There are many types of stories. Of these stories‚ there are over 900 versions of Cinderella. But in this essay‚ I will only be talking about four of them. I will compare‚ contrast‚ and conclude those four versions called‚ “Yeh-Shen”‚ “The Algonquin Cinderella”‚ “Aschenputtel”‚ and “Interview” in this essay. One thing you probably didn’t know‚ is that these three stories are very old‚ which is something they all have in common. They also all have an element of magic. For example‚ Aschenputtel had
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EUREKA MATH – AFUHSD Mid-Module Review M1 ALGEBRA I Name Date 1. Jacob lives on a street that runs east and west. The grocery store is to the east and the post office is to the west of his house. Both are on the same street as his house. Answer the questions below about the following story: At 1:00 p.m.‚ Jacob hops in his car and drives at a constant speed of 25 mph for 6 minutes to the post office. After 10 minutes at the post office‚ he realizes he is late and drives at a constant speed of
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000‚00010‚ and that 1T = (1‚000‚00010 + d)2 8 bits/byte => 8 · 1 trillion or 812 => 8‚000‚000‚000‚000 3. Convert the binary number 1010110.1001 to decimal. 64 32 16 8 4 2 1 .5 .25 .125 .0625 1 + 0 + 1 + 0 + 1 + 1 + 0. 1 + 0 + 0 + 1 64 + 16 + 4 + 2 + .5 + .0625 = 86.5625 4. Convert the decimal number 1938.257 to hexadecimal. 1938 914 402 156 18 2 -1024 -512 -256 -128 64 32 -16 8 4 -2 1. 914 402 156 18
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CLICK TO DOWNLOAD MAT 540 Midterm Exam 1. Deterministic techniques assume that no uncertainty exists in model parameters. 2. A continuous random variable may assume only integer values within a given interval. 3. An inspector correctly identifies defective products 90% of the time. For the next 10 products‚ the probability that he makes fewer than 2 incorrect inspections is 0.736. 4. A decision tree is a diagram consisting of circles decision nodes‚ square probability nodes‚ and
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(2x – 5)(5 + 2x) (d) (9y - 8)(3y - 3) 4. Evaluate the following without using a calculator. (a) [pic]= (b) [pic]= (c) 8[pic]+[pic] = (d) 1[pic] = (e) 4[pic] = 5. Find expressions for the following algebraic functions‚ simplify the answers as far as possible. a) [pic] = b) [pic] = (c) [pic] = (d) [pic] = 6. Factor completely: x2 + 3xy – 154y2 = 7. Factor out the greatest common factor: 36x9y9 – 27x7y7 + 90x4y3 8. Simplify the complex function
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Quadratic Equations ax2 + bx + c = 0 Examples of Quadratic equations 1. x2 +2x – 8 = 0 2. x2 – 10x + 25 = 0 3. 3x2 + x - 2 = 0 Quadratic Formula If [pic] a x2 + b x + c = 0‚ then [pic] Finding the zeros of the quadratic functions - The zeros of a function are the input values which result in an output value of zero. One way of solving quadratic equations is using factoring Examples are the following: 1) x2 + 5x + 6 = 0 Set this equal to zero:
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Algebra Tile Lesson Reflection Although my students are in RSP‚ most have significant learning disabilities. Due to their special needs‚ the students have a difficult time performing above the ‘Far Below Basic’ level in most subjects‚ especially in Math. However‚ with the given opportunity to teach a math concept‚ I embraced it and learned from every aspect of the experience. During previous lessons‚ the students had learned about positive and negative integers. Using concrete and
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Catwoman There have been many versions of Catwoman’s origin over the years but details of her possible storyline suggested that Selina Kyle was born to Brian and Maria Kyle in the slums of Gotham City. Her mother was never close to Selina or her sister Maggie and would often rather spend time with her cats then her children. Her father was an abusive and drunken man who would always quarrel with Maria‚ a homemaker. In her spare time‚ Selina took gym lessons not just as an extra curricular but to
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Apparatus Material and Equipment: 0.00200 M KNCS‚ 0.00200 M Fe(NO3)3 0.200 M Fe(NO3)3‚ 0.10 M HNO3‚ 5 Cuvettes‚ 1 colorimeter 4 100ml beakers‚ 5 Test tubes 2 250ml Graduated cylinder. The first step is to calibrate the colorimeter with0.20 M Fe(NO3)3and set the absorbance at 470 nm since it is known to keep an acidic solution throughout the entirety of the experiment. It was important to do this right at the beginning of the lab since the zeroed value of the acid was the
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MA1506 TUTORIAL 1 1. Solve the following differential equations: (a) x(x + 1)y = 1 (b) (sec(x))y = cos(5x) (c) y = e(x−3y) (d) (1 + y)y + (1 − 2x)y 2 = 0 Use www.graphmatica.com to sketch the functions you found as solutions of [a]-[d]‚ if y = 1/2 at x = 1. Graphmatica can also directly sketch the graph if you insert the equation itself; for example‚ in [a] you just enter x(x + 1)dy = 1 {1‚ 1/2}. [curly brackets for the initial conditions‚ with x followed by y.] Here dy represents
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