CHAPTER 1: FLUID PROPERTIES LEARNING OUTCOMES At the end of this topic‚ you should be able to: Define Fluid State differences between solid and fluid Calculate common fluid properties: i. Mass density ii. Specific weight iii. Relative density iv. Dynamic viscosity v. Kinematic viscosity INTRODUCTION Fluid Mechanics Gas Liquids Statics i F 0 F 0 i Laminar/ Turbulent Dynamics ‚ Flows Compressible/ Incompressible Air‚ He‚ Ar‚ N2‚ etc. Water‚ Oils‚ Alcohols‚
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May 2012 Master of Business Administration - Semester 2 MB 0048: “Operations Research” (4 credits) (Book ID: B1301) ASSIGNMENT- Set 1 Marks 60 Note: Each Question carries 10 marks. Answer all the questions. Marks 60 1. (a) What is linear programming problem? Ans: Linear programming (LP‚ or linear optimization) is a mathematical method for determining a way to achieve the best outcome (such as maximum profit or lowest cost) in a given mathematical model for some list of requirements
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School of Petroleum Engineering Design Project for Petroleum Engineers PTRL 3022 Group Report Mass & Energy Balances Group 3 Done by; Student No; Khalid Al-Abadi 3392461 Ahmed Al-Suleimani 3389102 Munther Al-Kalbani 3389087 Due date: 29/ 8/ 2012 Contents 1. Executive summary 2 2. Introduction 3 3. GOSP diagram 4 4. Gas Fractionation diagram 5 5. Three phase separation
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Sample 1 9.0 Project Scheduling Project scheduling is one of important part Software Development Project. This is because time is one of the aspects that should be concerned of when starting a project in order to meet the goal of project. IT Developer often failed to meet time constraints and choose to neglect time management to put more focus on development and other technical aspects. For this project we tried to apply project time management in order to ensure the tasks could be delivered
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Private Sector Participation in Solid Waste Management in Kathmandu Section Chief‚ Solid Waste Management Section Kathmandu Metropolitan City September 19‚ 2002 1.1 Overview of Kathmandu Kathmandu Valley‚ which provides the physical setting for Kathamndu Metropolitan City (KMC)‚ is situated between the latitudes 270 32’ 13” and 270 49’ 10” north and latitudes 850 11’ 31” and 850 31’ 38” east. It covers an area of about 667 sq. km and its mean elevation is about 1350m. above sea level
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Smog pollution in Beijing Smog pollution has been around since the start of industrialization‚ and there are many cities that suffer from its consequences. Among them‚ Beijing is singled out as the hotspot these days. In the past winter‚ an unprecedented amount of smog cloaked Beijing‚ filling the city with noxious air and causing convulsive coughing among the local residents. Not only does smog cause inconvenience in transportation by reducing visibility‚ but also‚ according to a study at
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FULL LAB REPORT I hereby declare that this report is written by me/us and it is my own/group effort and no part has been plagiarized without citations FACULTY OF MANUFACTURING ENGINEERING EXPERIMENT TITLE: MEASUREMENT WITH FLOWMETER GROUP NO: 02 SECTION: 02 NAME OF STUDENT NO ID 1. ALI ZULFAKAR BIN KHAIRUDIN FA12032 2. MOHD ZUL ASRI BIN MOHD RAMLI FB12011 3. MUHAMAD ASLAM BIN ABDUL RAUB FB12010 PRACTICAL DATE: 20 MARCH 2015 WEEK:04 SUBMISSION DATE (FULL REPORT): 27 MARCH 2015 WEEK:05
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Autonomic nervous system The autonomic nervous system (ANS or visceral nervous system) is the part of the peripheral nervous system that acts as a control system functioning largely below the level of consciousness‚ and controls visceral functions. The ANS affects heart rate‚ digestion‚ respiration rate‚ salivation‚ perspiration‚ diameter of the pupils‚ micturition (urination)‚ and sexual arousal. Whereas most of its actions are involuntary‚ some‚ such as breathing‚ work in tandem with the conscious
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Determine the sequent depth in a trapezoidal channel of 3 m width. The initial depth is 0.5 m. The side slope is 1:1. Initial flow velocity is 4 m/s. Solution: 0.5 1 1 3 A= (b+my)y (b+my)y ______________ b+2 Q = A.ν = = (3+0.5) 0.5*4 3.5 = *4 = 7 m3 /s 2 Q2 M1 = + zA gA = m2+1 y =R ⎛ 3*0.52 1*0.53 ⎞ +⎜ + ⎟ 3.5 ⎜ 2 3 ⎟ ⎝ ⎠ 9.81* 2 72 = 2.86 + 1.5*0.25 + 0.041666 = 3.2767m3 M1 =M 2 ⎛ 3*y 2 2 2 3 ⎞ +⎜ + y2 ⎟ ⎜ 2 ⎟ 3 ⎝ ⎠ Solve by trial and error y 2 = 1.05m. M1 = 72 9.81* ( 3+y 2 ) y
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REGENT COLLEGE BTEC Higher National Certificate in Business Assignment Brief Unit Number: Unit Title: 4 Marketing Principles BTEC Higher National Diploma in Business Unit 4: Marketing Principles Assignment Cover Sheet Assignment No: ............................................. I hereby confirm that this assignment is my own work. I have identified and acknowledged all sources used in this assignment and have referenced according to the Harvard Referencing system. I have read
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