1. Why are spindle fibers important for mitosis? (5 points) Spindle fibers work as a path for chromosomes to travel(Campbell‚ 2009). 2. State the four bases that make up DNA. (4 points) a. (A)-Adenine b. (G)-Guanine c. (T)-Thymine d. (C)-Cytosine (Campbell‚ 2009). 3. What are the two base pairs? (2 points) a. AG b. CT 4. Answer the following questions: a. Define the term crossing over. (3 points) The phase in meiosis where chromosomes exchange segments of genetic materials (Campbell‚ 2009). b. Explain
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of the specialized underlying structures of these life-forms. In order for us to appreciate these special adaptation‚ we first need to know how a typical plant or an animal cell organelle behaves in different water and solute concentrations. In this lab‚ we will determine the effects of hypertonic‚ isotonic and hypotonic solutions on plant and animal cells. In general when an animals cell’s placed in hypertonic solution it shrivels; a plant cell on the other hand undergoes plasmolysis. When an animal
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Lab #1 ‐ Introduction to the Microscopy & Observation of Prokaryotic and Eukaryotic Cells Introduction Many of the cells and organisms that you will be studying are at the lower limits of visibility of light microscopes; therefore‚ it is extremely important that you attain critical lighting and focussing. It is also important to handle the microscope competently to avoid damaging either the microscope or the preparation you are studying
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Extra-Corporeal Membrane Oxygenation (ECMO) is a life-saving treatment for severe respiratory failure irresponsive to mechanical ventilation‚ associated or not with haemodynamic instability‚ and its application fields are widening to refractory sepsis and also to elective thoracic procedures. ECMO is replacing conventional cardio-pulmonary by-pass (CPB) even during lung transplantation due to its potential advantages: the absence of full-anticoagulation and the possibility of maintaining the extra-corporeal
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In this lab we will look at how molecules move across the membrane of a cell . Osmosis is the movement of water across a cell membrane.In osmosis the cell membrane is selectively permeable‚which allows for the membrane to control what types of substances that passes through.Transportation can either be passive or active.Passive transport does not require the use of added energy where as active transport requires the cell to use energy. Diffusion is the simplest form of passive transport. Using
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Cell Membrane Transport ZOOL 2011.19 A. Introduction: Cells are the most significant building blocks of all living things. They are also the tiniest living organisms in the human body which provides structure for the body and intake nutrients that become energy. Cell membranes control what goes in and out the cell‚ it protects it. The lipid bilayer describes the membrane of both animal and plant cells where the properties that make up phospholipids are very important
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Experiment Number 5 10/02/14 Margaret E. Vorndam‚ M.S. Version 42-0038-00-01 Lab Report Assistant This document is not meant to be a substitute for a formal laboratory report. The Lab Report Assistant is simply a summary of the experiment’s questions‚ diagrams if needed‚ and data tables that should be addressed in a formal lab report. The intent is to facilitate students’ writing of lab reports by providing
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Stacy Hernandez Period 1 Mrs. Riley AP Biology Osmosis and Diffusion Lab I. Introduction: Diffusion is vital to many life functions of a cell‚ it allow the transportation of vitally important nutrients and compounds without the expenditure of excess metabolic energy. To explain diffusion‚ it is as if a bottle of perfume is opened at one end of the room‚ then in a short amount of time a person at the other end of the room can detect the scent of the perfume; this is the process of diffusion
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indicated by a very pale pink color. To calculate the molarity of NaOH‚ the following equation was used MNaOH x VNaOH = MKHP x VKHP therefore the molarity was .125 M. INTRODUCTION This lab experiment covers the preparation of standard solution and the acid/base titration. The first part of the lab is to prepare a standard solution of Potassium hydrogen per. A standard solution is a solution of known concentration‚ in which it is prepared using exacting techniques to make sure that the molarity
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Gagneux February 5‚ 2013 Marketing Research 4338 Case 5- Student Computer Lab 1. Did the moderator do an adequate job of getting the information needed by the SCC? The moderator did a good job getting the information needed. * He started out appropriately by explaining who he was and the purpose for the research (focus group). * Encouraged respondents to talk to one another as he started with a broad question everybody could answer (“How do you think the computer lab is meeting your
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