descriptors All distinction descriptors Key dates: Assignment distribution date to learners: Assignment submission date for TASK 1 & 2: Assignment submission date for TASK 3 & 4: Assignment returns date to learners (if applicable): 14 May 2013 21 June 2013 02 August 2013 10 September 2013 Page 1 of 12 BTEC HND in Business/ Managing Human Resources/May 2013 -BLANK PAGE- Page 2 of 12 BTEC HND in Business/ Managing Human Resources/May 2013 Introduction The aims of this assignment are to measure the outcome
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OBJECTIVE The main purpose of this experiment is:- i. To demonstrate the working principles of industrial heat exchangers ii. To investigate the efficiency of the heat exchanger in parallel and counter flow arrangements 1.0 INTRODUCTION A heat exchanger is equipment in which heat exchange takes place between 2 fluids that enter and exit at different temperatures. The main function of heat exchanger is to either remove heat from a hot fluid or to add heat to the cold fluid. The direction
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Units and tasks DAVID HILTON Unit 7 Management Accounting
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calculator. ____ 9. 2 in. a. 50 in.2 ____ 10. b. 13 in.2 c. 201 in.2 d. 25 in.2 2 in. a. 13 in.2 b. 50 in.2 ____ 11. Find the volume of the triangular prism. c. 6 in.2 d. 3 in.2 7m 7m 9m a. 24.5 m3 b. 441 m3 c. 31.5 m3 d. 220.5 m3 Find the volume of the rectangular prism. ____ 12. a. 108 yd3 ____ 13. b. 540 yd3 c. 560
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------------------------------------------------- ASSIGNMENT 1 1. A rigid tank with a volume of 1.8 m3 contains 15 kg of saturated liquid vapor mixture of water at 90oC. Now the water is slowly heated. Determine the temperature at which the liquid in the tank is completely vaporized. Also‚ show the process on a T-v diagram with respect to saturation lines. (5 marks) 2. A 0.5 m3 vessel contains 10 kg of refrigerant-134a at -20oC. Determine (a) the pressure‚ (b) the total internal energy
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The net force F = ΔP.A that acts on the ball is from the high pressure area(surrounding) to the low pressure area(above the fan) which makes the ball return to its initial position. Recorded air velocity = 5.4 +/- 0.5 m/s. Air density = 1.3 kg/m3 Diameter= (5.040 +/- 0.005) ×10-2m [pic]=[pic] [pic]= [pic]=[pic]= 1.6×10-5 m2 Ball area= (7.980 +/- 0.016)[pic]m2 Ball mass = (3.30 +/- 0.05)[pic]kg [pic] Now F of air resistance equals the ball’s weight since it is just lifted above
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3. Given the following data: Job M1 M2 (processing times at machine 1 and 2) A 9 12 B 13 9 C 8 20 D 11 7 E 16 18 F 18 22 G 14 13 What is the minimum makespan? Answer: In order to find the minimum makespan for the two macines we can apply Johnson’sRule: Step 1: Look at the processing
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The Impact of Traffic on Indoor NO2 and PM10Contents at Shopping Malls by Chao Liu (1030400030) A Final Year Project Thesis (ENV4071; 3 Credits) submitted in partial fulfillment of the requirements For the degree of Bachelor of Science (Honours) in Environmental Science (Environmental Technology stream) at BNU-HKBU UNITED INTERNATIONALCOLLEGE DECLARATION I hereby declare that all the work done in this project is of my independent effort. I also certify that I have never
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depth before the jump is 1.0m. and downstream depth is 2m.‚ what is the discharge? Solution: The jet of a horizontal nozzle strikes a vertical plate with a force equal to 7000N. If the discharge flowing at the nozzle is 0.12 m3/s. Compute the diameter of the jet. Solution: A tank filled with water to a depth of 2.4m. is
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Materials Manganese ore‚ Metallurgical coke‚ Limestone & Quartz. Karnataka SEAC PPT For EC of Star Metallics & Power Pvt. Ltd. 3 PROJECT HIGHLIGHTS Contd……. Water requirement and Source 148 m3/ day‚ Tungbhadra dam reservoirs Effluent Generation & Disposal 46 m3/ day Gardening & dust suppression Source of power GESCOM Grid (It is used to run 15‚000 MVA furnace only‚ untill the proposed CPP will not be operational) Karnataka SEAC PPT For EC of Star Metallics
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