Methods We began this experiment by turning the Spectrophotometer to 605 nm absorbance‚ and setting up each of the tubes as stated in Table 7-2*‚ ignoring the DPIP until the rest of the sample was set up. Once all of the samples were set up accordingly‚ we blanked the spectrophotometer‚ and added the DPIP to the sample right before‚ inverting the sample and taking a reading at the Zero time mark‚ and placing the sample in the designated light apparatus‚ Sample 1 was wrapped in aluminum foil to
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cells‚ we must understand tonicity as the ability of a nearby solution to cause a cell to lose or gain water‚ depending on its concentration of non-penetrating solutes relative to solutes inside the cell (Reece et al. 133). The dialysis bags used in this experiment have membranes which are selectively permeable‚ which only allows particles specifically small enough to pass through (Carmichael‚ Grabe and Wenger). In a hypotonic solution‚ water
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Law‚ which is the linear relationship between absorbance and concentration of an absorbing species. Absorbance formula is shown in fig. 1.1. However‚ the Beer-Lambert Law is not obeyed at high concentration as solution with high concentration may alter the refractive index of the solution which in turn may affect the absorbance reading. The limitation of the Beer-Lambert Law is shown by the non-linear part of the graph in fig 1.2. The absorbance
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procedures each chemist must master to become proficient in the laboratory. Crystallization is based on the principles of solubility: compounds (solutes) tend to be more soluble in hot liquids (solvents) than they are in cold liquids. If a saturated hot solution is allowed to cool‚ the solute is no longer soluble in the solvent and forms crystals of pure compound. Impurities are excluded from the growing crystals and the pure solid crystals can be separated from the dissolved impurities by filtration. (orgchem
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lecture‚ you will be able to Define viscosity and viscosity coefficient Outline the method to measure viscosity using Ostwald viscometer Determine the average molecular weight of a polymer Determine the surface concentration of 1-butanol in aqueous solution Measure the distribution coefficient of a solute betweenn two solvents 39.1 Introduction Viscosity‚ one of the transport properties‚ arises because of intermolecular attractive and relatively long-range forces. Viscosity coefficient ([pic])
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Research Question: Which salt solution caused the sailor to die? Hypothesis: If the sailor drank the 40% salt water solution‚ then would die sooner‚ because the high amount of salt causes more dehydration. Variables: Independent- Salt Solution Dependent- Mass of Potato Control- Tap Water Materials: •Tap Water (50 ml for each cup) •Salt •Beaker •3 cups •3 pieces of potato •Scale Procedure: Step 1: Gather Materials. Step 2: Weigh each potato separately on the scale and record weight
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during this process‚ water moves down its concentration gradient. A solution surrounding a cell is hypertonic if it contains more solute particles than the inside of the cell‚ and the water will move out of the cell into the surrounding hypertonic solution by osmosis. If the solution is hypotonic (containing fewer solute particles than the inside of the cell)‚ the water will move from the solution into the cell. When the solution is isotonic (the same concentration of solutes as the cell)‚ the cell
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Measuring the dependence of net mass gain in potato pieces on concentration of sugar solution By Jonas Kulikauskas Siauliai Didzdvaris Gymnasium Hypothesis: The more sugar in solution‚ the more potato mass will decrease. Aim: To see how potato mass will change at different concentration solution. Research question: How the mass of potato will change at different concentration solutions? Variables: Dependent: solution concentration. Independent: sugar concentration in potatoes. Controlled: time
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osmosis is due to the net movement of water from an area of low concentration to an area of high concentration. Because the tubes had different concentrations‚ certain tubes gained more mass than others. Solution A had 0.6 molarity which increased the amount of mass by 1.48 grams (15 % change). Solution B had 0 molarity and
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(serum‚ urine‚ chemical solution‚ etc.) contained in a solvent (diluent). A 1:10 dilution of serum was made by adding one part serum to nine parts diluent to make a total of ten parts. If 1.0 milliliter of serum is added to 9.0 milliliters of H20‚ a total volume of 10.0 milliliters is obtained. Therefore‚ the dilution is expressed according to the following equation. volume of serum/volume of solution = [1.0 mL serum ]/[1.0 ml serum + 9.0 mL H20] 1.0 mL serum/10 mL solution = 1:10 total This means
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