aromatic polyamide membranes for FO and PRO. In the 1970s‚ Votta et al. [38] and Anderson [36] used several commercially Available RO membranes and an in-house cellulose acetate membrane to treat dilute wastewater by FO using a simulated seawater draw solution. Goosens and Van-Haute [39] used cellulose acetate membranes reinforced with mineral fillers to evaluate whether membrane performance under RO conditions can be predicted through FO testing.
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sucrose solutions of different concentrations and measuring the changes in mass of the apple cores. The changes in mass reflect the movement of water into or out of the tissue. After determining the concentration of sucrose solution at which there is no net gain or loss of water from the apple tissue‚ the osmotic potential can be calculated. This will then tell the water potential of the apple cells. Research Question and Hypothesis: How will changing the concentration of sucrose in solutions impact
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The Solubility of Potassium Nitrate Aim: The aim of this experiment is to find out by how much the solubility of potassium nitrate into distilled water increases when the solution is heated‚ and if yes‚ by how much. Hypothesis: According to data on the internet‚ 3.75 × 10¹ moles of potassium nitrate dissolve in 100g of water. I believe this information may be correct. I also believe that as the solute is absorbing outside heat‚ the energy is increased causing it to dissolve both faster‚ with
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Equipment: Refer to Biology 12 Lab Manual – Investigation 13 Procedure: Refer to Biology 12 Lab Manual – Investigation 13 Data and Observations: The Potatoes change in mass after the process of Osmosis Test Tube # | Concentration of Sucrose Solution (mol/L) | Initial mass (g) | Final mass (g) | Change in mass (g) | Percentage change in mass (%) | 1 | 1.0 | 5.12 | 3.63 | -1.49 | 29.0% | 2 | 0.9 |
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increase in temperature decreases solubility. Generally‚ an increase in temperature decreases solubility. Solids in liquid solution increases solubility. But for solubility of gas in liquids‚ an increase in temperature decreased solubility because gas evaporates as temperature increases. 2. Effect of Pressure Pressure unlike temperature has little effect on solutions unless the solute is a gas. An increase in pressure causes greater interaction between particles of the gas and the liquid
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answered: c. It is a type of diffusion. 2. Which of the following occurs when a hypertonic solution is added to cells? You correctly answered: d. The cells shrink. 3. The variable that affects osmotic pressure is You correctly answered: a. the concentration of nondiffusing solutes. 4. The net movement of water would be into the cell in a Your answer : d. hypnotonic solution. Correct answer: b. hypotonic solution. 01/20/14 page 1 Experiment Results Predict Question: Predict Question 1:
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Simple Diffusion Activity 1: Simulating Simple diffusion 1.What is the molecular weight of Na+? 22.9 2. What is the molecular weight of Cl-? 35.45 3. Which MWCO dialysis membranes allowed both of these ions through? 50‚ 100‚ and 200 4. Which materials diffused from the left beaker to the right beaker? Urea‚ NaCl and glucose diffused 5. Which did not? Why? Albumin‚ because the molecular weight exceeded the highest MWCO membrane‚ thus being to large to pass through
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election. The voters are too evenly divided on the issue‚ and he would lose a substantial number of votes no matter what stand he took. Yet with pressure increasing from both sides‚ he has to do something. After much distress he thinks is an ideal solution to his dilemma. He has appointed a committee to study the problem and make some recommendations. To make sure that the committee’s work will not be completed before the election comes up it was important to pick the right people. Specifically‚ Sam
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September 17th at the beginning of class. Show your work. 1. Match the differential equation in (a)-(c) to a family of solutions in (d)-(f). The point of this exercise is not to solve the differential equations in a) - c). (a) y = y 2 (b) y = 1 + y 2 (c) yy = 3x (d) y = tan(x + C) (e) 3x2 − y 2 = C (f) y = −1/(x + C) 2. Find the value of k so that y = e3t + ke2t is a solution of y − 2y − 3y = 3e2t . 3. Solve the following differential equations and IVP’s. You may solve these equations implicitly
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consumption of CO2. All the oxygen within the leaf disks will be removed before being placed into either of the solutions. III. Question & Hypothesis 1. What solution will allow the leaf disks to undergo Photosynthesis first? 2. If the cup with bicarbonate solution allows the leaf disk to produce oxygen by the process of photosynthesis then the leaf disk in the bicarbonate solution will be the first to float within the 15 minutes allowed. IV. Methods‚ Constants‚ Controls‚ & Trials
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