Estimating Price Elasticities with Theory-Based Priors Author(s): Alan L. Montgomery and Peter E. Rossi Source: Journal of Marketing Research‚ Vol. 36‚ No. 4‚ (Nov.‚ 1999)‚ pp. 413-423 Published by: American Marketing Association Stable URL: http://www.jstor.org/stable/3151997 Accessed: 22/07/2008 16:25 Your use of the JSTOR archive indicates your acceptance of JSTOR ’s Terms and Conditions of Use‚ available at http://www.jstor.org/page/info/about/policies/terms.jsp. JSTOR ’s Terms and Conditions
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Power System Fault Analysis 2.0 Introduction The fault analysis of a power system is required in order to provide information for the selection of switchgear‚ setting of relays and stability of system operation. A power system is not static but changes during operation (switching on or off of generators and transmission lines) and during planning (addition of generators and transmission lines). Thus fault studies need to be routinely performed by utility engineers (such as in the TNB). Faults
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SPHERICAL TRIGONOMETRY DEFINITION OF TERMS The sphere is the set of all points in a three-dimensional space such that the distance of each from a fixed point is constant. The fixed point and the given distance are called the center and the radius of the sphere respectively. The intersection of a plane with a sphere is a circle. If the plane passes through the center of the sphere‚ the intersection is a great circle; otherwise‚ the intersection is a small circle. A line perpendicular to
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------------------------------------------------- Spiral of Theodorus In geometry‚ the spiral of Theodorus (also called square root spiral‚ Einstein spiral or Pythagorean spiral)[1] is a spiral composed of contiguous right triangles. It was first constructed by Theodorus of Cyrene. ------------------------------------------------- ------------------------------------------------- [edit]Construction The spiral is started with an isosceles right triangle‚ with each leg having a length of 1
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304 IEEE COMMUNICATIONS LETTERS‚ VOL. 16‚ NO. 3‚ MARCH 2012 A Low Complexity MMSE for OFDM Systems over Frequency-Selective Fading Channels Tian-Ming Ma‚ Yu-Song Shi‚ and Ying-Guan Wang Abstract—Channel estimation is one of the key technologies in Orthogonal Frequency Division Multiplexing (OFDM) systems‚ which has received more and more consideration. A modified Minimum Mean Square Error (MMSE) is proposed and simulated by MATLAB over a frequency-selective fading channel. Comparing with
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A Social Networ k-Based Recommender System (SNRS) Jianming He and Wesley W. Chu Computer Science Department University of California‚ Los Angeles‚ CA 90095 jmhek@cs.ucla.edu‚ wwc@cs.ucla.edu Abstr act. Social influence plays an important role in product marketing. However‚ it has rarely been considered in traditional recommender systems. In this paper we present a new paradigm of recommender systems which can utilize information in social networks‚ including user preferences‚ item’s general acceptance
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Class XII Chapter 3 – Matrices Compiled By : OP Gupta [+91-9650 350 480 | +91-9718 240 480] Maths Exercise 3.1 Question 1: In the matrix ‚ write: (i) The order of the matrix (ii) The number of elements‚ (iii) Write the elements a13‚ a21‚ a33‚ a24‚ a23 Answer (i) In the given matrix‚ the number of rows is 3 and the number of columns is 4. Therefore‚ the order of the matrix is 3 × 4. (ii) Since the order of the matrix is 3 × 4‚ there are 3 × 4 = 12 elements in it. (iii)
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Geometry Final Exam Review #1 Semester 2 Name:________________________ Hour:_______ GEOMETRY SEMESTER 2 FINAL REVIEW #1 1. The ratio of the side lengths of ΔOMN to ΔHGI is 4:3. Find x and y. 2. Find f. 3. The triangles are similar. Which choice below is NOT a correct statement? (A) B F (B) ΔBAC~ΔFDE BA FE (C) BC FD AC BC (D) DE FE (E) A D 4. Which of the following statements is not true? (A) ΔABC ~ ΔEDC by SAS~ (B) ΔABC ~ ΔEDC by AA~ (C) ΔABC ~ ΔEDC by SSS~ (D) ΔCDE ~ ΔCBA by SAS~
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QUADRATIC FUNCTIONS (WORD PROBLEMS) 1. The area of a rectangle is 560 square inches. The length is 3 more than twice the width. Find the length and the width. Representation: Let L be the length and let W be the width. The length is 3 more than twice the width‚ so The area is 560‚ so Equation: Plug in and solve for W: Solution: Use the Quadratic Formula: Since the width can’t be negative‚ I get . The length is 2. The hypotenuse of a right triangle is 4 times the smallest side. The third
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Contents 1. RYBCZYNSKI THEOREM ............................................................................................................................. 3 1.1 Theorem: ............................................................................................................................................. 3 1.1.1 Graphical Proof ............................................................................................................................ 3 1.1.2 Mathematical Proof .........
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