accurately weighed due to some CaCO3 reside being left on the sides of the beaker. Na2CO3 + CaCl22H2O = CaCO3 + 2NaCl + 2H2O Convert 1g of CaCl22H2O to moles‚ 1g CaCl22H2O x 1mol = .00689Moles CaCl22H2O 144.9994 Consider the mole ratio of Na2CO3 to CaCl22H2O 1:1 Thus‚ 1 mole of CaCl22H2O will equal 1 mole of Na2CO3 Convert moles of Na2CO3 to grams: .00689moles Na2CO3 x 105.99 = .73027g Na2CO3 1 mole Na2CO3 How much CaCO3 can we expect? .00689 moles of CaCl22H2O x 1mole CaCO3 = .00689Moles
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stoichiometry was used to determine how much Na2CO3 was needed for a full reaction: First‚ 1 g of CaCl22H2O was converted to moles: 0.00680 moles. The mole ratios of CaCl22H2O and Na2CO3 was seen to be 1:1. Then‚ moles of Na2CO3 were converted to grams: 0 .72 g. The measure of CaCo3 was predicted to be 0.00680 moles. 0.00680 moles converted to grams is 0.68 grams. Then‚ 0 .72 grams of Na2CO3 was measured into a paper cup because that was the measure calculated for Na2CO3 using stoichiometry in the step before
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solution was swirled‚ it became orange again. At the end point‚ the solution turned from orange to pink. Calculations 2HCl + Na2CO3 -> 2NaCl + CO2 + H2O Therefore‚ mole ratio of Hydrochloric Acid to Sodium Carbonate is 2:1 Percentage uncertainty of volume of HCl = 0.10/14.63 * 100 = 0.68% Percentage uncertainty of volume of Na2CO3 = 0.06/25 * 100 =0.24% Number of moles of sodium carbonate
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Edexcel Level 3 BTEC Nationals in Applied Science (Forensic Science) Unit 01 – Fundamentals of Science Assignment 01-01‚ Volumetric Analysis Date set: Sept 2010 Date due: Oct 2010 This assignment addresses the following Criteria… Unit 1 – Fundamentals of Science Assessment and grading criteria To achieve a pass grade the evidence must show that the learner is able to: To achieve a merit grade the evidence must show that‚ in addition to the pass criteria‚ the learner is able to: To
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is titrated with an HCl titrant‚ standardized by 1o Na2CO3. The indicators used are phenolphthalein for basicity and methyl orange for acidity. The two volumes of the titrant are then used to calculate percent composition of soda ash analyte. Statistical parameters such as relative standard deviation and confidence limits are also calculated. At the end of the experiment‚ the calculate percent /calculated average percent by mass of Na2CO3 is 27.6% with a relative standard deviation of 64.1 ppt
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ratio NaCl : Na2CO3 = 2 : 1 (1) mass ratio NaCl : Na2CO3 = 117 : 106 = 1 : 106/117 (1) 546 kg NaCl produces 546 × 106/117 (1) = 495 kg Na2CO3 (unit required) (1) or moles NaCl = 546000/58.5 = 9333 (if 9.33‚ allow 3 max) (1) moles NaHCO3 = moles NaCl = 9333 (1) moles Na2CO3 = ½ moles NaHCO3 = ½ × 9333 = 4667 (1) mass Na2CO3 = 4667 × 106 = 495 kg (unit required) (1) or mass ratio NaCl: NaHCO3 = 58.5 : 84 (1) mass NaHCO3 = 546 × 84/58.5 = 784 kg (1) mass ratio NaHCO3 : Na2CO3 = 168 : 106
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Then carefully and slowly add 5.30g of Na2Co3 into the volumetric flask until it reaches the exact measurement. After removing the volumetric flask off the scale‚ Slowly add diluted water into the volumetric flask until it reaches exactly 100 millimeters. Cover/seal the top opening of the volumetric
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amount of Na2CO3 I needed for it to completely react with the CaCl2 +2H2O using stoichiometry. 1.0g CaCl2+2H2O= 1mol CaCl2+2H2O =0.006802mol CaCl2+ 2H2O 147.0156g CaCl2+2H2O g of Na2CO3 = 105.98844g Na2CO3 0.006802 mol CaCl2+2H2O = 0.7209g Na2CO3 1 mol Na2CO3 X So I needed 0.72g of Na2CO3 to completely react with 1.0g CaCl2+ 2H2O. Since the scale I used only measures to 1 decimal point I used 0.7g instead of 0.72g of Na2CO3. After
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Lab chemisty 03/27/2011 Five unlabeled bottles Set 1: A) colorless B) colorless C) blue D) blue E) colorless A: Ba(NO3)2 B: AgNO3 C: CuSO4 D) CuCl2 E) KCl Description how to identify solution: _ We have two blue solution which are CuSO4 and CuCl2 or C and D‚ according to chemical reaction experiment‚ C didn’t have any reaction with other solution like B and D beside A‚ so if we look at the solubility
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chemical (primary standard) for the preparation of a standard solution. Standard Solutions are critical in chemistry because you need to have solutions with an EXACT known concentration and volume. Chemicals/Materials: solid sodium carbonate (Na2CO3) distilled water Apparatus: 250cm3 volumetric flask 250cm3 beaker Glass stirring rod Weighting boat or aluminium foil Dropping pipette Electronic scales to 2 DP Health and safety: Sodium carbonate powder may irritate the lungs if
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