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    Physicals Essay

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    this is because it has more time to accelerate. We hope to find out from our results that the golf balls acceleration is the same as gravity which is 9.81 ms². We intent on showing this through the Suvat equation which is V²=U²+2as where ‘a’ is acceleration. Suvat equations were made by Gottfried Leibniz‚ Suvat stands for displacement (S)‚ Initial velocity (U)‚ Final velocity (V)‚ Acceleration (A) and Time (T). As I said we are using the equation V²=U²+2as‚ but we have to re-arrange this equation

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    Problem Solving Equations

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    distance of 110 m. Determine the acceleration of the car. ------------------------------------------------- Solutions Given: d = 110 m | t = 5.21 s | vi = 0 m/s | | Find:a =?? | d = VI*t + 0.5*a*t2 110 m = (0 m/s)*(5.21 s) + 0.5*(a)*(5.21 s)2 110 m = (13.57 s2)*a a = (110 m)/ (13.57 s2) a = 8.10 m/ s2 ------------------------------------------------- Equations and Problem-Solving * Rocket-powered sleds are used to test the human response to acceleration. If a rocket-powered sled is accelerated

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    Remedial Physics------------------------------------Review Questions -------------------------------------Chapter 2 Quantitative Problems 1) An object moves 15.0 m north and then 11.0 m south. Find both the distance traveled and the magnitude of the displacement vector. A) 6.0 m‚ 26.0 m B) 26.0 m‚ 4.0 m C) 26.0 m‚ 26.0 m D) 4.0 m‚ 4.0 m 2) A boat can move at 30 km/h in still water. How long will it take to move 12 km upstream in a river flowing

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    Velocity and M/s

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    B) 1.3 s C) 5.3 s D) 7.3 s E) 9.3 s 0=16-9t2 t2=16/9 t=1.33 s 4. Over a short interval near time t = 0 the coordinate of an automobile in meters is given by x(t) = 27t – 4.0t3‚ where t is in seconds. At the end of 1.0 s the acceleration of the auto is: A) 27 m/s2 B) 4.0 m/s2 C) –4.0 m/s2 D) –12 m/s2 E) –24 m/s2 at= -24t 5. Each of four particles move along an x axis. Their coordinates (in meters) as functions of time (in seconds) are given by | particle 1:

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    the board. If it enters with a speed of 450 m/s and emerges with a speed of 220 m/s‚ what is the bullet’s acceleration as it passes through the board? Answer: –550 km/s2 5. A particle confined to motion along the x axis moves with constant acceleration from x = 2.0 m to x = 8.0 m during a 2.5s time interval. The velocity of the particle at x = 8.0 m is 2.8 m/s. What is the acceleration during this time interval? Answer: 0.32 m/s2 6. A package is dropped from a helicopter moving upward

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    Projectile Motion

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    vertical motions which are independent from each other‚ known as vector components. For an object to be considered a projectile‚ it must not be self-propelled. Projectiles move horizontally at a constant velocity. However‚ they undergo uniform acceleration in the vertical direction‚ which is caused by gravity. An important aspect of projectile motion is that the time it takes for the object to travel on the Y axis is exactly the same as the time it takes to travel on the X axis. A practical example

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    Terminal Velocity

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    a factor in the practical has a big impact on the outcomes that you get‚ as there is nothing acting against gravity hence a greater acceleration the object has. Having Air Resistance However having air resistance also changes the outcome of the practical because the air resistance is acting against the force of gravity hence the object has less acceleration and once the air resistance is stronger then the terminal velocity that is when the object is going at a small velocity. Terminal

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    Summer Assignment Revision –Term 1 Grade:9 Answer as many as possible: 1) State universal law of gravitation. Express it mathematically. 2) Differentiate between G‘ and g‘ in tabular form. 3) (a) What is acceleration ? Write its unit. (b) Draw velocity-time graph‚ when an object has (i) uniformly accelerated velocity. (ii) uniformly retarded velocity. 4) Prove that if a body is thrown vertically upward‚ the time of ascent is equal to the time of descent. 5) The earth attracts the moon. Does the moon

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    Psy094 Unit 6 Lab Report

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    ball’s acceleration. (b) How far does the ball moves before coming to a stop? 4. A particle moves in a straight line with varying velocity as shown by the velocity time graph in Figure 1. (The graph is not drawn to

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    Free Fall Motion

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    scientificwork interface‚ and photogate to measure the acceleration of gravity‚ g‚ in a free-fall experiment. Using a “picket fence” dropped through a photo gate with disregard for air resistance; students calculated the results from the charted data and compared it with the accepted value of 9.8 m/s2 discussing any variations and their potential causes. Goal The goal of this experiment is to measure g‚ the acceleration of gravity‚ using various software and a picket

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