Respiratory system: Minute ventilation is the quantity of oxygen which is taken in by your lungs per minute. When we exercise there is a higher oxygen intake per minute due to a higher breathing rate‚ we will also need more oxygenated blood cells to go round to the muscles in use to help try and prevent muscular injuries. The reason why when minute ventilation increases is positive to an athlete is because there is a higher intake of oxygen and nutrients needed. This will mean that the athlete
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Respiratory Rate and Tidal Volume [pic] The total amount of air moved in and out of the lungs each minute (pulmonary ventilation) depends upon 2 factors: size of each breath (tidal volume) and number of breaths/minute (respiratory rate). For example‚ suppose your tidal volume is 500 mL (0.5 liters) and you breathe 15 times/minute. Your pulmonary ventilation = 15 breaths/min x 0.5 L/breath = 7.5 L/min. Pulmonary Ventilation = (Respiratory rate; breaths per minute) x Pulmonary Ventilation
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be an increase in the subject’s minute ventilation. The rise in minute volume‚ with exercise‚ could be accomplished by increasing the volume of each breath‚ the tidal volume‚ increasing the respiratory rate or by some combination of the two. In the subject’s case it was a combination of the two. Tidal volume is more effective at increasing minute ventilation than respiratory rate‚ however‚ if a subject is unfit they will be required to increase their respiratory rate as they cannot breath as deeply
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1-2 page analysis on how would you react to the changes in the fastener / attaching industry. What corrective steps should ML take to face the Japanese competitor? Changes in the Fastener/Attaching Industry: 1. Japanese entrant in the European market M/s Hiroto Industries‚ sold fasteners at price 20% less than that of Muller Lehmkuhl‚ with same quality products. 2. ML offered fasteners which were compatible to assemble only with their attaching machines‚ but Hiroto Industries manufactured
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of mass and volume. The ratio of the mass per unit volume is density‚ d and is written as (D = m/v). Using the metric system‚ the ratio for solids and liquids is expressed in g/mL or g/cm. Matter expands and contracts according to temperature. For liquids and solids‚ the change in volume is very small‚ but for gases‚ a temperature results in a proportional change in the volume. Therefore‚ gas density is dependent upon temperature; for liquids and solids‚ the small effect on volume is often ignored
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Acid –Base Titration: A volume of 128 mL of 0.650 M Ba(OH)2 was required to completely neutralize 50.0 mL of nitric acid solution (HNO3). What is the concentration of the acid solution? Gravimetric Titration: Calculate the molar concentration of Ba2+ ions in a 500.0 mL sample of an unknown aqueous solution if 2.47 g BaSO4 is formed upon the addition of excess Na2SO4? Stoichiometry of Acid –Base Reactions: What volume of 0.800 M HCl is required to completely neutralize 35.0 g of Ca(OH)2
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Merlyn Larrondo Period 5 ENC 1101 10/13/14Alan Turning Knowledge for the World Math genius‚ World War II hero and Father of Artificial Intelligence‚ get’s arrested in Manchester England‚ 1954. Alan reports to police in England that it appeared to him that things in his home such as shirts‚ pants‚ and sweaters were missing but nothing big of value. As the police arrive to Alan’s apartment‚ detectives interview him and put his ideas together as they realize that the thief behind this robbery
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be evolutionary adaptations allowing the elephant to remain underwater for long periods of time while breathing through its trunk which emerges as a snorkel.[4] Birds The main section for this topic is on the page Bird anatomy‚ in the section Respiratory system. The respiratory system of birds differs significantly from that found in mammals‚ containing unique anatomical features such as air sacs. The lungs of birds also do not have the capacity to inflate as birds lack a diaphragm and a pleural cavity. Gas
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Teflon ball 50 mL graduated cylinder 100 mL graduated cylinder 50 mL beaker Electronic balance Calcaulator Water Ammonium sulfate Step: Part 1.Measurment of the density of a solid 1. Three metal objects were selected for density determination: a metals‚ and Teflon ball. 2. Make sure each object was determined by weighing on an electronic balance. 3. Add 25 mL of water to the graduated cylinder. Precisely measure this volume of water. Add another 25 mL of distilled water
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100 mL of a new solution of each solute based on having as much of the initial solution as you need. V1 M1 V2M2 SoluteFormula of SoluteInitial Concentration (M)Final Concentration (M)Recipe For 100 mL of New SolutionSodium hydroxideNaOH1.0 M0.27 M(1.0M)(VNaOH) (0.27 M)(100 mL) VNaOH 27 mL Dilute 27 mL of 1.0 M NaOH to 100 mL.Potassium permanganateKMnO41.0 M0.34 MDilute 34 mL of 1.0 M KMnO4 to 100 mL.Copper (II) sulfateCuSO41.0 M0.25 MDilute 25 mL of 1
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