(most significant bit [MSB]) Read the answer from bottom (MSB) to top least significant bit (LSB): 110010 Convert 110010 binary into decimal. Weights 32 16 8 4 2 1 Bits 1 1 0 0 1 0 Adding the weights whose bits are 1: 32 + 16 + 2 = 50 Solution: 125/2=62 remainder 1 62/2=31 remainder 0 31/2=15 remainder 1 15/2=7 remainder 1 7/2=3 remainder 1 3/2=1 remainder 1 1/2= 0 remainder 1 Reading the answer from bottom to top =1111101 Weights 64 32 16 8 4 2 1 Bits 1 1 1
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watermark contents are embedded into the elements in second and third rows offirst column of left singular matrix U since they have much closer value and represent proper threshold. The values of this pairare reclaimed using the threshold to embed a bit of watermark content.One binary image (logo) and other text data have been used as watermark contents.Thisscheme offers better visibility of watermarked image and recovery of watermark content due toDWT-SVD combination.Using proposedscheme‚ watermark
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(27)10 = (162)10 + (973)10 = (135)10 (c) Convert the following numbers into binary and perform the arithmetic operations in (i) and (ii) using signed binary numbers with 2’s complement. Use 7 bits to represent the integer part of decimal numbers and the sign bit. Use three bits to represent the fractional part. (i) (4.5)10 – (9)10 (ii) (8.5)10 + (9)10 (4.5)10 = 0000100.100 (9)10 = 0001001.000 2’s of (9)10
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Introduction - Basic Flip-Flop Circuit A flip-flop circuit can be constructed from two NAND gates or two NOR gates. These flip-flops are shown in Figure 2 and Figure 3. Each flip-flop has two outputs‚ Q and Q’‚ and two inputs‚ set and reset. This type of flip-flop is referred to as an SR flip-flop or SR latch. The flip-flop in Figure 2 has two useful states. When Q=1 and Q’=0‚ it is in the set state (or 1-state). When Q=0 and Q’=1‚ it is in the clear state (or 0-state). The outputs Q and Q’ are
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Shifts the bits in the first operand (destination operand) to the left or right by the number of bits specified in the second operand (count operand). Bits shifted beyond the destination operand boundary are first shifted into the CF flag‚ then discarded. At the end of the shift operation‚ the CF flag contains the last bit shifted out of the destination operand. The shift arithmetic left (SAL) and shift logical left (SHL) Instructions perform the same operation; they shift the bits in the destination
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perform addition of two binary numbers‚ to produce a sum and carry out‚ is called a HalfAdder. In multi-bit binary numbers‚ after adding the two least significant bits‚ the addition becomes one of adding two operands plus the carry produced by the previous add. The circuit to implement this operation is called a Full-Adder. A circuit to add two multi-bit binary numbers together in parallel‚ or at least pseudo-parallel is called a ripple-carry adder. We will examine each of these circuits below. Half
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. 6 TRANSFER FRAMES FORMAT .............................................................................................................. 7 6.1 AX.25 TRANSFER FRAME FORMAT 6.1.1 Flag (8 bits) 6.1.2 AX.25 Transfer Frame Header (128 bits) 6.1.3 Information Field (0 to 2048 bits) 6.1.4 Frame-Check Sequence (16 bits) 6.2 TELEMETRY INFORMATION FIELD USAGE 6.2.1 Telemetry Transfer Frame Secondary Header 6.2.2 Data 6.2.3 Telemetry Transfer Frame Trailer 6.3 TELECOMMAND INFORMATION FIELD USAGE 7 7 7 8 8
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result in a small amount of call quality degradation due to transcoding. Secondly‚ why should one use G727 for VoIP? This objective is to get the best results for VoIP by embedding 2-bit quantizer to 3-bit quantizer‚ and the same for the higher modes. This permits the dropping of the least significant bit from the bit stream without any adverse effect on speech signals. Thirdly‚ why should one use UDP? Most often‚ UDP applications do not employ reliability mechanisms. Streaming media and voice over
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Which of the following bit patterns cannot be expressed in hexadecimal notation? A. 11111111 B. 1001 C. 110011 D. 100000000001 ANSWER: C 4. Which of the following is the binary representation of 4 5/8? A. 100.11 B. 10.011 C. 110.101 D. 100.101 ANSWER: D 5. Which of the following bit patterns represents the value 5 in two’s complement notation? A. 00011010 B. 11111011 C. 00000101 D. 11111011 ANSWER: C 6. Which of the following bit patterns represents the
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InvenSense Inc. 1197 Borregas Ave‚ Sunnyvale‚ CA 94089 U.S.A. Tel: +1 (408) 988-7339 Fax: +1 (408) 988-8104 Website: www.invensense.com Document Number: RM-MPU-9150A-00 Revision: 4.2 Release Date: 09/18/2013 MPU-9150 Register Map and Descriptions Revision 4.2 CONFIDENTIAL & PROPRIETARY 1 of 52 MPU-9150 Register Map and Descriptions Document Number: RM-MPU-9150A-00 Revision: 4.2 Release Date: 9/18/2013 CONTENTS 1 REVISION HISTORY ..........................................................
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