Case 3: Jackpine Mall Jane Rodney‚ President of the Rodney development company‚ is creating a shopping centre at Jackpine Mall. She had already decided on a few stores to include within the shopping centre but could not decide on the next few. With our knowledge of decision modeling‚ we can achieve the most feasible solution for Jane. We based the decision of allocating the remaining few stores through our Present Value function: MAX = 28.1CM + 34.6CW + 50.0CV + 162.0RF + 77.8RL + 100.4RC
Premium Trigraph Optimization Shopping mall
Assignment #3: Case Problem "Julia’s Food Booth" Page 1 Case Problem "Julia’s Food Booth" Jenna Kiragis Strayer University 8/24/2012 Assignment #3: Case Problem "Julia’s Food Booth" Page 2 A) Formulate and solve an L.P. model: Variables: x1 – Pizza Slices x2 – Hot Dogs x3 – Barbeque Sandwiches Subject to: $0.75x1 + $0.45x2 + $0.90x3 ? $1‚500 24x1 + 16x2 + 25x3 ? 55‚296
Premium English-language films Rain American films
BUS 306 Fall 2012 H. Saber Names: Assignment #2 (Due October 7‚ 2012) A. 1. Review chapter3 from the textbook and do all the cases in the chapter independently. 2. Go through all the Solved Problems on chapters 2 and 3 in the textbook CD independently. B. C. 1. Provide complete solutions to problems 3.21‚ 3.25‚ 3.30‚ 3.34 from the textbook on pages 104 – 107 Submit the solution to the following questions. 1. Consider the following LP: Maximize Z = 3X1 + 2X2 Subject to: 2X1 + 4 X2 -X1
Premium Optimization
A) P: the #of pizza slices H: # of hot dogs B : # of barbeque sandwiches Total revenue Total cost Profit Pizza slice 1.50 6/8 slices = $0.75 0.75 Hot dog 1.50 0.45 1.05 Barbeque sandwich 2.25 0
Premium Optimization Hamburger Profit maximization
As per the information given‚ profits per acre on various crops are as follows: Profit per acre on wheat = 50 x 2 = $100 Profit per acre on Alfalfa = 1.5 x 40 = $60 Profit per acre on Barley = 2.2 x 40 = $88. Suppose Young’s production plan for the next year is as follows: Parcel Cultivation Area (Acre) Land Available Wheat Alfalfa Barley Southeast 2000 North 2300 Northwest 600 West 1100 Southwest 500 Total 6500 Total profit as per the production plan: The objective function
Premium Optimization Agriculture Maxima and minima
Linear Programming History of linear programming goes back as far as 1940s. Main motivation for the need of linear programming goes back to the war time when they needed ways to solve many complex planning problems. The simplex method which is used to solve linear programming was developed by George B. Dantzig‚ in 1947. Dantzig‚ was one in who did a lot of work on linear programming‚ he was reconzied by several honours. Dantzig’s discovery was through his personal contribution‚ during WWII when Dantzig
Premium Optimization Linear programming Algorithm
Resource Allocation Problem Statement The type of problem most often identified with the application of linear program is the problem of distributing scarce resources among alternative activities. The Product Mix problem is a special case. In this example‚ we consider a manufacturing facility that produces five different products using four machines. The scarce resources are the times available on the machines and the alternative activities are the individual production volumes. The machine
Free Linear programming Operations research Optimization
Algorithm to Calculate Basic Feasible Solution using Simplex Method Abstract: The problem of maximization/minimization deals with choosing the ideal set of values of variables in order to find the extrema of an equation subject to constraints. The simplex method is one of the fundamental methods of calculating the Basic Feasible Solution (BFS) of a maximization/minimization. This algorithm implements the simplex method to allow for quick calculation of the BFS to maximize profit or minimize loss
Premium Optimization Algorithm Mathematics
Case Problem 3: Hart Venture Capital 1. Let S = fraction of the Security Systems project funded by HVC M = fraction of the Market Analysis project funded by HVC Max 1‚800‚000S + 1‚600‚000M s.t. 600‚000S + 500‚000M ≤ 800‚000 Year 1 600‚000S + 350‚000M ≤ 700‚000 Year 2 250‚000S + 400‚000M ≤ 500‚000 Year 3 S
Premium Optimization Security Linear programming
LOGISTICS Example how to use software transformation mode>new: 1.sources: number of source 2.destination:number of destination 3.activities minimize/maximize >click ok> supply‚ demand‚ time ________________________________________________________________________________________ logistics is a part of supply chain management‚ cooperation of different elements of different ownerships supply chain units do not compete with each other‚ but work as one body order cycle time-time
Premium Marginal cost Real number Vertical integration