Hydrogen peroxide and iodide ions Aim: To determine the rate equation for the reaction between Hydrogen peroxide and iodide ions‚ and to investigate the effects of a catalyst and temperatures on the reaction and to derive the activation enthalpy. Background knowledge: 1Hydrogen peroxide reacts with iodide ions producing iodine‚ when in an aqueous acid solution. H2O2 (aq) + 2I- (aq) + 2H3O+(aq) I2 (aq) + 2H2O(l) To detect iodine you can look at the color shown by the addition of starch
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Experiment 4: Developmental of an Equation Purpose While performing this lab‚ the student will learn how to determine the formula of the ionic solid produced from the reaction. Also‚ the student will learn to write the chemical equation corresponding to the reaction. Procedure Please refer to General Chemistry Laboratory Experiments‚ Volume 1‚ 2011‚ by Robert Tatz and Judith Casey‚ Exp 4‚ pages 32-33‚ for proper procedure. Data See attached sheet. Report Questions 1. The charge on an
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References: [2] J. Clerk Maxwell‚ A Treatise on Electricity and Magnetism‚ 3rd ed.‚ vol. 2. Oxford: Clarendon‚ 1892‚ pp.68-73. [3] I.S. Jacobs and C.P. Bean‚ “Fine particles‚ thin films and exchange anisotropy‚” in Magnetism‚ vol. III‚ G.T. Rado and H. Suhl‚ Eds. New York: Academic
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Introduction to Structural Equation Modeling (Path Analysis) SGIM Precourse PA08 May 2005 Jeffrey L. Jackson‚ MD MPH Kent Dezee‚ MD MPH Kevin Douglas‚ MD William Shimeall‚ MD MPH Traditional multivariate modeling (linear regression‚ ANOVA‚ Poisson regression‚ logistic regression‚ proportional hazard modeling) is useful for examining direct relationships between independent and dependent variables. All share a common format: Dependent Variable = Independent variable1 + Independent Variable2 + Independent
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Absolute values In an absolute value‚ everything with it is counted as a positive. ∣-a∣ = --a= a ∣a∣ =a In an equation‚ absolute values have two possibilities when talking about equations ∣a+b∣ =x = a+b=x = a+b= -x e.g. Solve ∣x-4∣=8 x-4=8 OR x-4= -8 x=12 x=-4 Sub both answer into the equation ∣12-4∣ =8 OR ∣-4-4∣ =8 8=8 8=8 Both solution re true so x=12 or x=-4 Absolute inequalities (method 1) If ∣a+b∣ ≤x∣a+b∣
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and continues the study of differential equations with the objective of introducing classical methods for solving boundary value problems. This course serves as a basis of the applications for differential equations‚ Fourier series and Laplace transform in various branches of engineering and sciences. This course emphasizes the role of orthogonal polynomials in dealing with Sturm-Liouville problems. 2. Text Book: Simmons G.F.‚ Differential Equations with Applications and Historical Notes
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Reflection is the change in direction of a wavefront at an interface between two different media so that the wavefront returns into the medium from which it originated. Common examples include the reflection of light‚ sound and water waves. The law of reflection says that for specular reflection the angle at which the wave is incident on the surface equals the angle at which it is reflected. Mirrors exhibit specular reflection. In acoustics‚ reflection causes echoes and is used in sonar. In geology
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EXPERIMENT : - 2 EXPERIMENT Verification of Bernoulli’s Energy Equation THEORY For steady incompressible flow Bernoulli’s energy equation along a streamline is written as [pic] constant where [pic] = pressure‚ [pic] = velocity and [pic] = height from datum Purpose of this experiment is to verify this expression. In the special apparatus the pipe is tapered with the cross section decreasing in the direction of flow first and then
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Consider a steady two-dimensional flow of Maxwell‚ Jeffrey and Oldroyd-B nanofluids over a cone having radius and half-angle . x-axis varies along the surface of cone and y-axis is perpendicular to it. The temperature and concentration distributions are vary along the surface of the cone. A variable magnetic field is applied along -direction as shown in Fig.1. A variable temperature along with the thermophoresis and Brownian motion effects are taken into account. and are the ambient temperature
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from now" is six times Miguel’s "age last year" or‚ in math: g + 3 = 6(m – 1) This gives me two equations with two variables: m + g = 68 g + 3 = 6(m – 1) Solving the first equation‚ I get m = 68 – g. (Note: It’s okay to solve for "g = 68 – m"‚ too. The problem will work out a bit differently in the middle‚ but the answer will be the same at the end.) I’ll plug "68 – g" into the second equation in place of "m": g + 3 = 6m – 6 g + 3 = 6(68 – g) – 6 g + 3 = 408 – 6g – 6 g + 3 = 402 – 6g
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