disproportionation reaction). The solution remains strongly basic. The chemical equation for the process is: Cl2(g) + 2OH- (aq) ---> ClO- (aq) + Cl- (aq) + H2O (l) The amount of hypochlorite ion present in a solution of bleach can be determined by oxidation-reduction titration. One of the best methods is the iodine-thiosulfate titration procedure. Iodide ion‚ I-‚ is easily oxidized by almost any oxidizing agent (It has many electrons to lose!). In an acid solution‚ hypochlorite ions oxidize iodide
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Redox Problem Set 1: Reactions and Stoichiometry (All of these questions are no calculator friendly) 1) Give the oxidation number of carbon in each of the following: a) b) c) d) CF2Cl2 Na2C2O4 HCO3-1 C2H6 2) Give the oxidation number of sulphur in each of the following: a) b) c) d) SOCl2 H2S2 H2SO3 Na2S 3) Identify the oxidizing and reducing agents in each of the following: a) b) c) d) 8H+(aq) + 6Cl-1(aq) + Sn(s) + 4NO3-1(aq) SnCl6 -2(aq) + 4NO2(g) + 4H2O(l) 2MnO4-1(aq) + 10Cl-1(aq) + 16H+(aq)
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p. 1 Megan Ly Chemistry 231L February 20‚ 2013 SOLUBILITY Purpose: To better comprehend solubility behavior by investigating the solubility of various substances in different solvents‚ looking at miscible and immiscible pairs of liquids‚ and observing the solubility of organic acids and bases. Reference:
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chemistry lab report : reaction of alcohol CHEMISTRY LAB REPORT SK026 SEMESTER 2 SESSION 2011/2012 TITLE :REACTION OF ALCOHOL DATE : NAME : MATRIC NO : PARTNER : PRACTICUM : SUPERVISOR : Title : Reaction Of Alcohol Objectives : 1. To classify alcohol 2. To study the chemical properties of alcohols Introduction: Alcohol is a class of organic compound containing hydroxyl group‚ OH as the
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Chemistry Final Study Guide Matter as anything that has mass and takes up space. Significant figures refers to digits that were measured. When rounding calculated numbers‚ we pay attention to significant figures so we do not overstate the accuracy of our answers. Rules: -All nonzero digits are significant. -Zeroes between two significant figures are themselves significant. -Zeroes at the beginning of a number are never significant. -Zeroes at the end of a number are significant if a decimal
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final product‚ which is called ________. 6. For further derivation of energy‚ aerobic cells must convert pyruvate into acetyl coenzyme A by stripping off a C02 molecule. This process is known as ___________. 7. All of the reactions of glucose oxidation that follow glycolysis involving the transfer of electrons to their final acceptor‚ oxygen‚ take place in eukaryotic cells in the ___________. 8. Because the chemical formation of ATP is driven by a diffusion force similar to osmosis‚ this process
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used COD as a source of organics for denitrification. In the next 2 hours of aeration‚ ammonium was oxidized faster than COD and reached 89%. This was a result of the increase in DO concentration that exceeded 6 mg/L. The increase in DO made the oxidation of NH4-N unlimited. The first-order kinetic constants were 0.34 h-1 and 0.24 h-1 (Table 6)‚ with correlation coefficients of 0.94 and
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Hazy Joy L. Dela Cruz II-Science Class OUTPUT NO. 3 I. Background of the Related Topic A. Malunggay Malunggay leaves was once considered a "poor man’s vegetables" but now it is known as a "miracle tree" or "nature’s medicine cabinet" by scientists and health care workers from around the world because it is loaded with vitamins and minerals that can be an effective remedy against many kinds of ailments. All parts of the malunggay tree are usable for nutritional and medicinal purposes
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Determining activation energy (Ea) of a reaction © KCl http://hk.geocities.com/fatherofchemistry Objective To determine the activation energy for the reduction of peroxodisulphate(VI) ions. S2O82-‚ by iodide ions I-‚ using a ’clock’ reaction. Principle The equation for reduction of S2O82- by I- is: S2O82- + 2I- → 2SO42- + I2 The formation of iodine is ’monitored’ by small & known amount of thiosulphate ions‚ S2O32-:
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n this lab‚ everyone got a flask which we then drew a pumpkin face on. Then we mixed 42 mL sodium hydroxide solution‚ 10 g of glucose‚ 1 mL‚ 1 L of water and Methylene blue solution and leave it undisturbed. The blue solution turned clear and when we added the yellow food coloring it turned an orange color. The solution then turned dark blue once the solution was shaken vigorously. This reaction occurred because the oxygen oxidized the methylene blue.In the oxidized state the methylene blue shows
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