by the direct titration of a filtered solution with a standard sodium hydroxide solution‚ since it is a slightly soluble salt. Because one mole of sodium hydroxide neutralizes one mole of HT- ions‚ the number of moles of sodium hydroxide used in the titration will equal the number of moles of HT-. The concentration of HT- can be determined by dividing its moles by its volume. The concentration of HT- will be equal to the concentration of K+‚ which in turn will be equal to
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demonstrate the basic laboratory technique of titration 2. To learn to calculate molarity based on titrations INTRODUCTION Molarity (M) or molar concentration is a common unit for expressing the concentration of solutions. It is defined as the number of moles of solute per liter of solution (or millimoles of solute per milliliter of solution). The concentration of a basic solution can be determined by titrating it with a volume of a standard acid solution (of known concentration) required to neutralize
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150g Mass of weigh boat (g) .500g Mass of weigh boat + oxalic acid (g) 3.662g Mass of oxalic acid (g) 3.162g Concentration of 100.00ml .2510M Table 2: NaOH Mass of NaOH + weigh boat 11.336g Mass of weigh boat .500g Calculated mass of NaOH 10.836g Moles of NaOH .2709mol Concentration of 500.0ml NaOH .5418M Table 3: HCl Volume of Concentrated HCl 10.00mL Concentration diluted to 250.00ml .5475M Table 2: Volume of NaOH needed to neutralize 10.00 mL of oxalic acid Trial 1 Trial 2 Initial reading
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using the mole concept. Limiting Reactant: It is the reactant that will deplete or will be used up first during a chemical reaction. Limiting reactant also determine how long the reaction will last for. Balanced Equation: Mg + 2HCl = MgCl2 + H2 The balanced equation is needed to determine the mole ratio between the two reactants. From the equation we know that the equation mole ratio is 1:2. However‚ we need the actual mole ratio to find out the limiting reactant. The actual mole ratio is
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out who a suspected mole is in “the Circus” (British Intelligence Headquarters in London). Through the flashbacks‚ stories that nestle within stories‚
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the reaction has taken place. Therefore‚ the idea is that 50 cm³ of sodium thisoulphate are made to react with 5 cm³ of hydrochloric acid that is of different concentration each time. The concentrations of hydrochloric acid used varied from 0.1 to 5 moles. Afterwards‚ the cross is observed through the top of the conical flask until it because invisible. The time of which this happens is then recorded and monitored using a stopwatch. The symbol equation of this reaction is as follows: The above
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Equilibrium Constant of an Unknown Ester Hydrolysis Reaction Abstract The experiments to follow determined that the equilibrium concentrations of the reaction: ester + water ↔ alcohol + acid‚ are equal to 0.0363 moles of ester‚ 0.2852 moles of water‚ and 0.0268 moles each of alcohol and acid. Using this information the equilibrium constant was determined to be 0.06938. 1. Introduction In this lab the equilibrium constant‚ Kc‚ for the acid catalyzed reaction between an unknown
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T = R = 1. What pressure is required to contain 0.023 moles of nitrogen gas in a 4.2 L container at a temperature of 20.(C? 2. Oxygen gas is collected at a pressure of 123 kPa in a container which has a volume of 10.0 L. What temperature must be maintained on 0.500 moles of this gas in order to maintain this pressure? Express the temperature in degrees Celsius. 3. How many moles of chlorine gas would occupy a volume of 35.5 L at a pressure of 100
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of ZnCI2. As well titrating with NaOH solution. After all the experiment we got hta salt witch we weighted and we got our results. Experiment reactions: .33w of Zn(OH)2 x moles Zn(OH)2/m. moles Zn(OH2) x 1molZnCI2/1 mol Zn(OH)2 x g molZnCI2/1 mol of ZnCL2 = .4531 grams of ZnCI2 .4531g of ZnCl2 x 1 moles ZnCI2/m. moles ZnCI2 x 1molZn/1 mol of ZnCI2 x 65.39 of Zn/1 mol Zn = .2174g Zn Materials needed: Scale Burette Beaker Spatula Erlenmeyer flask Prenolpthen (color indicator) ZnCL2
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Questions: 1. One mole of a compound A‚ with vapor pressure 400mmHg at 50oC‚ mixed with 3 moles of compound B‚ with vapor pressure 480mmHg at 50oC to form a homogeneous solution. What is the vapor pressure of mixture at 50oC? XA =moles of A\total No. of moles XA =1\4 XB=3\4 Ptotal=PAoXA+PBoXB =400*1\4 + 480*3\4 = 460mmHg 2. Why should a distilling flask be filled not less than 1\3 filled or more than 2\3 full? This is to allow the liquid being heated room to expand as it turns
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