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    Mole Ratios Lab

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    Drew Moyer Mrs. Haire IB Chemistry Experiment 6 Mole Ratio in a Chemical Reaction Background: Mole ratios of reactants are often times figured out by the use of the other products in a chemical equation. However‚ in the instance that the products’ mole ratios are unknown‚ it can be determined through the experiment. This method is called continuous variations. In this lab‚ I determined the mole ratio between Sodium Hypochlorite and Sodium Thiosulfate by using continuous variations of ratios

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    In this lab‚ theoretical chemical equations of ionic compounds were balanced by the group to determine ratios of reactants and products. The products were determined by the group through switching the cation with their anion partner. Using this information‚ it was determined by the group‚ whether the reaction should result in a solid‚ gas‚ or water based on theoretical solubility. Then several experiments testing the reaction of these ionic compounds were performed by the partners. Two ionic compounds

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    Chlorine and Mole Ratios

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    Answer to Practice Problem #1: 1. Balance your equation first. 2KClO3 (s) --> 2KCl (s) + 3O2 (g) [balanced] 2. Convert from grams to moles using molar mass. To get moles from grams of potassium chlorate (KClO3): [molar mass = 122.55 g/mol] 138.6 g KClO3 X ( 1 mol / 122.55 g ) = 1.131 mol KClO3 3. Determine the limiting reagent [if necessary] (Use mole ratios to figure out.) *

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    Reagent and Mole Ratio

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    of Chemical Reactions Objective In this lab we took Fe(NO3)3 and NaOH and mixed 7 different mole ratios in graduated cylinders to determine what the mole ratio is. We also did the same thing with solutions of CuCl2 and Na3PO4. We determine the mole ratios by graphing the volume of reactant #1 vs. volume of precipitate for each reaction. Data Part 1.) Cylinder 1 2 3 4 5 6 7 Fe(NO3)3‚ 0.1 M‚ ml 5 10 12 15 17 20 24 NaOH‚ 0.1 M‚ ml 55 50 48 45 43 40 36 Fe:OH mole ratio

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    an underlying purpose in determining the relationship between moles evolved and consumed. This can be demonstrated by measuring the hydrogen gas evolved by performing a chemical experiment when hydrochloric acid reacts with the magnesium. The formulated reaction includes; Mg + 2HCl → H2 + Mg2+(aq) + 2Cl- (aq) The major findings contributing to the experiment is being able to determine and distinguish what moles have evolved thus being the hydrogen moles evolved allowing the magnesium to be consumed

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    numericals on mole concept

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    1 mole of any substance can be defined as: Amount of a substance that contains as many particles (atoms‚ molecules or ions) as there are atoms in 12 g of the 12C isotope Avogadro number or Avogadro constant (NA); equal to 6.022 × 1023 particles Example − 1 mole of oxygen atoms = 6.022 × 1023 atoms 1 mole of carbon dioxide molecules = 6.022 × 1023 molecules 1 mole of sodium chloride = 6.022 × 1023 formula units of sodium chloride Molar mass of a substance can be defined as: Mass of one mole

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    S. 5.2 – The Mole The mole: - - - - Ex. - Molar mass (g/mol): - - - Ex. |Element |Atomic mass shown on Periodic |Molar mass of element | | |table | | |N |14.0067 |14.0067 g

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    Equation of State

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    Equations of State (EoS) Equations of State • From molecular considerations‚ identify which intermolecular interactions are significant (including estimating relative strengths of dipole moments‚ polarizability‚ etc.) • Apply simple rules for calculating P‚ v‚ or T ◦ Calculate P‚ v‚ or T from non-ideal equations of state (cubic equations‚ the virial equation‚ compressibility charts‚ and ThermoSolver) ◦ Apply the Rackett equation‚ the thermal expansion coefficient‚ and the isothermal compressibility

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    balancing equations

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    Balancing Equations Balancing equations is a fundamental skill in Chemistry. Solving a system of linear equations is a fundamental skill in Algebra. Remarkably‚ these two field specialties are intrinsically and inherently linked. 2 + O2 ----> H2OA. This is not a difficult task and can easily be accomplished using some basic problem solving skills. In fact‚ what follows is a chemistry text’s explanation of the situation: Taken from: Chemistry Wilberham‚ Staley‚ Simpson‚ Matta Addison Wesley

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    Mole Formula Lab

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    Shawn Dubbs Lab 1 The Mole Concept of and the Chemical Formula of a Hydrate Abstract: The objective of this lab was to conduct an experiment to analyze the molar components in alum. This was conducted by heating the alum till the water had evaporated and then determining the number of moles for each component. Then using the these amounts to figure out the empirical formula for alum. Results: In order to determine how much of each separate component a total mass was taken before hand for

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