1 Quadratic Equations in One Unknown (I) Review Exercise 1 (p. 1.4) 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. Let’s Discuss Let’s Discuss (p. 1.23) Angel’s method: Using the quadratic formula‚ Ken’s method: Using the quadratic formula‚ Let’s Discuss (p. 1.30) The solution obtained by using the factor method is the exact value of the root. However‚ the solution obtained
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Answers: New GCSE Maths Edexcel Linear Homework Book Higher 2 1 Number: Using a calculator 1.1 Basic calculations and using brackets HOMEWORK 1A 1 a 195 b 300 2 a 28.08 b 48.18 3 a 24.5 b 38.3 c 326.9 d 11.3 4 14 days 5 Alfie 4.67; Becky 5.46; Chloe 6.14; Daniel 3.77 Daniel is correct. 6 75 Euros is approximately £65.79; $100 is about £67.11‚ so $100 is worth more 7 a 15.26 b 194.88 8 a 1.7 b 4.8 9 a 533.05 b 5.221096 1.2 Adding and subtracting fractions with a calculator
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monthly payments 2 d) Simultaneous equations: ( solving by elimination) Deposit = $350 Total monthly payments = 10 months x 120 By multiplying the second equation by 3‚ we get: = $1‚200 Total hire purchase price = 350 + 1200 = $1‚550 2x +3y = 9 9x – 3y = 24 By adding both equation we get: 11x = 33 so (x = 3) Q1.c (ii) Amount saved if laptop is purchased for cash of $1‚299 = 1‚550 – 1‚299 By substituting (x=3) into the first equation we get: = $251 2(3)+3y = 9
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Tutors Name: _____________________________________________________________ Tutorial Day: ________________________ Tutorial Time: _________________________ Mathematics 103‚ Semester 1 - 2013 MID-SEMESTER TEST 2 Question 1 Determine the equation of the line that passes through the points 2‚ 12 and 5‚ 6 . (3 marks) Question 2 Find the limit‚ lim → 2 3 2 (3 marks) Question 3 is on the next page… Mathematics 103‚ Semester 1 - 2013 MID-SEMESTER TEST 3 Question 3 If
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equivalent to the sum of the voltage drops in that loop. In other words‚ the algebraic sum of the voltages (Vk) in a closed loop is equal to zero (Eq 2). (Eq 2) Equations (1) and (2) are interrelated‚ and this can be demonstrated through modeling a basic electrical circuit involving a second order‚ linear differential equation. For our basic circuit‚ we will use a single closed loop involving one voltage source‚ one resistor‚ one capacitor‚ and one inductor. First‚ it is important to establish
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points chosen from all the data collected over the entire 200 seconds. As with the chart‚ it can be seen in the Absorption vs. time graph that light absorbed in the food coloring over time decreases. To find the concentration of the solution the equation for Beer’s law was used. Knowing A‚ є‚ and b‚ it was possible to solve for c and graph the points in the Concentration vs. time graph. This graph shows that over time the concentration of the food coloring is decreasing in the bleach. This function
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word FLUX roughly means FLOW. So based on this idea we can define the ELECTRIC FLUX as the ELECTRIC FEILD through a SURFACE AREA. Since the area vector is defined as perpendicular to the surface and the electric field goes through it‚ we define this equation as a dot product‚ similar to the work function. Φ E = E • A = EA cos θ dΦ = ∫ Eda A differential amount of flux is the cross product between the electric field and a differential amount of area. Since you want the total flux‚ you integrate to
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Maximum Marks : 100 Note : Question no. one is compulsory. Attempt any three questions from four. 1. (a) For what value of ’k’ the points ( - k + 1‚ 2 k)‚ (k‚ 2 - 2 k) and ( - 4 - k‚ 6 - 2 k) are collinear. (b) Solve the following system of equations by using Matrix Inverse Method. 3x+ 4y+ 7z= 14 2x-y+ 3z= 4 2x + 2y - 3z = 0 (c) Use principle of Mathematical Induction to prove that : 1 ± 1 ± 1x2 2x3 (d) 1 n (n+1) n+1 5 5 5 5 -‚ How many terms of G.P ‚[3 3‚ 3 /3 Add upto 39 + 13 BCS-012
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ABSTRACT The basic concept and operation of subsonic wind tunnel was demonstrated in this experiment by conducting airfoil drag analysis on a NACA 0015 airfoil. The small subsonic wind tunnel along with apparatus such as‚ the manometer rake‚ the inclined manometer and the pitot - static tube were used with different baffle settings to record varying pressure readings. To achieve this objective‚ some assumptions were made for the lower range of subsonic flow to simplify the overall analysis. From
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3 so f 0.484 We will use t d t dM (1 f ) and t dM from table 7.1 t dM‚D2O 4.3e 2; t dM‚Be 3.9e 3; t dM‚C 0.017 Then‚ t d‚D2O =0.022188sec;t d‚Be =2.0124e-3sec;t d‚C 8.772e 3sec 7.5 One‐delayed‐neutron group reactivity equation; lp 1 lp where 0.0065; 0.1sec1 1 lp For lp 0.0sec For lp 0.0001sec For lp 0.001sec Note:In this question examine the figure 7.2 and see that to give a constant period value ‚say
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