1 AND 2 STEP MOLE CONVERSIONS – MORE PRACTICE 1. How many moles does 80.0 grams of H2O represent? 2. How many moles does 45.0 grams of C6H12O6 represent? 3. How many moles does 22.0 grams of CO2 represent? 4. How many moles does 56.0 grams of N2 represent? 5. What is the mass of 2.0 moles of LiOH ? 6. What is the mass of 5.0 moles of Ba(CN)2 ? 7. What is the mass of 3.5 moles of water? 8. What is the mass of 0.75 moles of CuSO4 ? 9. How many atoms does 2.0 moles of He represent? 10. How
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Photocatalytic degradation of methylene blue using TiO2 nanoparticles Nupur Mittal Chemical Engineering‚ IIT (BHU) Varanasi. Abstract: The aim of this research is to reduce the pollution caused by methylene blue dye in waste water coming from textile industries. For this purpose‚ TiO2 nanoparticles are made as they show good photocatalytic activity in degradation of dyes into harmless products. Synthesis is done using titanium butoxide and 2-propanol. The particles formed were a little larger
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LEARNING TASK NO. 4B Composition Stoichiometry Problems Mole Relationship from Chemical Formulas: a) Determine the number of moles of chloride ions in 2.53 mol ZnCl2. b) Calculate the number of moles of each element in 1.25 mol glucose (C6H12O6). c) How many molecules of oxygen atoms are present in 5.00 mol diphosphorus pentoxide? d) Calculate the number of moles of hydrogen atoms in 11.5 mol water. e) A sample of ethanol (C2H5OH) has a mass of 45.6 g.How many carbon atoms does the sample
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Formula Sheet for the Corporate Finance Final Examination Paper 1. r = cost of capital t = year 2. Pure Play approach bL = bU[1 + (1 – T)(D/E)] bL = levered beta bU = unlevered beta T = tax rate D/E = debt to equity ratio 3. Firm value Rs = Cost of equity G = cash flow growth rate 4. rRF = the risk-free interest rate RPM = the expected market risk premium on an average stock = rM – rRF rM = the expected return on the market portfolio
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Problem: Reference : Kasavana Brooks‚ 5th Edition‚ Pg. 351 Hubbart Formula Approach‚ Room Pricing The Casa Vana Inn‚ a 200 room property‚ is projected to cost $9‚900‚000 inclusive of land‚ building‚ equipment‚ and furniture. An additional $100‚000 is needed for working capital‚ bringing the total cost of construction and opening to $10‚000‚000. The hotel is financed with a loan of $7‚500‚000 at 12% annual interest and cash of $2‚500‚000 provided by the owners. The owners desire a 15% annual return
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Metering Formula 1. Meter Multiplier Meter Multiplier - the multiplier applied to the register reading to obtain kilowatt-hours. M = Kh X Rr X Rs X CTR X VTR 10‚000 Where ; Kh = watt-hour constant of the meter in watt-hour per revolution Rr = register ratio = the number of revolutions of the register worm wheel for a revolution of the first dial pointer (right hand). Rs = gear ratio = the number of revolution of the disk for one revolution of the first point CTR = current transformer
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Assets = Liabilities + Shareholders’ equity Revenues – Expenses = Income Cash flow from assets = Cash flow to bondholders + Cash flow to shareholders Current ratio = Current assets/Current liabilities Quick ratio = Current assets – Inventory Current liabilities [2.1] [2.2] [2.3] [3.1] [3.2] [3.3] [3.4] [3.5] [3.6] Cash ratio = Cash/Current liabilities Net working capital to total assets = Net working capital/Total assets Interval measure = Current assets/Average daily operating costs Total
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Mole catcher by: Sam winters A mole catcher is a spy in the war. The second Continental congress created a Secret committee by a resolution on september 18‚1775. The committee was not a true intelligence agency. Since the committee of secret correspondenceoften worked was mainly concerned with obtaining military supplies in secret and distrubting them‚ and selling gun powder previously negotiated by certain members of the congress without the formal sanction of that body.. the committee kept its
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find ‘’ in the formula CuSO4.H2O‚ we need to find the ratio of mole between anhydrous copper II sulfate and the water vapour by using the formula: In this case‚ the molar mass of: Copper II sulfate (CuSO4) is: 63.55 + 32.06 + 15.99 x 4 = 159.57 g/mol Water (H2O) is: 1.01 x 2 + 15.99 = 18.01 g/mol (e.g. 0.37/18.01= 0.02054 mol.) Then‚ is obtained by: Calculation 1st attempt 2nd attempt 3rd attempt Mole of water (mol) = 0.06163 Mole of anhydrous copper
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Formulas (to differential equations) Math. A3‚ Midterm Test I. sin2 x + cos2 x = 1 sin(x ± y) = sin x cos y ± cos x sin y tan(x ± y) = tan x±tan y 1∓tan x·tan y differentiation rules: (cu) = cu ′ ′ ′ ′ ′ (c is constant) cos(x ± y) = cos x cos y ∓ sin x sin y (u + v) = u + v (uv)′ = u′ v + uv ′ ′ ′ u ′ = u v−uv v v2 df dg d dx f (g(x)) = dg dx sin 2x = 2 sin x cos x tan 2x = sin x = 2 cos 2x = cos2 x − sin2 x 2 tan x 1−tan2 x 1−cos 2x ‚ 2 integration rules: cos x = 2
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