Biology The aim of this investigation is to prove the effect of increasing size on the efficiency of diffusion. Diffusion is the process that cells use to obtain oxygen‚ water and food. Also‚ how they lose waste substances‚ for example‚ urea and carbon dioxide. Basically‚ Diffusion is when particles move from an area of high concentration to an area of low concentration. The surface area to volume ratio of the cell is an important factor in diffusion. It is the effect of this factor that will
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Math: Task 5: Surface Area of Cubes Introducing Surface Area For a fifth or sixth grade class to understand the concept surface area in relation to a cube they need to understand what a cube is first. They will learn that a cube is a special type of rectangular solid. The length‚ width‚ and height of a cube are exactly the same. After explaining what a cube is they will need to understand what it means to find the surface area. The surface area is not the same as finding the volume of a cube. The
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|Subject: Surface area of a sphere | A connection which could be illustrated‚ and could be understood by students who know the perimeter of a circle‚ runs as follows: Put the sphere of radius R inside a cylinder‚ with the cylinder just touching the equator‚ and cut off at the height of the top and bottom of the sphere. (A cutaway view is in the diagram.) [pic] What is the area of the curved part of
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Section Question 1. a) What number must be subtracted from 2x3 – 5x2 + 5x so that the resulting polynomial has a factor 2x – 3 ? [3] b) D‚ E‚ F are mid points of the sides BC‚ CA and AB respectively of a Δ ABC. Find the ratio of the areas of Δ DEF and Δ ABC. [3] c) A man borrowed a sum of money and agrees to pay off by paying Rs 3150 at the end of the first year and Rs 4410 at the end of the second year. If the rate of compound interest is 5% per annum‚ find the sum borrowed
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Performance Task in GEOMETRY * Computation of the surface area‚ amount and type of needed material and the volume of the package. Volume V= L x H x W = (23 cm) (4 cm) (12cm) = (276) (4) = 1 104 cm Area A= L x W = (23cm) (12cm) = 276cm Surface Area A= 2(Lh) + 2(Lw) + 2(Wh) / 2( lh + lw + wh) = 2(23*4) + 2(23*12) + 2(12*4) = 2(92) + 2(276) + 2(48)
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Maximum Cell Size & Diffusion – Ferris Shaw Research Question: How does the surface area to volume ratio affect the diffusion rate in agar cubes? Hypothesis: The rate of diffusion in directly related to the surface area to volume ratio of cells and is responsible for the efficiency of absorbing nutrients‚ oxygen‚ minerals etc. in the cell. This ratio is specific to cells as they require a ratio that isn’t big enough to take too long to receive the nutrients and oxygen or too small to
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find out if surface area affects reaction rate‚ and this experiment proved that surface area in fact does affect reaction rate. My experiment used a berocca tablet that was either cut into sections or left whole‚ the smaller fractions had a larger surface area as there was more area to cover‚ the pieces were then put into water to see what sized tablet reacted to the water the fastest. My hypothesis was supported as it was proven that the smaller pieces which had a larger surface area were much quicker
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Cell Size Control David A Guertin‚ Whitehead Institute for Biomedical Research‚ Cambridge‚ Massachusetts‚ USA David M Sabatini‚ Whitehead Institute for Biomedical Research‚ Cambridge‚ Massachusetts‚ USA Growth in biological systems is defined as the accumulation of mass‚ which leads to an increase in size. In this article‚ we discuss how cells‚ organs‚ and organisms normally control growth‚ and how deregulated growth can lead to a variety of pathological conditions. Introductory article Article
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ASSESMENT DATA COLLECTION AND PROCESSING CONCLUSION AND EVALUATION RELATIONSHIP BETWEEN SURFACE AREA AND THE VOLUME OF A CELL‚ HOW IT AFFECTS THE RATE OF DIFFUSION Nazirul Ibrahim 04.10.2011 DATA COLLECTION AND PROCESSING We have determined the following variables: * dV- the time for the color indicator phenolphthalein to reach the center of the cube (diffusion) * iV- the size of the cube * cV- the amount of Sodium Hydroxide the perfect dimensions of the cube‚ how the
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whatever the temperature may be. The larger the surface area‚ means there can be more “paths” from the sides of the body that are capable of releasing this heat particles‚ and reaching thermal equilibrium faster. This is what happens when a hotter body is subjected to a colder one. Research Question: How does the surface area to volume ratio affect heat loss in organisms? Hypothesis: I hypothesize that the larger the surface area to volume ratio‚ the more heat will be lost and vice versa
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