Name: Math Manisa No.: 10740 Project 2 Regression Line The following table shows (for the years 1965 to 2000 and for people 18 and over) the total percentage of cigarette smokers‚ the percentage of males who are smokers‚ and the percentage of females who are smokers. Percentage of Smokers _________________________________________________________________________________________________ Year Total Population All
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descriptions. a. g(x) = log( x + 5) horizontal left shift 5 Vertical asymptote x = -5 x-intercept: (-4‚ 0) b. g(x)=log(-x) over the x-axis vertical asymptote x=0 no x-intercept 3. Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The average score S(t)‚ in percent‚ after t months was found to be given by S(t) = 68 - 20 log (t + 1)‚ t ≥ 0. a. What was the average score when they initially took the test‚ t = 0? Round
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granted everyone in the class access to them. I would urge you to FIRST write them on paper‚ and THEN run them – just to be sure you understand them. You will not have access to Oracle SQL during the final exam. These take time‚ so please start early. I have granted you all access to query the tables in my account. You can access them by typing suebrown.‚ so to access the publishers table‚ type suebrown.publishers. As a second alternative‚ you can use the scripts in blackboard to create the tables
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value of r that minimizes this by taking the derivative‚ stetting it equal to 0‚ and solving for r. Use that to find h. You’ll find that the dimensions are different from an actual soda can‚ but I’m sure you can think of why this is the case. THE MATH PROBLEM: The surface area of a cylindrical aluminum can is measure of how much aluminum the can requires. If the can has a radius r and a height h‚ its surface area A and its volume V are given by the equations: A=2(pi)r^2 + 2(pi)rh and V=
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Math Exam Notes Unit 1 The Method of Substitution -Solving a linear system by substituting for one variable from one equation into the other equation -To solve a linear system by substitution: Step 1: Solve one of the equations for one variable in terms of the other variable Step 2: Substitute the expression from step 1 into the other equation and solve for the remaining variable Step 3: Substitute back into one of the original equations to find the value of the other variable Step
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Your Name: Jennifer Green MAT 205 Final Examination Your Score: of 250 points NOTE: You must show your work on each problem to receive full credit points allocated for each problem (excluding T/F questions) Write a matrix to display the information. 1) At a store‚ Sam bought 3 batteries‚ 15 60-watt light bulbs‚ 46 100-watt light bulbs‚ 8 picture-hanging kits‚ and a hammer. Jennifer bought 12 batteries‚ 3 100-watt light bulbs‚ and a package of tacks. Write the
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Maths Project Class 9 PROJECT WORK: Creative Mathematics Project Ideas General Guidelines: * Each student is required to make a handwritten project report according to the project allotted Please note down your project number according to your Roll Number. Roll Number | Project Number | 1-5 | 1 | 6-10 | 2 | 11-15 | 3 | 16-20 | 4 | 21-25 | 5 | 26-30 | 1 | 31-35 | 2 | 36-40 | 3 | 41-45 | 4 | 46-50 | 5 | * A project has a specific starting date and an end date. *
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Item 4B Item 4B Rachel Reiser Maths C Rachel Reiser Maths C Question 1 ab1+f’(x)2 dx y = acosh(xa) If: coshx=12ex+e-x Then: cosh(xa) = 12(exa+e-xa) y = acosh(xa) ∴ y=a(exa+e-xa)2 y=a(exa+e-xa)2 dydx=f’x=ddxa(exa+e-xa)2 dydx=f’x=ddx12aexa+e-xa f’x=12a1aexa+-1ae-xa f’x=exa-e-xa2 f’x2=exa-e-xa22 f’x2=(12exa-12e-xa)(12exa-12e-xa) f’x2=14e2xa-14e0-14e0+14e-2xa f’x2=14e2xa-12+14e-2xa f’x2=14e2xa-2+e-2xa Assuming the catenary is symmetrical‚ the entire length of
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MATH PORTFOLIO NUMBER OF PIECES Kanishk Malhotra 003566-035 (May 2012) In physics and mathematics‚ the ‘DIMENSION’ of a space or object is informally defined as the minimum number of coordinates needed to specify each point within it. Thus a line has a dimension of one because only one coordinate is needed to specify a point on it. A surface such as a plane or the surface of a cylinder or sphere has a dimension of two because two coordinates are needed to specify a point on it (for
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MATH OF INVESTMENT (FORMULAS AND SAMPLE PROBLEMS) SIMPLE INTEREST: a) I= Prt b) F= P+ I c) I= F- P d) F= P (1 + rt) e) P= F / 1+ rt f) R= I / Pt g) P= I / rt h) t= I / Pr i) EXACT INTEREST: j) k) Ie= Pr approximate time Ie= Pr exact time l) 365 days 360 days m) n) ORDINARY INTEREST o) p) Io= Pr exact time Io= Pr approximate time q)
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