INSTRUCTIONS: Read carefully each problem and solve them tidily. Use the proper formulas and a scientific calculator to solve them. Write and circle your answers in ink. REMEMBER TO STUDY THE THEORY FROM THE BOOK AND NOTEBOOK TOO. 1. Calculate the linear momentum for each of the following cases: a. A proton with a mass of 1.67x10-27 kg moving with a velocity of 5.00x106 m/s straight up. b. A 15.0g bullet moving with a velocity of 325 m/s to the right. c. A 75.0kg sprinter running with a velocity of10
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Executive Summary: Marketing Strategy Optimization: Using linear programming to establish an optimal marketing mixture. Drew M. Stapleton‚ Joe B. Hanna and Dan Markussen‚ American Business Review 2(21)-pg 54-62 June 2003 In recent times marketing strategy is playing a vital role in a firm success. It optimizes the marketing resources and can improve the revenue generation and market share. Since the global market place is increasing‚ companies find optimizing the marketing effort even more
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Chapter 9 Problems 1‚ 2‚ 3 = straightforward‚ intermediate‚ challenging Section 9.1 Linear Momentum and its Conservation 1. A 3.00-kg particle has a velocity of [pic]. (a) Find its x and y components of momentum. (b) Find the magnitude and direction of its momentum. 2. A 0.100-kg ball is thrown straight up into the air with an initial speed of 15.0 m/s. Find the momentum of the ball (a) at its maximum height and (b) halfway up to its maximum height. 3. How fast can you set the Earth
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conservation of energy and momentum using projectile motion. Theory: The ballistic pendulum demonstrates both the constant horizontal velocity in projectile motion and the conservation of momentum. Because there is no acceleration in the horizontal direction‚ the horizontal component (v_x) of the projectile’s velocity remains unchanged from its initial value throughout the motion. In a closed isolated system‚ if no net external force acts on a system of particles‚ the total linear momentum of the system cannot
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did not make perfect sense for me to note. As far as I am concerned the khan academy does not lecture it so I am not too sure in what to do about this. I am assuming finding velocity is the sole purpose of applying the law of conservation of momentum. Is this true? I also would like to note that a graph could not be drawn in some situations again due to me lacking the technology to send photos of handwritten notes. Hence there is sadly no examples of a problem for translational equilibrium
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mass 0.01 kg at a speed of 200 m/s. The recoil velocity of the rifle is about 0.001 m/s. 0.1 m/s. 1 m/s ***(answer) 0.01 m/s. none of these You’ve given m1 = 2 kg v1 = ? m2 = 0.01 kg v2 = 200 m/s Set it up as a conservation of momentum problem m1v1 = m2v2 Insert values and solve
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compare the change in momentum of the cart with the integral of the measured force vs time graph. Data: Item | Value | Mass of Cart | 516g | Impulse | .35N | Velocity before | .343 m/s | Velocity after | -.318 m/s | Momentum before | .177 kg m/s | Momentum after | -.163 kg m/s | change | -.340 kg m/s | Questions: 1.Why is it desirable to have the same initial speed for each data run? If speed differs‚ the momentum will be effected. As velocity increases‚ momentum increases. 2.How
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Abstract :The purpose of the experiment is to explore elastic and inelastic collisions in order to study the conservation of momentum and energy. The guided track‚ carts‚ photogates ‚ 250 g weight and picket fences were the primary components used in the procedural part of the experiment. Each experiment involved the use of the photogates and picket fences to measure the initial and final velocities of both carts when they collide. The data was collected and translated to a graphical model for further
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Encoding Information with Light’s Orbital Angular Momentum Light is the future of communication‚ traveling at 3‚000‚000 meters per second‚ the cosmic speed limit of the universe. Its tremendous speed makes it optimal for data transmission. The conventional method to encode information in light is through amplitude modulation‚ i.e. light pulses‚ time division multiplexing‚ i.e. delaying the time light beams enter a channel‚ and wavelength multiplexing‚ i.e. multiple beams of light in one channel
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Collision between carts of equal mass: Collision 1 Mass (kg) Initial Velocity (m/s) Final Velocity (m/s) Momentum Initial (kg*m/s) Momentum Final (kg*m/s) Red Cart 2.0 + 50.0 0 0 0 Blue Cart 2.0 - 50.0 0 0 0 Elastic Collision between carts of unequal mass: Collision 2 Mass (kg) Initial Velocity (m/s) Final Velocity (m/s) Momentum Initial (kg*m/s) Momentum Final (kg*m/s) Red Cart 1.0 + 50.0 -33.33 50 -33.33 Blue Cart 2.0 - 50.0 66.66 -100 133.2
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