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    Honey bees

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    = mole fraction liquid and y = mole fraction vapor on the horizontal axis. At a temperature of 114 oC what is the composition of the liquid according to this plot? 8. Examine Figure 5.38. Assume the boiling point for pure B is 120oC‚ for the azeotrope is 135oC‚ and for pure A is 80oC. Assume the azeotropic composition is 0.50 mole fraction A. (a) Draw a rough graph of temperature versus volume of liquid collected for a distillation starting with 100 mL of liquid having composition

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    3.06 Lab Worksheet

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    Part I: Lab Insert completed data tables for each part of the lab. Be sure that the data tables are organized and include units when necessary. Conductivity (4 points Solid Liquid Aqueous Solution Substance A Conductive No Yes Yes Substance B Conductive Yes No No Substance C Conductive No Yes Yes Substance D Conductive Yes No No Part II: Conclusion Answer the following questions in your own words‚ using complete sentences. Based on your observations in the lab

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    8.Heat until separation of solid and solution. 9.Cool flask and allow contents to settle. 10.Decant liquid from solid. 11.Wash solid with water and decant again. 12.Add 4M HCl until solid disappears‚ then add 1-2 ml excess. 13.Add 1g of aluminum to flask. Data/Observations 1.Start with 1g of orange/bronze solid. 2.When HNO3 is added to Cu a dark orange gas is formed. 3.Clear‚ blue liquid forms when Cu is fully reacted. 4.Solid blue precipitate forms when NaOH is added. 5.When heated‚ solution

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    In the novel Catalyst by Laurie Halse Anderson‚ there are three main sections‚ Solid‚ Liquid‚ and Gas. The main character‚ Kate‚ is very interested in science and the three titles are a metaphor for her state of mind throughout the book. The first section‚ Solid‚ shows how Kate is a stable and strong person. The next section‚ Liquid‚ is a time where Kate’s life is very inconsistent and she is unsure about herself. The last section‚ Gas‚ shows how Kate has accepted her fate and tries to help everyone

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    pnb lab practice

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    0 C and some molecules at 100 C for a brief period of time. This explains why wet stuff at room temperature (25 C) can dry out: over time‚ some of the molecules reach a temperature sufficient to "break free" from the liquid‚ becoming a gas. This isn’t limited to liquids either! Even ice in your fridge will lose molecules‚ leading to the puzzling "shrinking ice cube" effect and the ever popular "freezer burn" where $10 sirloin steaks are reduced to dried out slabs of meat. Now‚ I’ll answer

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    from the stove. Strain the mixture through a strainer. Discard the skins and put the liquid in a clean container. 5)Cover the container and keep it in the refrigerator. For our lye 1. Get the ingredients and equipments ready: You would need the following things to try your hand at making lye: two plastic buckets (a small one and a large one ? The small one should fit into the large one in such a way that liquid from the small one drips slowly into the large one); some fresh ash from burning hard

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    compound is the temperature at which the solid is in equilibrium with its liquid. A solid compound changes to a liquid when the molecules acquire enough energy to overcome intermolecular forces holding them together in an crystalline lattice structure. The melting point range is defined as the span of temperature from the point at which the crystals first begin to liquefy to the point at which the entire sample is liquid. This data can be tabulated experimentally through multiple trials for an

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    Chem Lab Mixtures

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    3) Decantation: involves the separation of a liquid from insoluble solid sediment by carefully pouring the liquid from the solid without disturbing the solid. 4) Filtration: involves separating a solid from a liquid through the use of a porous material such as filter paper. The porous material allows the liquid to pass through it but not the solid. 5) Evaporation: involves the process of heating a mixture in order to separate a volatile liquid in the form of a vapor‚ while the remaining component

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    Lab Report on Solubility

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    Separation of the Components of a Mixture General Chemistry 1 (Chem 101)‚ ISP SCUHS Report 2 January 26‚ 2014 Abstract The analyses of mixture were to distinguish and identify homogeneous mixture by using the techniques of decantation and sublimation. By performing these techniques‚ we examined our solutions such as SiO2 (sand)‚ NH4Cl (ammonium chloride)‚ and NaCl (sodium chloride) and mixed H2O (water) with each solution after being heated. After examining our solutions‚ we made calculations

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    objective

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    OBJECTIVES: 1. to investigate the heating process for solid dodecanoic acid 2. to investigate the cooling process for liquid dodecanoic acid 3. to determine and compare the melting and freezing points of dodecanoic acid SUPPLIES: Equipment ring stand buret clamp hot plate test tube (18mm * 150 mm) assembly (half full with solid dodecanoic acid with thermometer embedded) beaker (400 mL) thermometer for water bath lab apron safety goggles Chemical Reagents dodecanoic acid‚ C11H23COOH

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