using the tag provided. Unless otherwise stated in the question‚ all numerical answers should be given exactly or correct to three significant figures. clean copy of the Mathematics SL information booklet is required for this paper. A maximum mark for this examination paper is [90 marks]. The 11 pages © International Baccalaureate Organization 2013 0112 –2– M13/5/MATME/SP1/ENG/TZ1/XX Full marks are not necessarily awarded for a correct answer with no working. Answers
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assume that the growth rate of the tree is proportional to the difference between the maximum height and the current height‚ it is obviously not in conformity with the middle section of the growth process. We made a compromise assuming that the growth rate is proportional with both its current height and difference between the maximum height and the current height. Assumptions Assume that there is a maximum height of a tree can grow to‚ when this height is reached the tree will stop growing
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Our objective function calculates the maximum expected number of points scored in one game by optimizing the number of 2-point and 3-point shots attempted per quarter and using the average success rate for 2-point and 3-point shots. $k$ is a constant variable equal to the average number of points
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point on the curve y = 2x2– 6x – 4 at which the tangent is parallel to the x – axis 3. Find the slope of tangent for y = tan x + sec x at x = π/4 4. Show that the function f(x) == x3– 6x2 +12x -99 is increasing for all x. 5. Find the maximum and minimum values‚ if any of 6. For the curve y = 3x² + 4x‚ find the slope of the tangent to the curve at the point x = -2. 7. Find a point on the curve y = x2– 4x -32 at which tangent is parallel to x-axis. 8. Find a‚ for which f(x)
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performed on each day). 90 beds x 1.50 = 135 beds 135 beds x 7 days = 945 beds available in a week 945 beds / 3 days x 5 days in a week = 63 operations per day The hospital could perform a maximum of 63 operations per day if the beds are increase by 50%.
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------------------------------------------------- Q6. The drive shaft for a truck (outer diameter 60 mm and inner diameter 40 mm) is running at 2500 rpm (see figure Q6). (a) If the shaft transmits 150 kW‚ what is the maximum shear stress in the shaft? (b) If the allowable shear stress is 30 MPa‚ what is the maximum power that can be transmitted? Figure Q6. SOLUTION: Drive shaft for a truck ------------------------------------------------- Q7. A tubular shaft being designed for use on a construction
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Project Report Synopsis Name : Name Of The Programme : Post Graduate Diploma In Management (PGDM) Registration Number : Address For Correspondence : Email-Id : Name of the Project Guide Designation & Address : Title of the Project : “The study on sales promotion on tvs motors
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perform an experiment to determine the volume of water to use in order to obtain maximum height for the bottle rocket. Introduction Bottle rockets are often used in science as an experimental apparatus. Researchers use rocketry to understand the principles of Newton’s law of motion. This report will investigate‚ design‚ perform and analyse an experiment on water rockets and explain how a water rocket reaches a maximum height using the concept of physics and experimental results. Hypothesis If
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Jayanna k Lecturer: Electrical power Engineering Student name: Student ID: Power stations Page 1 Chapter 1 Load curves & its relevant factors Contents: 1.1 Analysis of Load curves 1.2 Important terms & Factors 1.2.1 Connected Load 1.2.2 Maximum demand 1.2.3 Demand Factor 1.2.4 Average Load 1.2.5 Load Factor 1.2.6 Diversity Factor 1.2.7 Plant Capacity Factor 1.2.8 Plant Factor 1.3 Problems on load curves & its factors References: [1] V.K. Mehta & Rohit Mehta‚ “Principles of Power System
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a trolley‚ which runs along the jib. The shorter horizontal machinery arm contains the crane’s motors and electronics as well as the large concrete counter weights. The Operator’s cabin is at the top of the tower.A typical tower crane can lift a maximum load of 18 metric tons‚ which is approximately 39700 pounds; however the crane cannot lift that much of weight if load is at the end of the jib. The closer the load is positioned to the mast‚ the more weight the crane can lift safely. 1) The long
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