by : Directorate of Education‚ Delhi SOME IMPORTANT REASONING BASED QUESTIONS OF ORGANIC CHEMISTRY 1. Chlorobenzene is less reactive than chloromethane. Ans. In chlorobenzene‚ each carbon atom of benzenering is sp2 hyridised and is electron withdrawing. Chlorine atom donates a lone pair of electron and acquire positive charge. The negative charge is delocalised on ortho and para position by resonance. C-Cl bond acquires partial double bond character and is 169 pm as compared to 17.0 pm in chloromethane
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Organic Chemistry II Laboratory (ABCT357) Although studying fundamental theories of chemistry in the class is important to understand the concept of chemistry‚ carrying out experiments to corroborate the theories is also important. It is very important for students to get used to experiments in order to speed up their experiments. Expt.1. Acetylation of α-D-glucopyranose Add slowly 2.5 g (0.014 mol) of powdered D-glucose in small portions (roughly in 7-10 portions and 5 min for each addition)
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Access the virtual lab and complete the experiments. Part One (Flame Test): 1. Create and complete a data table for Part One of the lab. It should include the name of the element (or unknown) examined and the color of the observed flame: Barium-green Calcium-red Sodium-yellow Rubidium-purple Potassium-blue Lithium-pink 2. Identify each unknown from Part One of the lab and briefly explain why you identified each unknown as you did.: Unknown 1-yellow. I think it is Sodium because their flames
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Name__________________________ Chemistry 190: Organic Chemistry EXAM 3 Thursday April 21‚ 2011 1. (12) ______ 2. (14) ______ 3. (20) ______ 4. (12) ______ 5. (54) ______ 6. (16) ______ 7. (12) ______ 8. (10) ______ Total (150) ______ The exam consists of twelve numbered pages and an unnumbered cover sheet. Make certain that you have a complete exam. You will have two hours to work on the exam. No books or notes are allowed; however‚ you may use a molecular model set and a calculator
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Objective: Recognize and distinguish between chemical and physical changes. Materials: - lab balance - microspatula - lab burner - dropper pipet - 5 test tubes - mortar and pestle - test tube rack - magnet - test tube holder - insulating pad - watch glass - safety goggles - glass square - lab apron or coat - copper sulfate pentahydrate - iron fillings - sodium chloride - magnesium ribbon - hydrochloric acid - paper (5 cm x 10 cm) - silver nitarate
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He a lt h 0 3 2 3 Fire 0 Re a c t iv it y 2 P e rs o n a l P ro t e c t io n Material Safety Data Sheet Sulfuric acid MSDS Section 1: Chemical Product and Company Identification Product Name: Sulfuric acid Contact Information: Catalog Codes: SLS2539‚ SLS1741‚ SLS3166‚ SLS2371‚ SLS3793 CAS#: 7664-93-9 Sciencelab.com‚ Inc. 14025 Smith Rd. Houston‚ Texas 77396 RTECS: WS5600000 US Sales: 1-800-901-7247 International Sales: 1-281-441-4400 TSCA: TSCA
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rocks that I like to collect. As I went through high school‚ I settle and wanted to be a doctor due to my strong duty in helping people and my interest in human anatomy and chemistry. But‚ like most pre-med students
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Nitration of Methyl Benzoate to form Methyl-m-nitrobenzoate via Aromatic Substitution Linh Ngoc Thuy Nguyen Seattle Central Community College Professor: Dr. Esmaeel Naeemi Date: February 21st‚ 2012 Abstract In this experiment‚ methyl-m-nitrobenzoate‚ followed the electrophilic addition of aromatic ring‚ would be formed from the starting material methyl benzoate and nitric acid‚ under the catalysis of concentrated sulfuric acid. The reaction between nitric acid and sulfuric acid resulted
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Introduction The purpose of this experiment is to synthesize methyl nitrobenzoate from methyl benzoate‚ concentrated HNO3‚ and concentrated H2SO4 via an electrophilic aromatic substitution reaction. Reaction Procedures/ Observations Use a 50 ml beaker to cool about 6 ml of concentrated sulfuric acid in an ice water bath. Weigh the vial containing about 3 grams of methyl benzoate and add it to the cooled sulfuric acid. Next pour about 2 ml of sulfuric acid to the nitric acid in the vial
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Chemistry 121 Colligative Properties Lab Demonstration of Selected Calculations from Choice I Determination of Kf for Naphthalene To determine the Kf for naphthalene‚ we need to find the difference in the freezing point of pure naphthalene and the solution of 1‚4-dichlorobenzene in naphthalene. Let’s say that we did this experiment‚ used 1.00 g 1‚4-dichlorobenzene in 10.00 g naphthalene‚ and found that the freezing temperature of pure naphthalene was 78.2°C‚ while that of the solution was 75
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