Dilutions Calculations (M1V1 = M2V2‚ careful with M2) * Solution Stoichiometry * volume-volume conversions * volume-mass conversions * Molecular interpretation of solubility * solubility rules * Precipitation Reactions * Determining reaction products * Following Solubility rules * Molecular Formula‚ Total ionic formula‚ net ionic formula * Acid-Base Reactions * Oxidation-Reduction reactions
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Resolution of Matter into Pure Substances – Paper Chromatography Abstract The purpose of this laboratory was to determine how different substances have different solubilities in a given solvent. This was accomplished using the method of chromatography. The solubility of each substance was first determined by dropping a drop or two of each on a line drawn 2 inches above the bottom of a piece of paper. Then the paper was lightly bent in order to tape both sides of the paper leaving about a 4 centimeter
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PREPARATION OF TIN TETRAIODIDE 09/06/2012 Introduction The objective of this project was to prepare tin tetraiodide through the following reaction: Sn+2I2∆SnI4 and to measure the melting point of tin tetraiodide. Tin tetraiodide was recrystallized after the synthesis. The percent yield and the theoretical yield of tin tetraiodide were calculated. Recrystallization is to further improve the purity of tin tetraiodide. The solvent is carefully chosen to be toluene in order to maximize the recovery
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Purpose The goal of the investigation was to observe if certain solutes would result in dissolving in different solvents. Solubility is what determines if a substance will dissolve in a certain solvent. The ionic solutes will dissolve into the polar solvents and the covalent solutes will dissolve into the non-polar solvents because the molecules of the solvents have a stronger force that will break apart the solute and dissolve it into the solvent. Procedure Small amount of the solutes‚ roughly
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throughout f. Henry’s Law An expression for calculating the solubility of a gas in a fluid based on temperature and partial pressure g. solution mixture of two or more substances h. Molarity concentration measured by the number of moles of solute per liter of solution. i. Osmosis The tendency of molecules of a solvent to pass through a semipermeable membrane from a less concentrated solution into a more concentrated solution j. Solubility the quantity of a particular substance that can dissolve
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Purpose The purpose of this experiment is to observe reactions of chemicals that can be found in consumer products. Through observation‚ students should be able to interpret the chemical reactions and determine some characteristics‚ such as pH and solubility. Method 1. Pipets containing chemicals will be opened using scissors to snip the end and each pipet will be placed in a well of a 24-well plate. The scissors must be washed between each pipet. 2. A 96-well plate will be placed onto a white sheet
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(mol) Theoretical moles of Product (mol) Theoretical mass of Product (g) Actual Mass of Product (g) % yield 〖CuSO〗_4 (s) 1.992 g .0124 mol .0124 mol 3.047 g 2.640 g 86.64% Solubility of Precipitate ion [Cu(NH_3 )_4 ]SO_4*H_2 O+Solvent Observation of Solubility [Cu(NH_3 )_4 ]SO_4*H_2 O + Acetone When the precipitate ion was added to ~1 mL of acetone there was a strong property of insolubility. Even when a stir rod was used to mix the precipitate in the acetone‚ the
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Introduction: The theory behind the extraction of a solution containing benzoic acid‚ cellulose‚ and methyl orange involves many components pertaining to the fundamental ideas of solubility and polarity. Using the concepts of like dissolving like and acid base reactions‚ a solution of organic acid (benzoic acid)‚ a water soluble compound cellulose‚ and an organic soluble compound methyl orange‚ can be separated and benzoic acid can be isolated by a method of extraction. At the fundamental
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Experiment18 Aim To determination the partition coefficient of ethanoic acid between water and butan-2-ol. Procedure 1. The room temperature was recorded. 2. 15cm3 of the given aqueous ethanoic acid and 15cm3 of butan-2-ol were poured into a 100cm3 separating funnel‚ using suitable apparatus. The funnel was stoppered and was shook vigorously for 1 to 2 minutes. (The pressure in the funnel was released by occasionally opening the tap.) 3. 10cm3 of each layer was separated
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Water • Define the terms solute‚ solvent and solution • Solute: Substances dissolved by the solvent (or the component present in a lower amount) • Solvent: Substances in which solutes are dissolved (or the component present in a larger amount) • Solution: A homogenous mixture of 2 or more substances • 1.1.2. Identify the importance of water as a solvent. • Water is distributed in the biosphere‚ lithosphere‚ hydrosphere and atmosphere • On earth‚ it is distributed as a solid‚ liquid and gas
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