osmosis rate on different surface areas‚ depending on different types of water solution An investigation showing the effect of surface area on osmosis rate‚ including some different types of water concentration. Osmosis is a type of passive (not requiring energy) transport of water molecules across partially permeable membrane‚ from an area of high water concentration into area of low water concentration. But how does surface area affect rate of osmosis? Surface area plays important role
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energetic eruption‚ affirming the nucleation-site theory. The surface of the mint Mentos is covered with many small holes that increase the surface area available for reaction (and thus the quantity of reagents exposed to each other at any given time)‚ thereby allowing CO2 bubbles to form with the rapidity and quantity necessary for the "jet"- or "geyser"-like nature of the effusion. Each Mentos candy has thousands of small pores on its surface which disrupt the polar attractions between water molecules
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permeable barrier whose total surface area is important in regulating the substances that diffuse into or out of the cell. However‚ as a cell grows in size‚ its volume increases at a greater rate than its surface area. Consequently‚ the surface area of the growing cell soon becomes inefficient for effective diffusion throughout the cell. This relationship between surface area and the volume of a cell can be expressed as a ratio; and the need for an effectively large surface area to volume ratio is considered
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Exploring Enzymes - Ground-Up Tissue Activity Abstract Our experiment looked at how increasing the surface area of a substance affects the amount of bubbles created due to the presence of the enzyme catalase. The experiment used two pieces of fish‚ one whole and one ground up‚ which were then covered in hydrogen peroxide. This method allowed us to observe the catalase in ground up fish break down the hydrogen peroxide at a quicker rate than in the piece of fish left intact. This was determined
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Group: _______________________________________ 1) Five equilateral triangles‚ each with side length are arranged so they are all on the same side of a line containing one side of each. Along this line‚ the midpoint of the base of one triangle is the vertex of the next‚ as shown in the diagram below. What is the area of the region that is covered by the union of the five equilateral triangular regions? Answer: Question Attempt 1 Attempt 2 Attempt 3 1 Triangles
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Effects of Agriculture on the Environment Introduction: Agriculture has changed dramatically‚ especially since the end of World War II. Food and fibre productivity rose due to new technologies‚ mechanization‚ increased chemical use‚ specialization and government policies that favoured maximizing production. These changes allowed fewer farmers with reduced labour demands to produce the majority of the food and fibre. Humans‚ like all other species‚ exploit their surroundings for the resources they
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Business Challenge #6: To develop the best scratch resistant coating in the world for ophthalmic lenses [Titan] Background The ophthalmic lenses (spectacle lenses) consist of some base material (substrate) like CR 39‚ Polycarbonate‚ Trivex and a surface treatment is given to them to increase their hardness. Currently‚ there are 2 processes of applying this coating‚ i.e. Dip coating and Spin coating. The current scratch resistant (Hard) coating on plastic and polycarbonate lenses available in the
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effect of the surface area to volume ratio on the rate evaporation of water in different sized containers. By measuring the time it takes for the whole amount of water to evaporate‚ a conclusion can be made about the validity of the surface to volume ratio in regards to the biological process of diffusion. Research Question: What is the effect of the surface area to volume ratio on the evaporation of water? Variables: - Independent: o Surface area in cm2 of the top most surface of water in the
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at least have to pick r and h such that pi r^2 h = 355. That means h = 355 / (pi r^2). The surface area of a cylinder is the top (pi r^2) plus the bottom (also pi r^2) times the lateral side (2 pi r h). So the total surface area is 2 pi r^2 + 2 pi r^2 + 2pi r h‚ or 4 pi r^2 + 2 pi r h. Substitute h = 355 / (pi r^2) into this to get the surface area in terms of just r. Now that you have the surface area in terms of just r‚ you can find the value of r that minimizes this by taking the derivative
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| | | | | | | | | The Erosion Process1. Water. Erosion from water typically occurs in the following ways. a. Raindrop Splash and Sheet Erosion. The first step in the erosion process begins as raindrops impact the soil surface. Raindrops typically fall with a velocity of 20-30 feet per second. The energy of these impacts are sufficient to displace soil particles as high as two feet vertically. In addition‚ the impact of a rainfall on a bare soil can compact the upper layer of
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