SOLUTION MINING A Laboratory Exercise in Extracting Copper from a Synthetic Copper Ore Your Name __Mel Hine______________________ Partner’s Name __Jay Ranson____________________ Date _October 2‚ 2012____________ Introduction This laboratory exercise involves the use of dilute sulfuric acid (H2SO4) to leach copper
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The world has so many problems that seem unrealistic to fix; poverty‚ bullying‚ terrorism global warming it’s overwhelming. Most people believe that homelessness is one of those but they are wrong. The solution to homelessness is to put the homeless people in homes. Specifically foreclosed homes. The ratio of foreclosed homes to homeless people in the United States is about six to one. Every single homeless person in the United States could be housed in a foreclosed home and there would still
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Refining Solutions PHL/458 February 27‚ 2012 Refining Solutions When in search for a viable solution into refining ideas there are three main steps to follow. According to Vincent R. Ruggiero‚ the three steps to follow are to work out details by determining exactly how solutions will be applied. The next step is to examine each detail for imperfections‚ and the last step is to make any improvements that will eliminate the imperfections. In week two the original issue that was faced was
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BUFFER SOLUTION (ACID) An acidic buffer solution is simply one which has a pH less than 7. Acidic buffer solutions are commonly made from a weak acid and one of its salts - often a sodium salt. Objectives: 1. Measure the pH of the unknown solution first with indicators and then with pH paper. 2. compare the buffer solution with both a strong acid and a weak acid materials: 2 30 mL beakers 2 100mL volumetric flask 1 10mL pipet 2 aspirator 1 50mL graduated cylinder 1 10mL graduated
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Scenario Solution Jennifer Hinkley HSM/220 November 20‚ 2011 Ruth Anne Ristow Axia College of University of Phoenix More and more students are dropping out of high school each year. The need to obtain the funds to open up programs that will make sure that these former students can gain the educational skills they need for their future careers. Having an education will ensure that careers is kept. The plan will take a lot of work‚ understanding‚ and communication from all parties. The students
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5 Solution Preparation 1. Why should the solutions be prepared with 0.10M HCl used as solvent? a. What will happen to Fe3+ if the solution was not prepared using 0.10M HCl? b. Give the balanced equation for the 1st hydrolysis of Fe3+. c. What is the color of the product of 1st hydrolysis of Fe3+? d. What is the effect of the product of 1st hydrolysis to the absorbance of the solution? Determination of Analytical Wavelength 2. Why should the solution with
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Workshop Five-Ethical Solutions Paper Jackie Marshall June 19‚ 2013 Workshop Five-Ethical Solutions Paper The owner of a company reduced wages by 5% for all employees in 2010 due to the aftereffects of 9/11: an action that was necessary in order to save the company from financial ruin during a very turbulent economy. Since that time‚ no one within the organization has gotten a raise. However‚ the business has now stabilized‚ showing a net profit for the fourth quarter of 2011‚ all of
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BUFFER SOLUTIONS CONTENTS 1. Introductions. 2. Principles of buffering. 3. Applications a. Simple buffering agents. b. "Universal" buffer mixtures. c. Common buffer compounds used in biology. 4. Buffer capacity. 5. Calculating buffer pH a. Monoprotic acids. b. Polyprotic acids. 6. Biblography. INTRODUCTION A buffer is an aqueous
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A buffer solution can maintains a narrow range of pH even when strong acid are added. In our experiment‚ we can see water is not a buffer‚ water can undergo very big changes when small amounts of strong acid or strong bases are added. When the strong acid‚ 100µl HCl was added into the dd water‚ the pH value changed from 7.38 to 5.83 which mean the dd water has turn into acid. The same phenomenon occurs while strong base‚ 100µl NaOH was added into the dd water. The pH value changed from 7.07 to 9
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1.John is twice as old as his friend Peter. Peter is 5 years older than Alice. In 5 years‚ John will be three times as old as Alice. How old is Peter now? 2. John’s father is 5 times older than John and John is twice as old as his sister Alice. In two years time‚ the sum of their ages will be 58. How old is John now? 3. Joan is 3 times as old as her sister. In 3 yeas ‚ shee will be two years more than twice the age her sister will be then. What are their ages? 4. Kevin is 4 years older than
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