Nailea Rosales Chemistry THE GAS LAWS LAB LAB 1 Pressure in kPa Volume in ml Dataset 1 30 90 Dataset 2 35 80 Dataset 3 40 75 Dataset 4 45 70 Dataset 5 50 60 Dataset 6 60 50 LAB 2 New temp. in Celsius New Volume in ml Dataset 1 5 47 Dataset 2 10 48 Dataset 3 15 49 Dataset 4 20 50 Dataset 5 25 51 Dataset 6 30 52 1. Describe the relationship that you observed between pressure and volume in this lab. Refer to your data and/or graph to help support your answer. I observed that the higher the pressure
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INTRODUCTION Gas exchange is the movement of respiratory gases across a membrane through diffusion. Diffusion is the process of which the respiratory gases across the gas exchange membrane (oxygen from the environment into the body‚ carbon dioxide from the body to the environment). Using the concentration gradient along the gas exchange surface. For gas exchange to occur these three Features are needed; the gas exchange surface needs to be moist so that the oxygen and carbon dioxide can dissolve
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This report will cover the adaptations relating to gas exchange in insects‚ fish and mammals. These all have different gas exchange systems but work in similar ways. All the animals studied have the same characteristics in order for them to be able to work properly. Overview The gas exchange system is the process in which oxygen enters the cells of many living animals. Some factors that affect how efficient a gas exchange system is are things such as the distance that the molecules have to go before
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Review Sheet for Gas laws Name ___________________________ 1. A gas at 2.3 atm occupies 12 liters. The volume is changed to 6 liters what is the resulting pressure? 2. A sample of gas is confined to 30ml at a pressure of 6 atmospheres. When the pressure is changed to 3liters‚ what is the resulting pressure? 3. A gas occupies 30 L. When the gas is heated from 50C to 100C‚ what is the final volume? 4. In a lab‚ Neon vapor occupied a volume of 1 liter at STP‚ the volume was changed to 4 liter
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Chemistry 1110 Molar Mass of Butane Materials * Butane Lighter * Plastic Tube * 100 ml Graduated Cylinder * 2 Thermometers * Barometer * Sink Full of Water Purpose The purpose of this experiment is to determine the molar mass of butane using Dalton’s Law of Partial Pressures and the ideal gas law. Hypothesis My hypothesis is that as we complete the experiment‚ we will be able to correctly use the air and water temperatures‚ volume of gas‚ and barometric
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during the lab. Data Set Pressure in kPa Volume in mL 1 150 20 2 100 30 3 75 40 4 60 50 5 45 60 6 40 70 Graph: [10 points] Create a graph of your data for this part of the lab. You may use any graphing tool to create the graph‚ but be sure to follow common guidelines for creating a graph. INSERT GRAPH HERE Conclusion: Answer the following questions after completing the lab. 1) Describe the relationship that you observed between pressure and volume in this lab. Refer to
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In Parts A and C‚ the relationship between surface area and volume was investigated. Plasticine was formed into a cube and a sphere; both shapes were cut in half. It was found that plasticine volume should not vary‚ two halves have a greater surface area than a whole‚ and cubes have a greater surface area than spheres of the same volume. In Part B‚ the relationship between diffusion and surface area to volume ratio was investigated. Three agar-phenolphthalein-sodium hydroxide cubes of different sizes
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substance. Here is a tutorial for an over view and for a reference as you work through these problems http://www.wiley.com/college/chem/spencer053872/tutorial/gramsmoles/gramsmoles1.html We can use this to do mathematical conversions to determine mass‚ volume‚ and number of atoms or molecules in a given substance. For example let’s check out this video to convert moles methane (CH4) to grams of methane. http://www.sciencegeek.net/Chemistry/Video/Unit4/GMV2.shtml Once you have finished the video let’s
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10-3 mol 3. Molar mass – mass in grams of one mole of a substance. Example 3-5 page 76 4.62 g Na3PO4 Molar Mass Na3PO4 = (22.9898 gNa X 3) + (30.9738 gP) + (15.9994 gO X4) = 163.9408 g per mol Na3PO4 Moles Na3PO4 = 4.62 g X 163.9408 g/ mol = 2.818 X 10-2 mol Na3PO4 Moles Na = 2.818 X 10-2 mol Na3PO4 X 3 mol Na / mol Na3PO4 = 8.45 X 10-2 mol Na Na+ ions = 8.45 X 10-2 mol Na X (6.022 X 1023) = 5.08 X 1022 ions C. Solutions and Their Concentrations 1. Molar Concentration
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Determination of the Molar Mass of Volatile Liquids Theory: Molar masses‚ can be seen and used daily in chemistry. In this lab‚ the ideal gas law helps determine and evaluate the molar mass of gases and volatile liquids. The ideal gas law compares four properties of a gas which include pressure‚ volume‚ moles‚ and temperature. During this experiment‚ the moles would be unknown‚ in effect the student must use a substance mass divided by its molar mass. With this‚ the ideal gas law can be arranged
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