Title: Redox Reactions Research Question: Is it possible to determine if a redox reaction took place by using only the equation? Hypothesis: Yes‚ I believe it is possible to determine if this reaction took place by using the oxidation numbers in the equation. Variables: 1. I cleaned the reaction surface to limit contamination 2. I held the chemicals at approximately a 90 degree angle for consistency Introduction: Redox reactions occur when both oxidation and reduction take place. All atoms
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solution‚ MnO4- ion undergoes reduction to Mn2+ this is the equation: 8H+(aq) + Mno4-(aq) + 5e- Mn2+(aq) + 4H2O Since the KMnO4 – ion is violet and the Mn2+ ion is nearly colorless‚ the end point titrations using KMnO4 as the titrant can be taken as the first pink color that appears in the solution (and stays without disappearing). The titration which involves the oxidation of Fe2+ ion to Fe3+ by permanganate ion‚ is carried out in sulfuric acid to prevent air-oxidation of Fe2+ (we can them determine
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INTRODUCTION For this experiment we studied an oxidation-reduction reaction of magnesium and hydrochloric acid solution. We compared the experimental measured amount of a product and the amount predicted by the theoretical calculation of a balanced equation: Mg (s) + 2HCl (aq) → MgCl2 (aq) + H2 (g) PROCEDURE First we obtained a strip of pre-cut magnesium ribbon‚ cleaned it with steel wool to remove any signs of oxidation from the strip (which would alter our results)‚ and then weighed it (individual
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Week 10: Oxidation and Reduction Reactions: The Reactions of Copper Data: Part I: Preparing a solution of copper (II) nitrate Initial mass of copper wire: .520g Mass of copper wire after vigorously scouring: .518g Observations of Copper (II) ribbon mixed with HNO3: Solution turned green. Thick brown gas formed. Copper (II) bubbled vigorously. Cu (II) dissolved‚ solution appeared green/blue. After the addition of H2O a blue crusty precipitate formed. Part II: Synthesis of solid copper
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STK 1084 Inorganic Chemistry I‚ LU 3 Oxidation – Reduction Reactions‚ Prepared By: Dr. Tay Meng Guan‚ Faculty of Resource Science and Technology‚ Universiti Malaysia Sarawak. LU 3 Oxidation and Reduction Reactions 3.1 Ideas of Oxidation and Reduction Oxidation of an atom can be occurred in the following conditions: 1. Losing an electron from the orbitals. e.g.: A A+ + e- 2. Adding an electronegative element (e.g.: F‚ Cl‚ Br‚ O) to a molecule. e.g.: A + F AF 3. Losing hydrogen
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DEFINITIONS OF OXIDATION AND REDUCTION (REDOX) This page looks at the various definitions of oxidation and reduction (redox) in terms of the transfer of oxygen‚ hydrogen and electrons. It also explains the terms oxidising agent and reducing agent. Oxidation and reduction in terms of oxygen transfer Definitions • Oxidation is gain of oxygen. • Reduction is loss of oxygen. For example‚ in the extraction of iron from its ore: [pic] Because both reduction and oxidation are going on side-by-side
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Oxidation and Reduction Mnemonic: OILRIG Oxidation Is Loss‚ Reduction Is Gain Oxidation → the loss of electrons from an atom or an ion→ always happens at anode (positive electrode) → think anOde (O2 in the electrolysis of water xp) Redox reactions: Reactions involving the transfer of electrons e.g. burning‚ rusting‚ photosynthesis‚ respiration and the browning of apples. happens in three types of reactions: 1. addition of oxygen 2. removal of hydrogen 3. increase in valency (how easily an atom
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different features that come about by using oxidation reduction and recording the observations‚ these tests will help determine the specific qualities each solution has. Hypothesis I theorize that nothing will happen with Magnesium because it is such a soft metal. Zinc should turn a greener color‚ because that’s what happens to a lot of statues and sculptures. I theorize that iron will tarnish badly because in air it can get tarnished so oxidation must do something as well. Materials 1 Paper
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8.07 Work File: Oxidation Reduction Reactions 1. What is the difference between an oxidizing agent and a reducing agent? The oxidation number (overall charge of the atom) is reduced in reduction and this is accomplished by adding electrons. The electrons‚ being negative‚ reduce the overall oxidation number of the atom receiving the electrons. Oxidation is the reverse process: the oxidation number of an atom is increased during oxidation. This is done by removing electrons. The electrons‚ being
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2 electrons NH3OH+ --> something + 2e- Oxidation number of N in NH3OH+ is -1‚ therefore the oxidation number for N on the product side must be +1 because it gains 2 electrons. N2O has an oxidation number of +1 for N‚ so that would work. Data:Equation 1: NH3OH+ + 2Fe+3 --> something + 2Fe+2 Equation 2: 8H+ + 5Fe+2 + MnO4- --> 5Fe+3 + Mn+2 + 4H2O Equation 3: 6H+ + 2MnO4- + 5H2C2O4 --> 2Mn+2 + 10CO2 + 8H2O Conclusion: Therefore the concluded reaction would be: NH3OH+ + 2Fe+3 --> N2O + 2Fe+2
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