Cell Biology- Osmosis‚ Cell Size and Diffusion and Enzymes 1.0 INTRODUCTION Cells are the basic building blocks of all living things. They provide structure for the body‚ take in nutrients from the food‚ convert those nutrients into energy‚ and carry out specialized functions. Cells also contain the body’s genetic material and can make copies of themselves. A cell is also a metabolic compartment where many different chemical reaction occur. There are two types of cells‚ eukaryotic and prokaryotic
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potato pieces‚ paper towels‚ iodine Purpose: to identify why cells are so small. Hypothesis: Make a statement as to which potato cubes will diffuse the closer to the center of a cell (small‚ medium‚ large. __________________________________________________________________________________________________________________________________________________________________________ Dimensions For Experiment 3 Cubes with sizes A) 0.5 cm B) 1.0 cm C) 2.0 cm Experimental Evidence: 1. Using
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the Ratio of Surface Area to Volume on Transformation Efficiency in Escherichia coli K-12 Eliana Pouchard‚ Steve Teng‚ and Cameron Wong Department of Microbiology & Immunology‚ UBC In the process of transformation‚ bact eria take up DNA fr om the environment through their cell wall. To induce competence in the cells‚ the DNA for uptake must first attach to the cell surface prio r to passing throug h the membrane. Previous studies on the effect of surface area on transformation
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Mathematics Volume of Solids Formulae for Volume of Solids Cube | Cuboid | Triangular Prism | Cylinder | Cone | Pyramid | Sphere | AnyPrism | s3 | lwh | ½bhl | Πr2h | 1/3πr2h | 1/3Ah | 4/3πr3 | Ah | A = area of the base of the figure s = length of a side of the figure l = length of the figure w = width of the figure h = height of the figure π = 22/7 or 3.14 1. Compute the volume of a cube with side 7cm. Volume of cube: s3 s = 7cm s3 = (7cm x 7cm x 7cm) = 343cm3 2. Compute
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Surface area / Volume ratio Experiment Introduction: The surface area to volume ratio in living organisms is very important. Nutrients and oxygen need to diffuse through the cell membrane and into the cells. Most cells are no longer than 1mm in diameter because small cells enable nutrients and oxygen to diffuse into the cell quickly and allow waste to diffuse out of the cell quickly. If the cells were any bigger than this then it would take too long for the nutrients and oxygen to diffuse into
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relationship between surface area and volume was investigated. Plasticine was formed into a cube and a sphere; both shapes were cut in half. It was found that plasticine volume should not vary‚ two halves have a greater surface area than a whole‚ and cubes have a greater surface area than spheres of the same volume. In Part B‚ the relationship between diffusion and surface area to volume ratio was investigated. Three agar-phenolphthalein-sodium hydroxide cubes of different sizes were exposed to a sulfuric
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AREA (i) The area of a rhombus is equal to the area of a triangle whose base and the corresponding altitude are 24.8 cm and 16.5 cm respectively. If one of the diagonal of the rhombus is 22 cm‚ find the length of the other diagonal. (ii) The floor of a rectangular hall has a perimeter 250m. If the cost of paining the four walls at the rate of Rs 10 per m2 is Rs 1500. Find the height of the hall. (iii) A room is half as long again as it is broad. The cost of carpeting the room at Rs
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Effects of Surface Area to Volume ratio in Agar Introduction: What is an efficient way to maximize mass but minimize diffusion time in cell? Answer: An efficient way to maximize mass but minimize diffusion time in a cell is to increase its surface area. If you increase the surface area of a cell relatively to its volume‚ then the diffusion time will decrease. Materials: Agar cubes‚ bromothymol blue- pH indicator‚ vinegar‚ ruler‚ spatula‚ beaker. Methods: I used agar cubes as cell models. The
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Research As an object becomes bigger its surface area and volume increases but the surface area to volume ratio decreases‚ this is because volume increases quicker than the surface area; as volume is three dimensional. This concept applies to cells and reaction rate because cells need to absorb their food‚ water and oxygen through their cell membrane and depending on the size of the cell membrane the rate at which it absorbs its requirements is changed. If the cell is large‚ the time which it takes to
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Surface area Surface area is the measure of how much exposed area a solid object has‚ expressed in square units. Mathematical description of the surface area is considerably more involved than the definition of arc length of a curve. For polyhedra (objects with flat polygonal faces) the surface area is the sum of the areas of its faces. Smooth surfaces‚ such as a sphere‚ are assigned surface area using their representation as parametric surfaces. This definition of the surface area is based on methods
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