CHAPTER 4 REACTIONS IN AQUEOUS SOLUTION MULTIPLE CHOICE QUESTIONS 4.1 Which of the following compounds is a strong electrolyte? E A. H2O B. O2 C. H2SO4 D. C6H12O6 (glucose) E. CH3COOH (acetic acid) Answer: C 4.2 Which of the following compounds is a strong electrolyte? E A. H2O B. N2 C. KOH D. C2H6O (ethanol) E. CH3COOH (acetic acid) Answer: C 4.3 Which of the following compounds is a weak electrolyte? E A. HCl B. CH3COOH (acetic acid)
Premium Electrochemistry Oxidizing agent Hydrogen
Allow the dish to cool in a desiccator because anhydrous sodium carbonate absorbs moisture to form the monohydrate. Weigh‚ then heat again for five minutes‚ cool and reweigh. Repeat this process until the mass is constant. Na2CO3 + 2HCl 2NaCl + H2O + CO2 Relative molecular mass of anhydrous sodium carbonate is 106. Mass of sodium carbonate for 250cm3 0.05 M solution is 0.25 x 0.05 x 106 = 1.325g Weigh a clean‚ dry weighing bottle and weigh our exactly 1.325g
Premium Sodium carbonate Carbon dioxide Sodium bicarbonate
neutralize the base? Answer(H2PO4- (aq) + OH- (aq) HPO4-2 (aq) + H2O (l) ) Question= Neutralization reactions typically occur between a strong acid and a strong base to produce a salt and water question When sodium carbonate (Na2CO3) dissolves in water‚ it partially ionizes. The carbonate (CO3-) ion takes up a hydrogen ion and forms HCO3-. What type of substance is sodium carbonate? Answer (weak base Questio Which of the following correctly describes the corrosive nature
Premium Acid PH Sodium hydroxide
for both teas by at least 40 ˚c. This indicates the impurity of the caffeine extracted with its tannins. Tannins are what give the caffeine its color‚ and when it is not isolated from the caffeine it creates a soluble salt in water when mixed with Na2CO3. The reason the melting point would be broader is because tannins decompose above temperatures of 200 ˚c‚ thus making the melting point higher. The results were obtained‚ the final mass of the caffeine for the black tea was 91.6 mg‚
Premium Water Acid Chemistry
The Grignard Synthesis of 3-methyl-3-heptanol In this experiment‚ an example of an organometallic compound which has a carbon magnesium bond will be utilized to form a tertiary alcohol. Grignard reagents have been extremely useful in the synthesis of a large number of classes of organic functional groups. Although Grignard reagents are unstable and decompose in air and moisture‚ they can be prepared and used immediately with moderate difficulty in the undergraduate organic chemistry laboratory
Premium Functional group Chemistry Oxygen
December 19th‚ 2012 Ms. Kathleen Sylva Head Researcher Ceramic Artisans Dear Ms. Sylva‚ In ionic and covalent bonds‚ there are many properties that make up each bond. Ionic bonds between a metal and a nonmetal are stronger than covalent bonds‚ have high melting and boiling points‚ and can conduct electricity in water. This is because the electrons are transferred‚ completing the valence electron shell and making the atom stable. Covalent bonds between nonmetals have weaker bonds‚ low melting
Premium Sodium chloride Water Ionic bond
What is the Ideal Gas Law in formula form? What is the value for the proportionality constant with units? Why are those units so important? b. PV = nRT c. C = PV / T 6. Write the balanced equations for CaCO3‚ BaCO3‚ Li2CO3‚ and Na2CO3 reactions with hydrochloric acid. 7. Calculate the molar mass of these same four metallic
Premium Gas Pressure Ideal gas law
Epoxidation Reactions Lab Report 2 Abstract An oxygen atom is transferred from a peroxy acid to the carbon=carbon double bond thus forming an epoxide. Scheme 1. Oxone Epoxidation. Scheme 2. mCPBA Epoxidation. The percent yield for the Oxone epoxidation reaction was 65% yield and the mCPBA epoxidation reaction was 70% yield. Oxone is the greener alternative because using mCPBA is twice as expensive as Oxone and leaves behind the epoxide plus m-chlorobenzoic acid while Oxone creates non-toxic
Premium Chemistry Nuclear magnetic resonance
Sr(NO3)2 b. Na2CO3 g. CuSO4 c. BaCl2 h. CuCl2 d. Al(OH)3 g. PbS e. Zn(CH3COO)2 6. Complete the following double replacement (exchange ) reactions. Be sure to balance them. a. MgCl2 + Ba(NO3)2 → b. Al2(CrO4)3 + (NH4)2SO4 → c. K2SO4 + SrCl2 → d. FeCl3 + KOH → e. HCl + AgNO3 → f. K2SO4 + Ba(NO3)2 → 7. (Brown 4.21) Will precipitation occur when the following solutions are mixed? If so‚ write a balanced chemical equation for the reaction. a. Na2CO3 and AgNO3
Premium Hydrochloric acid Acetic acid Sulfuric acid
Printed Ckt Board Types of PCB (I) Single Side (II) Double Side (III) Multi Layer (V) Flexible PCB * Single Side ( 1 layer ) :- The insulating substrate contains ckt pattern on only one side. Which is called as solder side. The other side is called component side. * Double Side (2 layer) :- Double side means the ckt pattern is present on the either side of the insulating material ckt pattern both on component side & solder side. * Flexible Cards :- Flexible
Premium Printed circuit board Ammonia Copper