receives every month. For example‚ I get 60‚000 won a month but there are students that get less than I do. Normally‚ when you’re on a date‚ the guys tend to spend more money. A normal date course would be a movie and eating dinner. A movie for two would be 14‚000 won‚ and dinner would cost about 20‚000 for two. A normal date would cost more than 30‚000 won. That is half my allowance. Some may say that the money is worth the use‚ but I say “are you going to be with that guy/girl forever?” If not
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TPCP Operation & Indication Clarification of Issues Found During ILTIS SAT2 & SAT3 Tests ABCDEFGH Page 1 of 6 Abbreviations Serial Number Abbreviation Full Form 1. SGEDT Seremban to Gemas Electrified Double Track Project 2. **** Keretapi Tanah Melayu Berhad (Malaysian National Railway Operator) 3. TPCP Technician’s Point Control 4. SE Sungai Gadut Station of SGEDT 5. RB Rembau Station of SGEDT 6. TA Tampin Station of SGEDT
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Michael Cullimore Math 1040 Skittles Project Part 2 Confidence Interval Estimates - Confidence Interval: A confidence interval is an indicator of a measurement’s precision. It is also an indicator of how stable an estimate is‚ which is the measure of how close a measurement will be to the original estimate if an experiment is repeated. The calculations show that we are 99% confident that the true proportion of yellow candies falls between 0.20125 and 0.21275. This is
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Supply Chain Management Application in E-Commerce Company Taking JD.com as an example MACC 5P31 Advanced Management Accounting Section 2 Instructor: Dr. Hemantha Herath Yifan ZHU 5294269 Zhulai LI 5608690 Ying GONG 5727086 Yahong HU 5718697 Due date: April 2nd‚ 2015 Abstract The target of this paper is to figure out the best way for the JD.com which is the largest B2C online shopping website in China in the area of supply chain management. The main issue is under
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Chapter 3 Standard units tell you how many standard deviations above or below average a data value is standard units = (actual value – average)/SD actual value = average + (SD x standard units). Standard units are denoted by Z. Chapter 8 Complement rule: P(A) = 1 – P(A doesn ’t happen) Multiplication rule: P(A and B both happen) = P(A) x P(B given A happened) Q. 5 random components removed one at a time from box containing 5 defective and twenty working. What is chance of selecting all defective:
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Sampling distribution The sampling distribution is the distribution of the values of a sample statistic computed for each possible sample that could be drawn from the target population under a specified sampling plan. Because many different samples could be drawn from a population of elements‚ the sample statistics derived from any one sample will likely not equal the population parameters. As a result‚ the sampling distribution supplies an approximation of the true value’s population parameters
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students are majoring in Finance? .0716 4. Assume that we have selected a random sample of 25 units from a normally distributed large population. If u = 15‚ and c2=4‚ what is the probability that we will obtain a sample mean of less than 14? .0062 5. The normal approximation of the binomial distribution is appropriate when. Np> 5 and n(1-p) >5 6. A newly married couple plans to have four children. Suppose that boys and girls are equal likely each time a child is born. What is the probability the couple will
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a bell-shaped graph known as a bell curve. It occurs when data is plotted on the graph based on normal measured traits. A normal distribution is symmetrical on both sides of the mean while a negative distribution has fewer scores on the left side of the mean than the right side. It is the opposite for a positive skew. The value for the mean‚ median and mode is the same for a normal distribution. 34% of the population has a score that is 85 to 100. 34% of the population has a score
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Returns 1 RETURNS Prices and returns Let Pt be the price of an asset at time t. Assuming no dividends the net return is Pt Pt − Pt−1 −1= Rt = Pt−1 Pt−1 The simple gross return is Pt = 1 + Rt Pt−1 Returns 2 Example: If Pt−1 = 2 and Pt = 2.1 then 2.1 Pt 1 + Rt = = = 1.05 and Rt = 0.05 Pt−1 2 Returns 3 The gross return over k periods (t − k to t) is 1 + Rt (k) := Pt−1 Pt−k+1 Pt Pt ··· = Pt−k Pt−1 Pt−2 Pt−k = (1 + Rt ) · · · (1 + Rt−k+1 ) Returns are • scale-free‚ meaning that they do not depend
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a. Is it reasonable that the distribution of checking account balances approximates a normal distribution? Yes. Its reasonable because the sample size is large and and n -( increases the distribution of checking account balances approximates normal distribution. b. Determine the mean and the standard deviation for the sample of 60 customers. |Mean = |1516.667 | |Variance= |2637500 | |Std dev= |1624.038 | c. Compare the actual distribution
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