handle unpredictable conditions‚ approaches to challenging task and communication style when collaboration with colleagues are obligatory‚ thus are similar key components in the medical and teaching profession. However‚ according to the article‚ “The Bell Curve” by Atul Gawande‚ accountability for the results‚ which considered “average work”‚ does not hold prominence as do in the teaching profession. Like the attributes of Dr. Warren Warwick‚ director of Fairview University Children’s Hospital‚ an exemplary
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STA1101 Normal Distribution and Continuous random variables CONTINUOUS RANDOM VARIABLES A random variable whose values are not countable is called a _CONTINUOUS RANDOM VARIABLE._ THE NORMAL DISTRIBUTION The _NORMAL PROBABILITY DISTRIBUTION_ is given by a bell-shaped(symmetric) curve. THE STANDARD NORMAL DISTRIBUTION The normal distribution with and is called the _STANDARD NORMAL DISTRIBUTION._ Example 1: Find the area under the standard normal curve between z = 0 and z = 1.95 from z
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April 2013. SPECIAL DISTRIBUTIONS I. Concept of probability (3%) 1. Explain why the distribution B(n‚p) can be approximated by Poisson distribution with parameter if n tends to infinity‚ p 0‚ and = np can be considered constant. 2. Show that – and + are the turning points in the graph of the p.d.f. of normal distribution with mean and standard deviation . 3. What is the relationship between exponential distribution and Poisson distribution? II. Computation
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real numbers t with the following properties: (1) (2) (3) (4) W0 = 0. With probability 1‚ the function t → Wt is continuous in t. The process {Wt }t≥0 has stationary‚ independent increments. The increment Wt+s − Ws has the N ORMAL(0‚ t) distribution. A Wiener process with initial value W0 = x is gotten by adding x to a standard Wiener process. As is customary in the land of Markov processes‚ the initial value x is indicated (when appropriate) by putting a superscript x on the probability
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Study Set for Midterm II‚ Chapters 7 & 8 ESSAY. Write your answer in the space provided or on a separate sheet of paper. 1) The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0. Suppose 36 golfers played the course today. Find the probability that the average score of the 36 golfers exceeded 71. 2) At a computer manufacturing company‚ the actual size of computer chips is normally distributed with a mean of 1 centimeter
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with an example 2 2 10 6 a) Describe the characteristics of Normal probability distribution. b) In a sample of 120 workers in a factory‚ the mean and standard deviation of wages were Rs. 11.35 and Rs.3.03 respectively. Find the percentage of workers getting wages between Rs.9 and Rs.17 in the whole factory assuming that the wages are normally distributed. Characteristics of Normal probability distribution Formula/Computation/Solution to the problem 3 4 10 6 a) The
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> data=read.table("d:/111113/1.txt"‚header=T) > model1=lm(S~u_direction+mx+my+mz‚data) > summary(model1) Call: lm(formula = S ~ u_direction + mx + my + mz‚ data = data) Residuals: Min 1Q Median 3Q Max -11.8430 -0.3962 0.3252 0.7887 18.3963 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) -0.50372 0.12738 -3.955 7.93e-05 *** u_direction -0.40368 0.07996 -5.048 4.85e-07 *** mx -0.40573 0
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side of the centerline When the process is in statistical control‚ find the false alarm probability (Type-I error) for each case. The corresponding probability measures are obtained from the Normal table as P(3 " Z) = 0.00135 P(2 " Z) = 0.02275 P(1 " Z) = 0.1587 Solution: ! i) Use the Binomial distribution to ! calculate the probability measures. ! 3! 3! P(Y ! 2 n = 3‚ p = 0.02275) = (0.02275)2 (1" 0.02275) + (0.02275)3 = 0.00153 2!1! 3!0! Type-1 Risk considering both sides: ! = 0.00306
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Variances Variances can be either: * Positive/favourable (better than expected) or * Adverse/unfavourable ( worse than expected) A favourable variance might mean that: * Costs were lower than expected in the budget‚ or * Revenue/profits were higher than expected By contrast‚ an adverse variance might arise because: * Costs were higher than expected * Revenue/profits were lower than expected What causes budget variance? There are four key reasons and it is important that
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Analysis for Managerial Applications Assignment No. : MS-08/TMA/SEM-I/2014 Coverage : All Blocks Note : Attempt all the questions and submit this assignment on or before 30th April‚ 2014 to the coordinator of your study center. 1. The distribution of Intelligence Quotient (I.Q.) scores measured for 100 students in a test is as follows: I.Q.* 40-50 50-60 60-70 70-80 80-90 90-100 Number of Students 10 20 20 15
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