Calculation: Use Kepler’s Third Law (M=(4π^2 r^3)/(GP^2 )) to calculate the mass of “Object X” from the orbit of its moon—whose orbital radius (r) is 64‚780 kilometers and whose orbital period (P) is 38.200 days—and knowing that the gravitational constant G= 6.673×〖10〗^(-11) m^3 〖kg〗^(-1) s^(-2)(where m= meters‚ kg= kilograms‚ and s=seconds). Express the answer in units of Earth Mass (M_Earth)‚ knowing that M_Earth= 5.980×〖10〗^24 kg. (Hint: first express r and p in standard units: meters and seconds
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LINEAR ALGEBRA Paul Dawkins Linear Algebra Table of Contents Preface............................................................................................................................................. ii Outline............................................................................................................................................ iii Systems of Equations and Matrices.............................................................................................
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students lack understanding of mathematical language and show weakness in basic numerical computation. The students make frequent errors because they misread operation signs when adding or subtracting integers or carry numbers incorrectly when multiplying whole number and decimals. Furthermore‚ these students have difficulty understanding written or verbal directions or explanations‚ and find word problems especially difficult to translate. Current Conditions The current data shows that only
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centimeters. Likewise‚ dividing one meter into one hundred units means memorizing that “centi” is the prefix for “hundred” and acquiring one hundred “centimeters.” Just converting from an inch to a mile means multiplying an inch times twelve to get a foot‚ multiplying that by three to get a yard‚ and multiplying that by 1‚780 to get a mile. Also‚ the US customary system was based on a medieval English system that does not change with the advancements in science and math that needs units for measurement. Meanwhile
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6‚367‚500m but would be increased to 6367530m if the polar ice caps melting caused sea levels to rise 30m)‚ T equals the length of a day which is approximately 86400 seconds. Using these numbers the new length of a day would be calculated by multiplying 63675302 (the estimated new radius of earth after the melting of the polar ice caps) by 86400 (approximate length of current earth day in seconds) and dividing this number by 63675002 (the current radius of the earth) which equals 86400.8 an increase
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| A Brief History of MathematicsPeople seem compelled to organize. They also have a practical need to count certain things: cattle‚ cornstalks‚ and so on. There is the need to deal with simple geometrical situations in providing shelter and dealing with land. Once some form of writing is added into the mix‚ mathematics cannot be far behind. It might even be said that the symbolic approach precedes and leads to the invention of writing.Archaeologists‚ anthropologists‚ linguists and others studying
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The Finite Element Method This page intentionally left blank The Finite Element Method An Introduction with Partial Differential Equations Second Edition A. J. DAVIES Professor of Mathematics University of Hertfordshire 1 Great Clarendon Street‚ Oxford ox2 6dp Oxford University Press is a department of the University of Oxford. It furthers the University’s objective of excellence in research‚ scholarship‚ and education by publishing worldwide in Oxford New York Auckland Cape Town Dar es Salaam
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coefficients for a linear relation c = bo + b1 d and plot the equation obtained together with the data. NOTE: It is recommended to use a spreadsheet program (Excel) to solve this problem Problem #2: Heat capacities are usually given in terms of polynomial functions of temperature. The equation for carbon dioxide is: C p = 8.4448 + 0.5757 *10 −2 T − 0.2159 *10 −5 T 2 + 0.3059 *10 −9 T 3 where T is in °F and Cp is in BTU/(lb mol) (°F). Convert the equation so that T can be in °C and Cp will be in
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This hypothesis was supported in the data recorded and final graph shown above. The final graph has a polynomial trendline‚ which has a resemblance trend as the graph in the hypothesis section. Moreover‚ it has shown that the highest temperature (39 OC) had the greatest rate of cellular respiration and comparatively lower rate at 19 OC. By theory‚ temperature
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Vectors in Two Dimensions‚ Mathematics in Practical situation‚ Graphs in Practical Situations 4. Ten Years Series Additional Mathematics 1. Secondary Three Topics- Simultaneous Eqn‚ Surds Indices & Log‚ Quadratic Eqn & inequalities‚ Polynomials & Partial Fractions‚ The Modulus Function‚ Biomial Theorem‚ Coordinate Geometry‚ Linear Law‚ Trigo Functions 2. Secondary Four Topics- Simple Trigo Identities & Eqn‚ Further Trigo Identities‚ Differentiation‚ Rates of Change‚ Maxima & Minima
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