The Law of Conservation of Mass Goals: 1. To identify the parts of a chemical equation. Students need to identify subscripts‚ coefficients‚ reactants‚ products‚ chemical formulas‚ and chemical symbols 2. To appreciate that scientific discoveries are often the result of inquiry. 3. to distinguish between an element‚ a compound‚ and a mixture (and between heterogeneous and homogeneous mixtures) 4. To balance a chemical equation in order to prove that the Law of Conservation of Mass works quantitatively as well as conceptually
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digging. What is x? Given this scenario the Pythagorean Theorem would be the strategy we use to solve for x. I started off with the Pythagorean Theorem. I then plugged the binomials into the Pyth. Thrm. Next I moved (2+6)^2 to le left of the equation by subtracting (2x+6)^2 from both sides. I then squared the expression Next I foiled the expression by multiplying and combining like terms. I multiplied -1 by each term inside the parentheses and then removed the parentheses around the expression
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involved in economics. Some argue‚ the process is not focused on linear (Sayes 2012; Hughes 2000). An analyses of Ziziphus mauritiana linkage and production process‚ shows that they are a complex web of economic inter-linkages). Contrary to being linear as often suggested. Instead‚ value chains are more space‚ time and socially constructed. The study noted with concern that value chain has been and is still being described as linear (Ash 2013). Suggesting there is a beginning node and the ending
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water according to the following equation: → 2Agϩ(aq) ϩ CrO42Ϫ(aq) Ag2CrO4(s) ← Which of these correctly represents the equilibrium expression for the above equation? 2[Agϩ] ϩ [CrO 42Ϫ] [Agϩ]2[CrO42Ϫ] [Ag2CrO4] (a) ᎏᎏ (b) ᎏ ᎏ (c) ᎏ ᎏ 1 Ag2CrO4 [Agϩ]2[CrO42Ϫ] [Agϩ]2[CrO42Ϫ] (d) ᎏᎏ 2[Ag2CrO4] 2. Are pure solids included in equilibrium expressions? Explain your answer. 3. Write the equilibrium expression for the following hypothetical equation: → 2C(aq) ϩ 3D(aq) 3A(aq) ϩ B(aq)
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the Symbol button on the Symbols Group > Choose the appropriate symbol. 5. Equations Word 2007 also allows you to insert mathematical equations. To access the mathematical equations tool: * Place your cursor in the document > Click Insert Tab > Click the Equation Button > Choose the appropriate equation and structure or click Insert New Equation * To edit the equation > click the equation > Design Tab 6. SPELLING AND GRAMMAR Place the cursor at the beginning of
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model is made up of the velocity‚ and height. The equation is -16t2 + vt + h. V is equivalent to the velocity‚ and h is equal to the height. The vertical motion falls under the influence of gravity. As the force due to gravity may be opposite to the direction of motion‚ there exists the possibility that the body under force of gravity reverses its direction. It is‚ therefore‚ important to understand that the quantities involved in the equations of motion may evaluate to positive or negative values
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Catherine U. Toledo Detailed Lesson Plan I. Objectives: At the end of the lesson‚ the first year section one students should be able to: * Recognize key word that indicates certain mathematical operations. * Translate verbal statement into equations. * Identify the basic steps in solving word problem. * Solve age problems in at least 5 minutes. * Show the process in solving the Age problems. * Demonstrate honesty through solving and checking Age problems. II. Subject Matter:
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See that document for the complete discussion. Here we summarise that document in a form suitable for printing. Equations of Motion In the absence of air resistance: where: s = the position at time t s0 = the position at time t = 0 v0 = the speed at time t = 0 g = the acceleration due to gravity. When there is air resistance‚ it is characterised by a constant : Then the equation of motion is approximately: The Apparatus The precision of the metal scale is one part in 4000. The accuracy
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offering a 20% off sale on complete purchases. Banana (“B”) School Supply is offering a sale in which there is a 25% discount for every dollar amount spent above $20.00. Using two different algebraic equations I will evaluate and compare the two cost options. After solving the systems of equations I will depict the situation graphically using separate amounts of total funds spent in range from $20-$300.00. X= Dollar amount before discount Y= Dollar amount after discount Store “A”
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can use the substitution method to set both equations equal to each other. 5x = 185 5/5 = 185/5 x = 37 Plug x = 37 back into one of the equations above to find y. y = 5 * 37 y= 185 The solution point is 37 hours for $185‚ (37‚$185) Daycare option y = 5x Center based option y = 185 + 8(x-40) (for x > 40 hours) Since they are both equal to y‚ we can use the substitution method to set both equations equal to each other. 5x = 185 + 8(x-40)
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