Understand and use the idea of a vector to represent displacements‚ velocities‚ accelerations and forces in a plane 5. Know the difference between speed (a scalar) and velocity (a vector) 6. Know the difference between “mass” and “weight” 7. Know the difference between “gravitational acceleration” and “gravitational force” 8. Be able to explain what a force is without using the word “force” 9. Be able to explain what time is without using the word “time” 10. Given a velocity or acceleration in terms of unit i and j vectors‚ understand how to find its
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object is moving with uniform accleration. Its velocity after 5 sec is 25m/s and after 8 sec‚it is 34 m/s. Find the distance travelled by this object in 12th second. Ans. 44.5 A particle starts with a velocity of 100 cm/s and moves with –2 cm/s2 acceleration. When its velocity be zero and how far will it have gone? Ans. 50s ‚ 25m m/s. After 7 a time interval ∆t‚ the velocity of the body is reduced by half‚ and after the same time interval‚ the velocity is again reduced by half. Determine the velocity
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CBSE TEST PAPER-02 CLASS - IX Science (Motion) 1. If a body starts from rest‚ what can be said about the acceleration of body? (a) Positively accelerated (c) Uniform accelerated (b) Negative accelerated (d) None of the above [1] 2. What does slope of position time graph give? (a) speed (b) acceleration (c) uniform speed [1] (d) Both (a) and (c) depending upon the type of graph. 3. When a body moves uniformly along the circle‚ then:(a) its velocity changes but speed remains the same (b) its
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determine the minimum speed required to clear 8m in 2.02 s just use D/T= 8/2.02= 3.96 m/s horizontally to clear 8 m from 20 m vertically. 5) Using acceleration = force * mass‚ we know the car had a force of 5000N‚ and a mass of 1500kg. 5000/1500 = -3.33 m/s deceleration. It took 5.6 seconds for the car to decelerate to 0‚ so multiply the deceleration/acceleration with the amount of time to obtain the initial speed of the vehicle. 3.33 * 5.6 = Initial speed of 18.65 m/s 6) Weight is equated as mass * gravity
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Instructor: (Name) Introduction We verified Newton’s Second Law for one-dimensional motion by timing an accelerated glider moving along a flat track. We varied both the accelerating force and the mass of the glider. We found that for a given force the acceleration of the glider was inversely proportional to the mass of the glider‚ in agreement with Newton’s Second Law. Experimental Procedure Description of the Apparatus: A sketch showing the essential elements of the apparatus is presented in Figure 1. below:
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motion in a straight line. 1. Distance travelled as a function of time 2. Velocity as a function of time 3. Acceleration as a function of the accelerated mass 4. Accelerated as a function of force THEORY Newton’s equation of motion for a mass point of mass m to which a force RF is applied is given by the following: m · Ra = RF ‚ where Ra = is the acceleration. The velocity v obtained by application of a constant force is given as a function of the time t by the expression
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Name Class Date Concept-Development Practice Page 4-1 Free Fall Speed 1. Aunt Minnie gives you $10 per second for 4 seconds. How much money do you have after 4 seconds? $40 2. A ball dropped from rest picks up speed at 10 m per second. After it falls for 4 seconds‚ how fast is it going? 40 m/s 3. You have $20‚ and Uncle Harry gives you $10 each second for 3 seconds. How much money do you have after 3 seconds? $50 4. A ball is thrown straight down with an initial speed of 20 m/s. After
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1 Velocity‚ Speed‚ Acceleration‚ and Deceleration The goal for today is to better understand what we mean by terms such as velocity‚ speed‚ acceleration‚ and deceleration. Let’s start with an example‚ namely the motion of a ball thrown upward and then acted upon by gravity. A major source of confusion in problems of this sort has to do with blurring the distinction between speed and velocity. The speed s is‚ by definition‚ the magnitude of the velocity vector: s := |v|. Note the contrast: –
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force and motion I problem 1 The figure below is an overhead view of a 12 kg tire that is to be pulled by three ropes. One force (Fl‚ with magnitude 50 N) is indicated. Orient the other two forces F2 and F3 so that the magnitude of the resulting acceleration of the tire is least‚ and find that magnitude if (a) F2 = 30N‚ F3= 20 N; (b) F2= 30 N‚ F3 = 10 N; and (c) F2 = F3 = 30 N. problem 2 A weight-conscious penguin with a mass of 15.0 kg rests on a bathroom scale (see figure below). What are (a)
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