ 240mA^2 + 180mA^2= 0.3 x 10^-3= 300mA θ= tan^-1(-IL/IR)= (-240mA/180mA)= -53° 300mA∟-53° 22. Calculate the total impedance for the circuit shown in Figure 11.38b. It= √IL^2 + IR^2= √800mA^2 + 120mA^2= 0.808949 x 10^-3= 808.95mA Zt= Vs/It= 120V/808.95mA = 148Ω θ= tan^-1(-IL/IR)= (-800mA/120mA)= -81.5= 82° 148∟82° 24
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Answers to Questions Activity 1: Simulating Dialysis (Simple Diffusion) (pp. 2–4) 9. All solutes except albumin are able to diffuse into the right beaker. Using distilled water in the right beaker and either the 100 MWCO or 200 MWCO membrane will remove urea from the left beaker and leave albumin If the left beaker contains NaCl‚ urea‚ and albumin‚ you can selectively remove urea by dispensing a concentration of NaCl into the right beaker equivalent to that in the left beaker and by using
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EXPERIMENT 5 GAS DIFFUSION COEFFICIENT OBJECTIVES: Determine the gas diffusion coefficient of acetone using the established Winkelmann’s method KEYWORDS Diffusivity‚ Gas Diffusion Coefficient‚ Winkelmann’s method OVERVIEW The knowledge of physical and chemical properties of certain materials is important because very often process engineering deal with the transformation and distribution of these materials in bulk. One such property is diffusivity. Mass transfer by diffusion takes place
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Part 1 of 1 - 40.85/ 100.00001 Points Question 1 of 22 4.55/ 4.55 Points Record your answer from Lab Exercise #1‚ Step 1‚ Question 1.What time in hours:minutes:seconds GMT did the P waves arrive? A. 01:48:00 Correct B. 01:49:00 C. 01:50:00 D. 01:51:00 Answer Key: B Question 2 of 22 0.0/ 4.55 Points Record your answer from Lab Exercise #1‚ Step 1‚ Question 2. What time in hours:minutes:seconds GMT did the S waves arrive? A. 01:51:30 B. 01:52:00
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