ORGANIC CHEMISTRY LAB 2: Separation of Organic Liquid Mixtures Introduction: In this experiment‚ a mixture of two compounds‚ cyclohexane and toluene‚ was separated into fractions by the techniques of simple and fractional distillation. The individual fractions that were gathered from the distillation were analyzed using gas chromatography (GC) and used to compare the efficiencies of the two different distillation techniques. The ultimate goal of this experiment was to determine whether simple
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Abstract: This lab experiment was conduct and taught based upon the primary instruction and introduction to mixtures. With this lab I was able to determine and execute the proper separation of a mixture of solids through various means‚ such as evaporation and filtration. Using these techniques presented the separation of different ingredients from a mixture was conducted based upon the usage of individual physical properties of each substance presented in the mixture. . Observations: Throughout
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13! (1 0.85)0 (0.85)130 (1 0.85)1 (0.85)131 0! (13 0)! 1! (13 1)! =0 . 1 2+ 0 09 . 2 7 7 =4 0.39= 839.83% Thus‚ the probability that the engineer incorrectly passes a day’s production as acceptable if only 85% of the day’s Blu-ray players actually conform to specification is 39.83%. (b) What is the probability that the engineer unnecessarily
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The final compound which I am going to look at is 4-aminobenzenecarboxylic acid. The compound is also known as 4-Aminobenzoic acid. The molecular and structural formula of the compound is C7H7NO2 which means that the compound consists of seven carbon atoms attached to seven hydrogen atoms along with one nitrogen atom and two carbon atoms attached as a carbon-oxygen double bond. The displayed formula for the 4-aminobenzenecarboxylic acid compound is shown and it shows the formula in a ring form therefore
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“SOLID WASTE MANAGEMENT IN MALAYSIA” PREPARED BY: SITI AZRYNNA BINTI MOHD AZANI Question 1 What is solid waste management? Solid waste management is another term for garbage management. Solid waste management is a system which handles any garbage‚ refuse‚ sludge from a wastewater treatment plant‚ water supply treatment plant‚ or air pollution control facility and other discarded materials including solid‚ liquid‚ semi-solid‚ or contained gaseous material‚ resulting from industrial
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Determination of Cleansing Action of Detergents (Using Capillary rise) Synopsis This project report explains about the surface tension and capillarity of liquid through a simple experiment of finding the capillarity of various detergents. Oil stains and grease on dirty clothes cannot be removed‚ using water alone‚ because water does not wet them. If detergents added ‚ surface tension is decreased‚ the area of contact is increased
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Alarms DeVry University NETW420 Alexander Davis Jun 1‚ 2014 This week’s assignment is to describe various event categories and event based transactions that are used by the Network Management System. It would be impossible to categorize all potential causes for alarms in all existing network systems however‚ understanding some common alerts and categories is essential for any network manager. Many Network Management Systems have a log and event manager that collects data
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A solution to case study Liquid Chemical Company A Proposal Presented to Dr. Madhumita Chakraborty Indian Institute of Management‚ Lucknow On November 25th‚ 2008. In Partial Fulfillment of the Requirement for the Course Management Accounting -II by Name Roll Number Rajesh Kumar Snehi 24089 Sai Harish Chava 24090 Samarendra Singh 24092 INTRODUCTION The Liquid Chemicals Company (LCC) produces and sells a wide variety of high grade products throughout
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Assignment Week 4 Chapter 11 20. A parallel RL circuit has values of IL = 240 mA and IR = 180 mA. Calculate the magnitude and phase angle of the circuit current. It=√ IL^2 + IR^2= √ 240mA^2 + 180mA^2= 0.3 x 10^-3= 300mA θ= tan^-1(-IL/IR)= (-240mA/180mA)= -53° 300mA∟-53° 22. Calculate the total impedance for the circuit shown in Figure 11.38b. It= √IL^2 + IR^2= √800mA^2 + 120mA^2= 0.808949 x 10^-3= 808.95mA Zt= Vs/It= 120V/808.95mA = 148Ω θ= tan^-1(-IL/IR)= (-800mA/120mA)= -81.5= 82° 148∟82° 24
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UNIT - I COMPTER FUNDAMENTALS & PROBLEM SOLVING Kishore Kumar M UNIT-I UNIT-I Contents : ➢ Introduction to computers –Computer Systems ➢ Computing Environments ➢ Computer Languages ➢ Creating and running programs
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