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    Chapter 11 Notes

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    constant. a. What is a mole? mole (mol): the SI unit used to measure the amount of a substance‚ number of representative particles. representative particle: any kind of particle such as atoms‚ molecules‚ formula units‚ electrons‚ or ions. Avogadro’s number: 6.022 136 7 x 10²³‚ volume of one mole of a gas determined by Amedeo Avagadro in 1811. B. Converting Moles to Particles and Partciles to Moles number of moles x 6.02 x 10²³ representative particles /1 mole = number of representative

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    element to the equivalent number of moles of that element. To find the simplest formula of a compound‚ we will combine the elements in the compound under conditions that allow us to determine the mass of each element. From these data‚ the moles of atoms of each element may be calculated. By dividing the numbers to the smallest number of moles‚ you obtain quotients that are in a simple ratio of integers or are readily converted to such a ratio. The ratio of moles of atoms of the elements in a compound

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    pointless waste of time

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    Topic 1.2 AMOUNT OF SUBSTANCE The mole Reacting masses and atom economy Solutions and titrations The ideal gas equation Empirical and molecular formulae Ionic equations Mill Hill County High School THE MOLE Since atoms are so small‚ any sensible laboratory quantity of substance must contain a huge number of atoms: 1 litre of water contains 3.3 x 1025 molecules. 1 gram of magnesium contains 2.5 x 1022 atoms. 100 cm3 of oxygen contains 2.5 x

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    solvent kg of solvent = 10 mL x 1 g/mL x 1kg/1000g = 0.01 kg molality = moles of solute / kg solvent moles of solute = molality x kg solvent Isopropyl alcohol trial 1 moles of solute = 5.91 m x 0.01 kg = 0.0591 moles Isopropyl alcohol trial 2 moles of solute = 5.38 m x 0.01 kg = 0.0538 moles Ethyl alcohol trial 1 moles of solute = 4.30 m x 0.01 kg = 0.0430 moles Ethyl alcohol trial 2 moles of solute = 3.76 m x 0.01 kg = 0.0376

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    an egg that is missing its nucleus is fertilized and that may or may not contain fetal tissue. It is characterized by the presence of a hydatidiform mole (or hydatid mole‚ mola hydatidosa).[3] Molar pregnancies are categorized into partial and complete moles. Mole as used here simply indicates clump of growing tissue‚ or a ’growth’. A complete mole is caused by a single (90%) or two (10%) sperm combining with an egg which has lost its DNA (the sperm then reduplicates forming a "complete" 46 chromosome

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    of moles of toluene = Mass/Mr = 43.35g/(92.15g/mol) = 0.470428648 moles ≈ 0.470 moles Volume of Sulphuric acid = 10mL (10cm3) Density of Sulphuric acid = 1.84g/cm3 Mass of Sulphuric acid = Density x Volume = 1.84g/cm3 x 10cm3 = 18.4g Mr of Sulphuric acid = 98.09g/mol No. of moles of Sulphuric acid = Mass/Mr = 18.4g/(98.09g/mol) = 0.187582832 moles ≈ 0.188 moles Limiting reagent: Sulphuric acid No. of moles of p-Toluenesulphonic acid = 0.188 moles Mr of p-Toluenesulphonic

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    contains equal numbers of Na‚ O‚ and H atoms. Since this is the case‚ the atom ratio Na:O:H is 1:1:1‚ and so the simplest formula is NaOH. In terms of moles‚ we have one mole of Na‚ 23 grams‚ one mole of O‚ 16 grams‚ and one more of H‚ 1 gram. From this kind of argument we can conclude that the atom ratio in a compound is equal to the mole ratio. We get the mole ratio from chemical analysis‚ and from that the formula of the compound. In this experiment‚ we will use these principles to find the formula

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    38 grams | Mass of hydrated MgSO4 | 3.00 grams | Mass of crucible‚ lid‚ and anhydrous MgS04 | 12.82 grams | Mass of anhydrous MgSO4 | 1.45 grams | Mass of water in hydrated MgSO4 | 1.55 grams | Moles of anhydrous MgSO4 | 0.0120 moles | Moles of water in hydrated MgSO4 | 0.0860 moles | Observation of anhydrous MgSO4 | Different shade of white‚ more thicker and solid; powder-like | 3. To obtain the mass of water‚ first measure the mass of the crucible with the lid and anhydrous MgSO4

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    is known as reaction stoichiometry. In the example above‚ reaction stoichiometry describes the 1:3:2 ratio of molecules of nitrogen‚ hydrogen‚ and ammonia. Stoichiometry can be used to determine quantities such as the amount of products (in mass‚ moles‚ volume‚ etc.) that can be produced with given reactants and percent yield (the percentage of the given reactant that is made into the product). Stoichiometry calculations can predict how elements and components diluted in a standard solution react

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    Theme in Battle Royal

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    arranged and he is told to participate. The main character wasn’t the only one there‚ 9 other African American participated in this match as well. During the event important men from the community there were drinking and smoking cigars. In the scene a naked beautiful white woman appears and begins to dance in front of the 10 fighters the main characters feels confuse about how he should react to the scene “My teeth chattered‚ my skin turned to goose flesh‚ knees knocked. Yet I was strongly attracted and

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